FUND OF ENG THERMODYN(LLF)+WILEYPLUS
9th Edition
ISBN: 9781119391777
Author: MORAN
Publisher: WILEY
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Steady-state operating data are shown in the figure below for an open feedwater heater. Heat transfer from
the feedwater heater to its surroundings occurs at an average outer surface temperature of 50°C at a rate of
100 kW. Ignore the effects of motion and gravity and let To = 25°C, po = 1 bar. Determine
(a) the ratio of the incoming mass flow rates, m/ṁ2.
(b) the rate of exergy destruction, in kW.
P2 = 1 bar
Tz = 400°C
1
ṁy = 0.7 kg/s
Pi = 1 bar
T, = 40°C
Feedwater heater
X3 = 25%
P3 = 1 bar
Tp = 50°C
%3D
2)
7.25 As shown in Fig. P7.25, a 1-lb metal sphere initially at 2000°R is removed from an oven and quenched by immersing it in a closed tank
containing 25 lb of water initially at 500°R. Each substance can be modeled as incompressible. An appropriate constant specific heat for the
water is c 1.0 Btu/lb °R, and an appropriate value for the metal is cm = 0.1 Btu/lb oR. Heat transfer from the tank contents can be
neglected. Determine the exergy destruction, in Btu. Let To = 77°F.
System boundary
Metal sphere:
Tmi=2000°R
m=0.1 Btu/lb R
mm= 1 lb
Water:
Twj=500°R
=1.0 Btu/lb R
m 25 lb
FIGURE P7.25
1. The first law of thermodynamics discussesa. Thermal equilibriumb. Energy conservationc. Direction of heat flowd. Entropy is zero at absolute zero temperature
2. A tank contains 1 kg mass gas whose density is 700 kg/m3. The pressure is increased from 1 bar to 3 bar. The approximate specific boundary work of the system isa. Cannot be find since some data is missingb. 285 kJ/kgc. 0 kJ/kgd. 0.285 kJ/kg
3. The nozzle is a device in whicha. Area decreases b. Area increasesc. Velocity decreases d. Velocity increases
4. Choose the correct statement/s with respect to entropy change during a processa. Entropy increases with increase in pressure at constant temperatureb. Entropy increases with increase in temperature at constant pressurec. Entropy can be kept constant by systematically increase both pressure and temperatured. Entropy can not be changed
5. The isentropic process is also called asa. Adiabatic processb. Irreversible adiabatic processc. Reversible adiabatic processd. Reversible…
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- Steady-state operating data are shown in the figure for an open feedwater heater.Heat transfer from the feedwater heater to its surroundings occurs at an average outer surfacetemperature of 50°C at a rate of 100 kW. Ignore the effects of motion and gravity and let T 0 =25°C, p0 = 1 bar. Determine(a) the ratio of the incoming mass flow rates, ?̇# /?̇ $ .(b) the rate of exergy destruction, in kW.arrow_forwardA silicon chip measuring 5 mm on a side and 1 mm in thickness is embedded in a ceramic substrate. At steady state, the chip has an electrical power input of 0.425 W. The top surface of the chip is exposed to a coolant whose temperature is 29°C. The heat transfer coefficient for convection between the chip and the coolant is 0.18 kW/m2 K. If heat transfer by conduction between the chip and the substrate is negligible, determine the surface temperature of the chip, in °R.arrow_forwardA silicon chip measuring 5 mm on a side and I mm in thickness is embedded in a ceramic substrate. At steady state, the chip has an electrical power input of 0.425 W. The top surface of the chip is exposed to a coolant whose temperature is 29°C. The heat transfer coefficient for convection between the chip and the coolant is 0.18 kw/m2 K. If heat transfer by conduction between the chip and the substrate is negligible, determine the surface temperature of the chip, in °R. Select one: O a. 714 O b. 353 O c. 396 O d. 635arrow_forward
- Three sub steps of a thermodynamic cycle are employed in order to change the state of a gas from 1 bar, 1.5 cubic meter and internal energy of 512 kJ. The processes are: 1st step: Compression at constant PV to a pressure of 2 bar and internal energy of 690 kJ. 2nd step: A process where work transferred is zero and heat transferred is - 150 kJ. 3rd step: A process where work transferred is -50 kJ. without KE and PE changes, determine: a. heat transferred during 1st step (kJ) b. heat transferred during 3rd step (kJ)arrow_forwardP.4 (Application on the First Law of Thermodynamics with heat transfer) A silicon chip measuring 5 mm on a side and 1 mm in thickness is embedded in a ceramic substrate. At steady state, the chip has an electrical power input of 0.225 w. The top surface of the chip is exposed to a coolant whose temperature is 20°C. The rate of energy transfer by heat between the chip and the coolant is given by 9= hA (T, - T), where T, and T, are the surface and coolant temperatures, respectively, A is the surface area, and If heat transfer between the chip and the substrate is negligible, determine the surface temperature of the chip, in °C.arrow_forwardI need some help in how to solve this problem. Any help will be appreciated. Thanksarrow_forward
- A rigid tank of volume 0.5 m3 is initially evacuated. A tiny hole develops in the wall, and air from the surroundings at 1 bar, 21° C leaks in . eventually, the pressure in the tank reaches 1 bar. The process occurs slowly enough that heat transfer between the tank and the surroundings keeps the temperature of the air inside the tank constant at 21° C. Determine the amount of heat transfer. 101.325 kJ 25 kJ 40 kJ 50 kJarrow_forwardA system undergoes a refrigeration cycle while receiving Qc by heat transfer at temperature Tc and discharging energy Qu by heat transfer at a higher temperature TH. There are no other heat transfers. (a) Using energy and exergy balances, show that the net work input to the cycle cannot be zero. (b) Show that the coefficient of performance of the cycle can be expressed as: Tc TH – TeA'¯ T(Qn – Q). B = where E, is the exergy destruction and To is the temperature of the exergy reference environment. (c) Using the result of part (b), obtain an expression for the maximum theoretical value for the coefficient of performance.arrow_forwardThe following processes occur in a reversible thermodynamic cycle: 1-2: 0.2 kg heating at constant pressure 1.05 bar at specific volume 0.1 m3/kg and work done -515 J. 2-3: Isothermal compression to 4.2 bar. 3-4: Expansion according to law pv1.7= constant. 4-1: heating at constant volume back to the initial conditions. Calculate the specific work done for process 1-2 in J/kg.arrow_forward
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