FUND OF ENG THERMODYN(LLF)+WILEYPLUS
9th Edition
ISBN: 9781119391777
Author: MORAN
Publisher: WILEY
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The following processes occur in a reversible thermodynamic cycle:
1-2.0.2 kg heating at constant pressure 1.05 bar at specific volume 0.1
m/kg and work done -515 J.
2-3: Isothermal compression to 4.2 bar.
3-4: Expansion according to law pv= constant.
4-1: heating at constant volume back to the initial conditions.
Calculate the net work done in joules?
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Question 21 of 84
The following processes occur in a reversible thermodynamic cycle:
1-2: 0.2 kg heating at constant pressure 1.05 bar at specific volume 0.1 m/kg and work done -515 J.
2-3: Isothermal compression to 4.2 bar.
3-4: Expansion according to law pv1./= constant.
4-1: heating at constant volume back to the iniüal conditions.
Calculate the work done for the constant volume heating process?
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An oxygen gas R = 0.2598 KJ/kg°k and k = 1.395. If 4 kg of oxygen undergo a reversible non flow constant pressure process from initial volume =1.2 cubic meter and initial pressure = 690 kPa to a state where final temperature = 600°C.
1. Determine the Change in Internal Energy.
choices: a.200.60 KJ. b.198.45 KJ. c.99.54 KJ. d.200.55 KJ
2. Determine the constant pressure-specific heat.
choices: a.0.9865 KJ/kg-°K. b.0.9175 KJ/kg-°K. c.0.8580 KJ/Kg-°K. d.0.7843 KJ/kg-°K
need complete solution, cancellation and symbol:)
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- 2.Find the minimum work done per Kg of air in a cycle according to the following processes: a. Isothermal expansion from state 1 to state 2. b. Constant volume compression from state 2 to state 3. c. Constant pressure compression from state 3 to the initial state. Data: P1= 350 KPa V1 = 1 m3 /Kg T3 = 16500 C d. Represent the work on a p-V diagram.arrow_forwardA reversible power cycle whose thermal efficiency is 37% receives 50 kJ by heat transfer from a hot reservoir at 300°C and rejects energy by heat transfer to a cold reservoir at temperature TC Determine a. the amount of energy rejected by heat Qc in kJ b. the amount of energy rejected by heat Tc in °C c. Entropy production for the cycle σcycle, in kJ/K.arrow_forwardAs shown in the figure below, two reversible cycles arranged in series each produce the same net work, Wcycle. The first cycle receives energy QH by heat transfer from a hot reservoir at TH-1000°R and rejects energy Q by heat transfer to a reservoir at an intermediate temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature T and rejects energy Qc by heat transfer to a reservoir at Te - 500°R. All energy transfers are positive in the directions of the arrows. Determine: Hot reservoir at TH lH R1 Reservoir Q at T 20 R2 lc Cold reservoir at Tc We cycle W Wcycle (a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two power cycles. (b) the thermal efficiency of a single reversible power cycle operating between hot and cold reservoirs at 1000°R and 500°R, respectively. Also, determine the ratio of the network developed by the single cycle to the network developed by each of the two cycles, Wcycle-arrow_forward
- pls answer all the given thanksarrow_forward1 kg of a fluid expands reversibly according to a linear law from 4.5 bar to 1.6 bar, the initial and final volumes are 0.004 m' and 0.02 m The fluid is then cooled reversibly at C. constant pressure. and finally compressed reversibly according to a law pV back to the initial conditions of 4,5 bar and 0.004 m Determine the work done in each process and the net work of the cycle. Sketch the cycle on a p-v diagram. =constantarrow_forwardQ.1 A piston-cylinder device operates 1 kg of fluid at 20 bar pressure. The initial volume is 0.1 (the last digit of your id.no). The fluid is expand reversibly following the process pv¹.3 = constant. at point B the volume becomes 1.5 m³. The fluid is then cooled at a constant temperature. Calculate the work done in the cycle. p (bar) 0.1 last digit of your id. no 0.1 v cu.m Py ¹.3 B 1.5arrow_forward
- Consider 100 kg of steam initially at 20 bar and 240°C as the system. Determine the change in exergy, in kJ, for each of the following processes: a) The system is heated at constant pressure until its volume doubles b) The system explands isothermally until its volume doubles Let To = 20°C, Po = 1 bar and ignore the effects of motion and gravity.arrow_forwardNeed ASAP thank you.arrow_forwardThe following processes occur in a reversible thermodynamic cycle: 1-2: 0.2 kg heating at constant pressure 1.05 bar at specific volume 0.1 m m3/kg and work done -515 J. 2-3: Isothermal compression to 4.2 bar. 3-4: Expansion according to law pv1./= constant. 4-1: heating at constant volume back to the initial conditions. Calculate the specific work done for process 1-2 in J/kg.arrow_forward
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