Chapter 7, Problem 64P

1. Determine the normal force, shear force, and moment at point C. 10 kN C -1.5 m 1.5 m 1.5 m 15 kN -1.5 m B

The load D has a mass of 220 kg and is being hoisted by the motor M with constant velocity.   Determine the resultant normal force acting on the cross section at point E in the beam.   Determine the resultant shear force acting on the cross section at point E in the beam.   (Express answer to three significant figures and include appropriate units.)

The beam is loaded with a uniformly varying load 0 at point D and maximum of 7 kN/m at the fixed support. Determine sense of the moment at the fixed support. D B 0.8 m → 1.8 m 0.4 m 25 kN

The beam is loaded with a uniformly varying load O at point D and maximum of 7 kN/m at the fixed support. Determine the resulting moment at the fixed support. D B 1.8 m →+ 0.8 m → 0.4 m 25 kN

The horizontal force P is subjected on the slit open circular ring beam. Determine the horizontal and vertical displacements at point A.   You are given a circular ring that is not entirely closed; it is open with a small gap so that theta goes from 0 to 2*Pi. The force P acts horizontally at the point where the ring is split, point A. Then you need to add a fictitious vertical load and a fictitious moment at point A.

Determine the normal force, shear force, and moment at points F and E. w = 50 a = 7 b= 5.0 A - 3 ft -Ε 2 ft B a W b F D 2 ft

Determine the internal normal force, shear force, and moment at point B in the beam. Point A is fixed to the wall. 7 kN 4 kN/m 30 kN • m A В -2 m 3 m- 5 m 2 m→ -3 m

Determine the internal normal force, shear force and the moment at points C and D. 2 m C Sup 6 m 45% 3 m D 2 kN/m 3 m B matolom

Determine the moment of the force about point O. Neglect the thickness of the member. Assume F = 60 N. Sign convention applies for the answer (positive is anti-clockwise). F -100 mm- m - 1600 45° 200 mm Answers: (a) -13.5 Nm (b) 13.5 Nm (c) 12.0 Nm (d) -12.0 Nm -100 mm-