Chapter 6, Problem 6.3CU

A thermodynamic steady flow system receives 4.56 kg at a boundary where p, = 551.6 kPa, v; - 0.193 m*/kg, 0, = 183 m/s and u, = 52.80 k.J/kg. During passage through the system the fluid receives 3,000 J/s of heat. Determine the work

Bmbx

An oxygen gas R = 0.2598 KJ/kg°k and k = 1.395. If 4 kg of oxygen undergo a reversible non flow constant pressure process from initial volume =1.2 cubic meter and initial pressure = 690 kPa to a state where final temperature = 600°C. What is the initial temperature ? 797.10 °K 796.77 °K 786.76°K 876.50°K Other: Determine the constant volume specific heat. 0.6568 KJ/Kg-°K 0.5897 KJ/Kg-°K 0.6580 KJ/Kg-°K 0.6577 KJ/Kg-°K Determine the Change in Internal Energy. 199.54 KJ 200.55 KJ 198.45 KJ 200.60 KJ Please show complete solution with derivation of formulas

T-4

When a system undergoes a Isochoric process (P = 5 bar), the change in internal internal is 5 kJ and temperature during the process is 15°C. Then its change in entropy would be approximately 1.736 kJ/kgK Select one: True False

Show your complete solution

A liquid expands reversibly in keeping with a linear regulation from 4.5 bar to 2 bar. The preliminary and very last volumes are 0.008 m^3 and 0.03 m^3. The fluid is then cooled reversibly at regular pressure, and subsequently compressed reversibly in keeping with a regulation pv regular again to the preliminary situations of 4.5 bar and 0.008 m^3. Calculate: a) the volume at the start isothermal compression. b) the work completed in every process, and c) the network of the cycle. Assume liquid as fluid

i) Use the thermodynamic identity for a P-V-T system and the equation of state to show that the entropy change of one mole of an ideal gas of vibrating diatomic molecules, as volume and temperature are changed, is given by; 7 AS = S(V;,T;) – S(V;, T;) = ;Rln + Rln T ii) The gas undergoes an isobaric compression from V; to V;/2. Evaluate the change in the number of microstates of the system that occurs as a result. ii) Using the equation derived in i), demonstrate that for an ideal gas undergoing an adiabatic expansion from initial volume V; to final volume V; the change in entropy is zero.

= 71°C with v₁ = 0.201 m³/kg. The gas v1 A piston-cylinder assembly holds 1.2 kg of air initially at T₁ undergoes a process as an ideal gas and reaches a final state at T2 = 149° C with v2 = Determine the change in entropy AS in kJ/K. Assume c = 0.72 kJ/kg. K. 0.725 m³/kg. (a) AS = Ex: 0.888 kJ/K (b) Is the process adiabatic? Pick (c) What is the direction of heat transfer? Pick Air