FUNDAMENTALS OF THERMODYNAMICS
10th Edition
ISBN: 9781119634928
Author: Borgnakke
Publisher: WILEY
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A 2.5 kg copper block at 200 °C and 5 kg aluminum block at 20 °C come in thermal contact. Find the final
temperature and the entropy generated. Consider both blocks together as your system and assume no
heat loss to the surroundings.
A nozzle is a device for measuring the velocity of flow. At inlet to a nozzle the
enthalpy is 3026 kJ/k, the velocity is 60 m/s. At exit from the nozzle the enthalpy
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Find he velocity at nozzle exit
The inlet area is 0.1 m2 and the specific volume at the inlet is 0.19 m²/s, find
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Air and fuel enter a furnace used for home heating. The air has an enthalpy of
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furnace has an enthalpy of 616 kJ/kg. There are 17 kgair / kgfuel, water circulated
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what is the fuel consumption per day.
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Q2: One mole of air at P: and temperature Ti is compressed at constant volume till its pressure doubled. Then it is allowed to expand reversibly and isothermally to the original pressure and finally restored to the originol temperature by cooling at constant pressure. Sketch the processes on a P-V and calculate the net work done by the
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- · A closed gaseous system undergoes a reversible process with constant pressure of 200kpa. 2500 kJ of heat is rejected, and the volume changes from 5m3 to 2m3. Find the change in internal energyarrow_forwardWater -Boundary A piston-cylinder device initially contains 14 kg of water at 350 °C and 3.0 MPa. Then the water expanded in a adiabatic process by producing 3000 kJ work out. If the final pressure for the process is 400 kPa, find the entropy changes during this process, in kJ/K.arrow_forwardQ6) One kg of air is allowed to expand reversibly in a cylinder behind a piston in an isothermal process at 260°C, while the volume is doubled. The piston is then moved and heat rejected at constant pressure until the volume is the same as it was initially. Find the heat flow and the overall change of entropy.arrow_forward
- ii. Inside the cylinder-piston is water with at-200C. During isothermal process, 550 kJ of heat is transferred to the water. Due to this, some water evaporated. The change of entropy of water during this process.arrow_forwardA compressor has R-134a entering at 10°C, 100 kPa and exiting as a saturated vapor. It is given that this particular compressor also involves heat loss (i.e., this compressor, in a non-typical fashion, has a non- zero q; i.e., you cannot neglect q for this compressor). If the compressor operates in a reversible isothermal manner, find the specific heat transfer and specific work.arrow_forwardA piston/cylinder receives (control mass system) R-134a at 300 kPa and compresses it in a process where the entropy does not change. to a state of 1000 kPa, 60° C. Find the initial temperature, AND THE CHANGE IN INTERNAL ENERGY.arrow_forward
- 0.02 kg / s entering a radial flow compressor at 100 kPa and 280 K air is compressed to a pressure of 600 kPa. 16 kJ / kg heat loss during process change is happening. Since the power required to run the compressor is 2.732 kW, the kinetic and find the temperature in the final state neglecting the potential energy changes.arrow_forwardFind the quality and internal energy of steam at 700 kPa and enthalpy of 2600 kJ/kg.arrow_forwardThe subject is Thermodynamics 1 Processes of Ideal Gasesarrow_forward
- The 1 lb of air has decrease of internal energy of 20.58 Btu while its Fahrenheit temperature is reduced to 1/3 of the initial temperature during a reversible nonflow constant pressure process. Find 1).the initial and final temperatures, 2). heat 3).workarrow_forwardYou have an adiabatic steam turbine. The steam enters a 0.1m diameter pipe at 200 m/s and it at state conditions of 773K and specific volume of 0.0482 m?/kg. When it exits the turbine as a saturated mixture at 393K its specific volume is 0.665 m²/kg. Using the first law for control volumes, find the work output of the turbine. You can neglect the change in KE and PE.arrow_forwardNumber 3arrow_forward
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What is entropy? - Jeff Phillips; Author: TED-Ed;https://www.youtube.com/watch?v=YM-uykVfq_E;License: Standard youtube license