Statistical Reasoning for Everyday Life - MyStatLab

5th Edition

ISBN: 9781323823781

Author: Bennett

Publisher: PEARSON

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Textbook Question

Chapter 5.2, Problem 27E

Heights of Males. For Exercises 25–36, sketch the normal distribution of heights of adult males, which has a mean of 174 cm and a standard deviation of 7 cm, then shade the described area. Use Table A-1 to find the indicated quantities.

27. The percentage of heights greater than 181 cm

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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Chapter 5.2, Problem 26E

Chapter 5.2, Problem 28E

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2. The SMSA data consisting of 141 observations on 10 variables is fitted by the model below: 1 y = Bo+B1x4 + ẞ2x6 + ẞ3x8 + √1X4X8 + V2X6X8 + €. See Question 2, Tutorial 3 for the meaning of the variables in the above model. The following results are obtained: Estimate Std. Error t value Pr(>|t|) (Intercept) 1.302e+03 4.320e+02 3.015 0.00307 x4 x6 x8 x4:x8 x6:x8 -1.442e+02 2.056e+01 -7.013 1.02e-10 6.340e-01 6.099e+00 0.104 0.91737 -9.455e-02 5.802e-02 -1.630 0.10550 2.882e-02 2.589e-03 11.132 1.673e-03 7.215e-04 2.319 F) x4 1 3486722 3486722 17.9286 4.214e-05 x6 1 14595537 x8 x4:x8 x6:x8 1 132.4836 < 2.2e-16 1045693 194478 5.3769 0.02191 1 1198603043 1198603043 6163.1900 < 2.2e-16 1 25765100 25765100 1045693 Residuals 135 26254490 Estimated variance matrix (Intercept) x4 x6 x8 x4:x8 x6:x8 (Intercept) x4 x6 x8 x4:x8 x6:x8 0.18875694 1.866030e+05 -5.931735e+03 -2.322825e+03 -16.25142055 0.57188953 -5.931735e+03 4.228816e+02 3.160915e+01 0.61621781 -0.03608028 -0.00445013 -2.322825e+03…

In some applications the distribution of a discrete RV, X resembles the Poisson distribution except that 0 is not a possible value of X. Consider such a RV with PMF where 1 > 0 is a parameter, and c is a constant. (a) Find the expression of c in terms of 1. (b) Find E(X). (Hint: You can use the fact that, if Y ~ Poisson(1), the E(Y) = 1.)

Suppose that X ~Bin(n,p). Show that E[(1 - p)] = (1-p²)".

Chapter 5 Solutions

Statistical Reasoning for Everyday Life - MyStatLab

Ch. 5.1 - Normal Distribution. When we refer to a normal...Ch. 5.1 - Normal Shape. Draw a rough sketch of a normal...Ch. 5.1 - Area Under the Curve. What does the area under the...Ch. 5.1 - Normal Conditions. Briefly describe the four...Ch. 5.1 - Does It Make Sense? For Exercises 58, determine...Ch. 5.1 - Does It Make Sense? For Exercises 58, determine...Ch. 5.1 - Does It Make Sense? For Exercises 58, determine...Ch. 5.1 - Does It Make Sense? For Exercises 58, determine...Ch. 5.1 - What Is Normal? Identify the distribution in...Ch. 5.1 - What Is Normal? Identify the distribution in...

Ch. 5.1 - Normal Distributions. For each of the data sets in...Ch. 5.1 - Normal Distributions. For each of the data sets in...Ch. 5.1 - Normal Distributions. For each of the data sets in...Ch. 5.1 - Normal Distributions. For each of the data sets in...Ch. 5.1 - Normal Distributions. For each of the data sets in...Ch. 5.1 - Normal Distributions. For each of the data sets in...Ch. 5.1 - Normal Distributions. For each of the data sets in...Ch. 5.1 - Normal Distributions. For each of the data sets in...Ch. 5.1 - Body Temperature. Figure 5.8 shows a histogram for...Ch. 5.1 - Cotinine. The amount of nicotine absorbed by the...Ch. 5.1 - Departure Delay Times. Figure 5.10 on the next...Ch. 5.1 - MM Weights. Figure 5.11 shows a histogram for the...Ch. 5.1 - Areas and Relative Frequencies. Consider the graph...Ch. 5.1 - Areas and Relative Frequencies. Consider the graph...Ch. 5.1 - Estimating Areas. Consider the graph of the normal...Ch. 5.1 - Prob. 26E Ch. 5.2 - The 68-95-99.7 Rule. What is the 68-95-99.7 rule...Ch. 5.2 - Applying the 68-95-99.7 Rule. For a normal...Ch. 5.2 - Standard Score. What is a standard score? How do...Ch. 5.2 - Percentiles. What is a percentile? Describe how...Ch. 5.2 - Does It Make Sense? For Exercises 58, determine...Ch. 5.2 - Does It Make Sense? For Exercises 58, determine...Ch. 5.2 - Does It Make Sense? For Exercises 58, determine...Ch. 5.2 - Does It Make Sense? For Exercises 58, determine...Ch. 5.2 - Using the 68-95-99.7 Rule. A test of depth...Ch. 5.2 - Using the 68-95-99.7 Rule. Pulse rates for adult...Ch. 5.2 - Applying the 68-95-99.7 Rule. In a study of facial...Ch. 5.2 - Applying the 68-95-99.7 Rule. Adult males have...Ch. 5.2 - IQ Scores. For Exercises 1324, sketch the normal...Ch. 5.2 - IQ Scores. For Exercises 1324, sketch the normal...Ch. 5.2 - IQ Scores. For Exercises 1324, sketch the normal...Ch. 5.2 - IQ Scores. For Exercises 1324, sketch the normal...Ch. 5.2 - IQ Scores. For Exercises 1324, sketch the normal...Ch. 5.2 - IQ Scores. For Exercises 1324, sketch the normal...Ch. 5.2 - IQ Scores. For Exercises 1324, sketch the normal...Ch. 5.2 - Prob. 20E Ch. 5.2 - Prob. 21E Ch. 5.2 - Prob. 22E Ch. 5.2 - Prob. 23E Ch. 5.2 - IQ Scores. For Exercises 1324, sketch the normal...Ch. 5.2 - Heights of Males. For Exercises 2536, sketch the...Ch. 5.2 - Heights of Males. For Exercises 2536, sketch the...Ch. 5.2 - Heights of Males. For Exercises 2536, sketch the...Ch. 5.2 - Heights of Males. For Exercises 2536, sketch the...Ch. 5.2 - Heights of Males. For Exercises 2536, sketch the...Ch. 5.2 - Heights of Males. For Exercises 2536, sketch the...Ch. 5.2 - Heights of Males. For Exercises 2536, sketch the...Ch. 5.2 - Heights of Males. For Exercises 2536, sketch the...Ch. 5.2 - Heights of Males. For Exercises 2536, sketch the...Ch. 5.2 - Heights of Males. For Exercises 2536, sketch the...Ch. 5.2 - Heights of Males. 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Heights of Males. For Exercises 25–36, sketch the normal distribution of heights of adult males, which has a mean of 174 cm and a standard deviation of 7 cm, then shade the described area. Use Table A-1 to find the indicated quantities. 27. The percentage of heights greater than 181 cm

Solution Summary: The author illustrates the normal distribution of heights of adult males, using Table A-1 to find the indicated quantities.

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Chapter 5 Solutions