FUND OF ENG THERMODYN(LLF)+WILEYPLUS
9th Edition
ISBN: 9781119391777
Author: MORAN
Publisher: WILEY
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A system executes a power cycle while receiving 900 Btu by heat transfer at a temperature of 900°R and discharging 800 Btu by heat
transfer at a temperature of 540°R. There are no other heat transfers.
Determine the cycle thermal efficiency. Use the Clausius Inequality to determine Ocycle, in Btu/°R. Determine if this cycle is internally
reversible, irreversible, or impossible.
Step 1
Determine the cycle thermal efficiency.
n =
i
%
A system executes a power cycle while receiving 1000 Btu by heat transfer at a temperature of 900oR and discharging 600 Btu by heat transfer at a temperature of 540oR. There are no other heat transfers.Determine the cycle thermal efficiency. Use the Clausius Inequality to determine σcycle, in Btu/oR. Determine if this cycle is internally reversible, irreversible, or impossible.
Three sub steps of a thermodynamic cycle are employed in order to change the state of
a gas from 1 bar, 1.5 cubic meter and internal energy of 512 kJ. The processes are:
1st step: Compression at constant PV to a pressure of 2 bar and internal energy of 690 kJ.
2nd step: A process where work transferred is zero and heat transferred is - 150 kJ.
3rd step: A process where work transferred is -50 kJ.
without KE and PE changes, determine:
a. heat transferred during 1st step (kJ)
b. heat transferred during 3rd step (kJ)
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- Q2/ A power cycle operating between two reservoirs receives energy Qi by heat transfer from a hot reservoir at T 1000K and rejects energy Q2 by heat transfer to a cold reservoir at Tz-200K For each of the following cases, determine whether the cycle operates reversibly, irreversibly, or is impossible. (a) QI = 500KJ, W 350KJ (b) Q1 = 1000KJ, Q2 200KJ (c) W= 800KJ, Q2 = 500KJ (d) 7 = 95 % %3D %3Darrow_forwardAs shown in the figure below, two reversible cycles arranged in series each produce the same net work, Wcycle. The first cycle receives energy QH by heat transfer from a hot reservoir at TH = 1000°R and rejects energy Q by heat transfer to a reservoir at an intermediate temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature T and rejects energy Qc by heat transfer to a reservoir at Tc = 500°R. All energy transfers are positive in the directions of the arrows. Determine: Hot reservoir at TH QH Reservoir at T R1 lo ali R2 Qc Cold reservoir at Te W. cycle W cycle (a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two power cycles. (b) the thermal efficiency of a single reversible power cycle operating between hot and cold reservoirs at 1000°R and 500°R. respectively. Also, determine the ratio of the net work developed by the single cycle to the net work developed by each of the two cycles, Wcycle.arrow_forwardAs shown in the figure below, two reversible cycles arranged in series each produce the same net work, Wcycle. The first cycle receives energy QH by heat transfer from a hot reservoir at TH = 1500°R and rejects energy Q by heat transfer to a reservoir at an intermediate temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature T and rejects energy QC by heat transfer to a reservoir at TC = 450°R. All energy transfers are positive in the directions of the arrows. Determine:(a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two power cycles.(b) the thermal efficiency of a single reversible power cycle operating between hot and cold reservoirs at 1500°R and 450°R, respectively. Also, determine the ratio of the net work developed by the single cycle to the net work developed by each of the two cycles, Wcycle.arrow_forward
- An air conditioner operating at steady state maintains a dwelling at 20 C on a day when the outside temperature is 35 C. Energy is removed by heat transfer from the dwelling at a rate of 2800 J/s while the air conditioner's power input is 0.8 kw. (a) Determine the coefficient of performance of the air conditioner. (b) Determine the power input required if it was a Carnot refrigerator. English (United States) 目 98%arrow_forwardAs shown in the figure below, two reversible cycles arranged in series each produce the same net work, Wcycle. The first cycle receives energy QH by heat transfer from a hot reservoir at TH-1000°R and rejects energy Q by heat transfer to a reservoir at an intermediate temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature T and rejects energy Qc by heat transfer to a reservoir at Te - 500°R. All energy transfers are positive in the directions of the arrows. Determine: Hot reservoir at TH lH R1 Reservoir Q at T 20 R2 lc Cold reservoir at Tc We cycle W Wcycle (a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two power cycles. (b) the thermal efficiency of a single reversible power cycle operating between hot and cold reservoirs at 1000°R and 500°R, respectively. Also, determine the ratio of the network developed by the single cycle to the network developed by each of the two cycles, Wcycle-arrow_forwardThe refrigerator shown in the figure below operates at steady state with a coefficient of performance (COP) of 5.0 within a kitchen at 23 °C. The refrigerator rejects 4.8 kW by heat transfer to its surroundings from metal coils located on its exterior. Determine: (a) the power input, in kW.(b) the lowest theoretical temperature inside the refrigerator, in K.arrow_forward
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