FUND OF ENG THERMODYN(LLF)+WILEYPLUS
9th Edition
ISBN: 9781119391777
Author: MORAN
Publisher: WILEY
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As shown in the figure below, two reversible cycles arranged in series each produce the same net work, Weycle. The first cycle receives
energy QH by heat transfer from a hot reservoir at TH = 1500°R and rejects energy Q by heat transfer to a reservoir at an intermediate
temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature T and rejects energy Qc by
heat transfer to a reservoir at Tc = 500°R. All energy transfers are positive in the directions of the arrows.
Hot reservoir at T
RI
W.
cycle
Reservoir
at T
R2
Wcycle
Cold reservoir at Te
Determine:
(a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two power cycles.
(b) the thermal efficiency of a single reversible power cycle operating between hot and cold reservoirs at 1500°R and 500°R,
respectively. Also, determine the ratio of the net work developed by the single cycle to the net work developed by each of the two
cycles, Woycle-
The system shown is at steady state, steady flow. At inlet 1, the rates of kinetic
energy, potential energy and enthalpy entering the system are: KE1 = 0.10 kW, PE1
%3D
0.22 kW, and H1 = 27.0 kW. At inlet 2, the rates are: KE2 = 0.23 kW, PE2 = 0.18 kW,
and H2 = 18.0 kVW. At exit 3, the rates are: KE3 = 0.52 kW, PE3 = 0.28 kW, and H3 =
7.0 kW. If the system gives up 5.0 kW of heat to the surroundings, what is the rate of
work transfer of the system? Express the answer in kw.
%3D
KE3
PE3
1
KE.
РЕ
H.
KE2
PE2
На
Control volume
boundary
As shown in the figure below, two reversible cycles arranged in series each produce the same net work, Wcycle. The first cycle receives
energy QH by heat transfer from a hot reservoir at TH = 1000°R and rejects energy Q by heat transfer to a reservoir at an intermediate
temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature T and rejects energy Qc by
heat transfer to a reservoir at Tc = 500°R. All energy transfers are positive in the directions of the arrows.
Determine:
Hot reservoir at TH
QH
Reservoir
at T
R1
lo
ali
R2
Qc
Cold reservoir at Te
W.
cycle
W
cycle
(a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two power cycles.
(b) the thermal efficiency of a single reversible power cycle operating between hot and cold reservoirs at 1000°R and 500°R.
respectively. Also, determine the ratio of the net work developed by the single cycle to the net work developed by each of the two
cycles, Wcycle.
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- As shown in the figure below, two reversible cycles arranged in series each produce the same net work, Wcycle. The first cycle receives energy QH by heat transfer from a hot reservoir at TH = 1500°R and rejects energy Q by heat transfer to a reservoir at an intermediate temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature T and rejects energy QC by heat transfer to a reservoir at TC = 450°R. All energy transfers are positive in the directions of the arrows. Determine:(a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two power cycles.(b) the thermal efficiency of a single reversible power cycle operating between hot and cold reservoirs at 1500°R and 450°R, respectively. Also, determine the ratio of the net work developed by the single cycle to the net work developed by each of the two cycles, Wcycle.arrow_forwardAs shown in the figure below, two reversible cycles arranged in series each produce the same net work, Weycle: The first cycle receives energy QH by heat transfer from a hot reservoir at TH = 1000°R and rejects energy Q by heat transfer to a reservoir at an intermediate temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature Tand rejects energy Qc by heat transfer to a reservoir at Tc = 450°R. All energy transfers are positive in the directions of the arrows. Hot reservoir at TH R1 W cycle Reservoir at T W cycle R2 Cold reservoir at Te Determine: (a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two power cycles. (b) the thermal efficiency of a single reversible power cycle operating between hot and cold reservoirs at 1000°R and 450°R, respectively. Also, determine the ratio of the net work developed by the single cycle to the net work developed by each of the two cycles, Wcyclearrow_forwardAs shown in the figure below, two reversible cycles arranged in series each produce the same net work, Wcycle. The first cycle receives energy QH by heat transfer from a hot reservoir at TH-1000°R and rejects energy Q by heat transfer to a reservoir at an intermediate temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature T and rejects energy Qc by heat transfer to a reservoir at Te - 500°R. All energy transfers are positive in the directions of the arrows. Determine: Hot reservoir at TH lH R1 Reservoir Q at T 20 R2 lc Cold reservoir at Tc We cycle W Wcycle (a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two power cycles. (b) the thermal efficiency of a single reversible power cycle operating between hot and cold reservoirs at 1000°R and 500°R, respectively. Also, determine the ratio of the network developed by the single cycle to the network developed by each of the two cycles, Wcycle-arrow_forward
- 1. The first law of thermodynamics discussesa. Thermal equilibriumb. Energy conservationc. Direction of heat flowd. Entropy is zero at absolute zero temperature 2. A tank contains 1 kg mass gas whose density is 700 kg/m3. The pressure is increased from 1 bar to 3 bar. The approximate specific boundary work of the system isa. Cannot be find since some data is missingb. 285 kJ/kgc. 0 kJ/kgd. 0.285 kJ/kg 3. The nozzle is a device in whicha. Area decreases b. Area increasesc. Velocity decreases d. Velocity increases 4. Choose the correct statement/s with respect to entropy change during a processa. Entropy increases with increase in pressure at constant temperatureb. Entropy increases with increase in temperature at constant pressurec. Entropy can be kept constant by systematically increase both pressure and temperatured. Entropy can not be changed 5. The isentropic process is also called asa. Adiabatic processb. Irreversible adiabatic processc. Reversible adiabatic processd. Reversible…arrow_forwardIf a closed system undergoes a process for which S2=S1, the process must be internally reversible. - True or False One of the Carnot principles states that all power cycles operating between the same two thermal reservoirs have the same thermal efficiency. - True or False One statement of the second law of thermodynamics recognizes that the extensive property entropy is produced within systems whenever internal irreversibilities are present. - True or Falsearrow_forwardThank youarrow_forward
- 7.25 As shown in Fig. P7.25, a 1-lb metal sphere initially at 2000°R is removed from an oven and quenched by immersing it in a closed tank containing 25 lb of water initially at 500°R. Each substance can be modeled as incompressible. An appropriate constant specific heat for the water is c 1.0 Btu/lb °R, and an appropriate value for the metal is cm = 0.1 Btu/lb oR. Heat transfer from the tank contents can be neglected. Determine the exergy destruction, in Btu. Let To = 77°F. System boundary Metal sphere: Tmi=2000°R m=0.1 Btu/lb R mm= 1 lb Water: Twj=500°R =1.0 Btu/lb R m 25 lb FIGURE P7.25arrow_forwardMultiple choice Questions Question No. 2: When a system is taken from state A to state B through a reversible path 1 and again the system is taken to its initial state A from B through different reversible path 2, then what will be the effect on entropy? a.entropy increasesb.entropy decreasesc. entropy remains constantd. none of the abovearrow_forwardSteam at 44 bar and a dryness fraction, x = 0.9 is throttled to a pressure of 12 bar. Calculate thedifference in power output in kilowatts between the following two expansion processes:a) Steam at the initial pressure of 44 bar and x = 0.9 at State 1 is expanded in a turbine to State 3 at 0.12 bar.b) Steam at the reduced pressure of 12 bar after throttling at State 2 is expanded in another turbine to State 4 at the same exhaust pressure of 0.12 bar.The mass flow rate of steam is 8 kg/sec in both cases and the expansion in both turbines can be assumed to be reversible and adiabatic. Sketch both expansion processes on the same T-s diagram using the respective initial and final state points as described above.Explain the reason for the difference in power output.Calculate the mass flow rate of steam for the turbine operating at the throttled/reduced pressure to generate the same output as the turbine operating at the pressure before throttling.NOTE: You are required to number the state…arrow_forward
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