Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN: 9781305632134
Author: J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher: Cengage Learning
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R2
L3
C5
BRF_OUT
HH
Sine_OUT
100
1m
100n
C3
C4
100n
100n
Figure 9. Square to sine waveform converter circuit
How do we make sense of this? First, we note that R2 and C3 form a first order low pass filter and L3 and C4 form another low pass filter. Both low
pass filters have been set at the same cutoff frequency. The combination of both form a two stage filter to remove the high frequency content
present in the DAB signal. Capacitor C5 is used to remove any residual DC offset in the signal.
But let's just deal with the AC steady state response, which means that you don't need to know any of these details, and then can conveniently treat
this circuit as a blackbox.
What is the theoretical cutoff frequency for the RC and LC filters shown in Figure 9? Answer to within 1% accuracy.
(a) RC Filter cutoff frequency (f 1) =
kHz
For the following steady-state AC circuit, find the complex output voltage, VO, shown in the diagram. Write the answer in polar form (angles in degrees), accurate within 1%.
L1=0.7H, L2=5H, C=14F, R=0.60, and w=0.7 rad/s
L1
m
Vo
R
Vs
5/30°V
Answer:
ய
ww
L2
23
Please draw logic circuit
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