EBK ADVANCED ENGINEERING MATHEMATICS
EBK ADVANCED ENGINEERING MATHEMATICS
6th Edition
ISBN: 9781284127003
Author: ZILL
Publisher: JONES+BARTLETT LEARNING,LLC (CC)
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[) Hwk 25 → C Hwk 27 - (MA 244-03) (SP25) IN X Answered: [) Hwk 25 4. [-/4 Poir X + https://www.webassign.net/web/Student/Assignment-Responses/submit?dep=36606606&tags=autosave#question3706544_6 3. [-/2.85 Points] DETAILS MY NOTES LARLINALG8 7.1.021. Find the characteristic equation and the eigenvalues (and a basis for each of the corresponding eigenspaces) of the matrix. 2 -2 5 0 3 -2 0-1 2 (a) the characteristic equation (b) the eigenvalues (Enter your answers from smallest to largest.) (1, 2, 13) = ·( ) a basis for each of the corresponding eigenspaces X1 x2 = x3 = Need Help? Read It Watch It SUBMIT ANSWER 4. [-/2.85 Points] DETAILS MY NOTES LARLINALG8 7.1.041. Find the eigenvalues of the triangular or diagonal matrix. (Enter your answers as a comma-separated list.) λ= 1 0 1 045 002 Need Help? Read It ASK YOUR TEACHER PRACTICE ANOTHER ASK YOUR TEACHER PRACTICE ANOTHER ill
[) Hwk 25 4. [-/4 Points] Hwk 25 - (MA 244-03) (SP25) || X Answered: Homework#7 | bartle X + https://www.webassign.net/web/Student/Assignment-Responses/last?dep=36606604 DETAILS MY NOTES LARLINALG8 6.4.019. Use the matrix P to determine if the matrices A and A' are similar. -1 -1 12 9 '-[ ¯ ¯ ], ^ - [ _—2—2 _ ' ], ^' - [ ˜³ −10] P = 1 2 A = -20-11 A' -3-10 6 4 P-1 = Are they similar? Yes, they are similar. No, they are not similar. Need Help? Read It SUBMIT ANSWER P-1AP = 5. [-/4 Points] DETAILS MY NOTES LARLINALG8 6.4.023. Suppose A is the matrix for T: R³ - → R³ relative to the standard basis. Find the diagonal matrix A' for T relative to the basis B'. A' = -1 -2 0 A = -1 0 0 ' 0 02 B' = {(−1, 1, 0), (2, 1, 0), (0, 0, 1)} ☐☐☐ ↓ ↑ Need Help? Read It Update available →] - restart now ASK YOUR T Sync and save data { Sign In ill ↑ New tab HT New window N New private window +HP ASK YOUR T Bookmarks History Downloads > > HJ Passwords Add-ons and themes HA Print... HP Save page as... HS…
Clarification: 1. f doesn’t have REAL roots2. f is a quadratic, so a≠0
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