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A 1.50 μF  capacitor is charging through a 16.0 Ω resistor using a 15.0 V  battery.  What will be the current when the capacitor has acquired 1/4 of its maximum charge? Please explain all steps
In the circuit shown in the figure (Figure 1), the 6.0 Ω resistor is consuming energy at a rate of 24 J/s when the current through it flows as shown. What are the polarity and emf of the battery E, assuming it has negligible internal resistance? Please explain all steps. I know you need to use the loop rule, but I keep getting the answer wrong.
If you connect a 1.8 F and a 2.6 F capacitor in series, what will be the equivalent capacitance?
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