The number of stereoisomers present in given structure of ephedrine has to be determined. Concept introduction: Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter. Asymmetric center is a stereocenter which arises to hydrocarbons if the carbon is bonded to four different groups. The equation for finding Stereoisomers from number of asymmetric centers in compounds is 2 n , in which ‘n’ is the number of asymmetric centers.

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Answer 1

Question

Chapter 4, Problem 75P

(a)

Interpretation Introduction

Interpretation:

The number of stereoisomers present in given structure of ephedrine has to be determined.

Concept introduction:

Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter.

Asymmetric center is a stereocenter which arises to hydrocarbons if the carbon is bonded to four different groups.

The equation for finding Stereoisomers from number of asymmetric centers in compounds is 2n, in which ‘n’ is the number of asymmetric centers.

(b)

Interpretation Introduction

Interpretation:

The configuration of each of asymmetric centers has to be given.

Concept introduction:

According to Cahn-Ingold-Prelog system,

The group attached to asymmetric center should be ranked based on the atomic number of atom which directly connected to asymmetric center. The higher the atomic number of atom, higher the priority. If there is tie, then consider the next atoms attached to the connected atom and so on.

Check the direction of arrow drawn in the direction of decreasing priority. If the arrow points clockwise direction, then the compound has R configuration. If the arrow points counterclockwise direction, then the compound has S configuration. If the group with lowest priority is not bonded by a hatched wedge, then interchange this group (lowest priority) by group bonded to hatched wedge and draw the arrow in priority order but the configuration is assigned as just reverse.

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Can you please help mne with this problem. Im a visual person, so can you redraw it, potentislly color code and then as well explain it. I know im given CO2 use that to explain to me, as well as maybe give me a second example just to clarify even more with drawings (visuals) and explanations.

Part 1. Aqueous 0.010M AgNO 3 is slowly added to a 50-ml solution containing both carbonate [co32-] = 0.105 M and sulfate [soy] = 0.164 M anions. Given the ksp of Ag2CO3 and Ag₂ soy below. Answer the ff: Ag₂ CO3 = 2 Ag+ caq) + co} (aq) ksp = 8.10 × 10-12 Ag₂SO4 = 2Ag+(aq) + soy² (aq) ksp = 1.20 × 10-5 a) which salt will precipitate first? (b) What % of the first anion precipitated will remain in the solution. by the time the second anion starts to precipitate? (c) What is the effect of low pH (more acidic) condition on the separate of the carbonate and sulfate anions via silver precipitation? What is the effect of high pH (more basic)? Provide appropriate explanation per answer

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Answer 2

Question

Chapter 4, Problem 75P

(a)

Interpretation Introduction

Interpretation:

The number of stereoisomers present in given structure of ephedrine has to be determined.

Concept introduction:

Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter.

Asymmetric center is a stereocenter which arises to hydrocarbons if the carbon is bonded to four different groups.

The equation for finding Stereoisomers from number of asymmetric centers in compounds is 2n, in which ‘n’ is the number of asymmetric centers.

(b)

Interpretation Introduction

Interpretation:

The configuration of each of asymmetric centers has to be given.

Concept introduction:

According to Cahn-Ingold-Prelog system,

The group attached to asymmetric center should be ranked based on the atomic number of atom which directly connected to asymmetric center. The higher the atomic number of atom, higher the priority. If there is tie, then consider the next atoms attached to the connected atom and so on.

Check the direction of arrow drawn in the direction of decreasing priority. If the arrow points clockwise direction, then the compound has R configuration. If the arrow points counterclockwise direction, then the compound has S configuration. If the group with lowest priority is not bonded by a hatched wedge, then interchange this group (lowest priority) by group bonded to hatched wedge and draw the arrow in priority order but the configuration is assigned as just reverse.

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Answer 3

Question

Chapter 4, Problem 75P

(a)

Interpretation Introduction

Interpretation:

The number of stereoisomers present in given structure of ephedrine has to be determined.

Concept introduction:

Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter.

Asymmetric center is a stereocenter which arises to hydrocarbons if the carbon is bonded to four different groups.

The equation for finding Stereoisomers from number of asymmetric centers in compounds is 2n, in which ‘n’ is the number of asymmetric centers.

(b)

Interpretation Introduction

Interpretation:

The configuration of each of asymmetric centers has to be given.

Concept introduction:

According to Cahn-Ingold-Prelog system,

The group attached to asymmetric center should be ranked based on the atomic number of atom which directly connected to asymmetric center. The higher the atomic number of atom, higher the priority. If there is tie, then consider the next atoms attached to the connected atom and so on.

Check the direction of arrow drawn in the direction of decreasing priority. If the arrow points clockwise direction, then the compound has R configuration. If the arrow points counterclockwise direction, then the compound has S configuration. If the group with lowest priority is not bonded by a hatched wedge, then interchange this group (lowest priority) by group bonded to hatched wedge and draw the arrow in priority order but the configuration is assigned as just reverse.

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Answer 4

Question

Chapter 4, Problem 75P

(a)

Interpretation Introduction

Interpretation:

The number of stereoisomers present in given structure of ephedrine has to be determined.

Concept introduction:

Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter.

Asymmetric center is a stereocenter which arises to hydrocarbons if the carbon is bonded to four different groups.

The equation for finding Stereoisomers from number of asymmetric centers in compounds is 2n, in which ‘n’ is the number of asymmetric centers.

(b)

Interpretation Introduction

Interpretation:

The configuration of each of asymmetric centers has to be given.

Concept introduction:

According to Cahn-Ingold-Prelog system,

The group attached to asymmetric center should be ranked based on the atomic number of atom which directly connected to asymmetric center. The higher the atomic number of atom, higher the priority. If there is tie, then consider the next atoms attached to the connected atom and so on.

Check the direction of arrow drawn in the direction of decreasing priority. If the arrow points clockwise direction, then the compound has R configuration. If the arrow points counterclockwise direction, then the compound has S configuration. If the group with lowest priority is not bonded by a hatched wedge, then interchange this group (lowest priority) by group bonded to hatched wedge and draw the arrow in priority order but the configuration is assigned as just reverse.

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Answer 5

Chapter 4, Problem 75P

(a)

Interpretation Introduction

Interpretation:

The number of stereoisomers present in given structure of ephedrine has to be determined.

Concept introduction:

Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter.

Asymmetric center is a stereocenter which arises to hydrocarbons if the carbon is bonded to four different groups.

The equation for finding Stereoisomers from number of asymmetric centers in compounds is 2n, in which ‘n’ is the number of asymmetric centers.

(b)

Interpretation Introduction

Interpretation:

The configuration of each of asymmetric centers has to be given.

Concept introduction:

According to Cahn-Ingold-Prelog system,

The group attached to asymmetric center should be ranked based on the atomic number of atom which directly connected to asymmetric center. The higher the atomic number of atom, higher the priority. If there is tie, then consider the next atoms attached to the connected atom and so on.

Check the direction of arrow drawn in the direction of decreasing priority. If the arrow points clockwise direction, then the compound has R configuration. If the arrow points counterclockwise direction, then the compound has S configuration. If the group with lowest priority is not bonded by a hatched wedge, then interchange this group (lowest priority) by group bonded to hatched wedge and draw the arrow in priority order but the configuration is assigned as just reverse.

Answer 6

Chapter 4, Problem 75P

(a)

Interpretation Introduction

Interpretation:

The number of stereoisomers present in given structure of ephedrine has to be determined.

Concept introduction:

Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter.

Asymmetric center is a stereocenter which arises to hydrocarbons if the carbon is bonded to four different groups.

The equation for finding Stereoisomers from number of asymmetric centers in compounds is 2n, in which ‘n’ is the number of asymmetric centers.

Answer 7

Chapter 4, Problem 75P

(a)

Interpretation Introduction

Interpretation:

The number of stereoisomers present in given structure of ephedrine has to be determined.

Concept introduction:

Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter.

Asymmetric center is a stereocenter which arises to hydrocarbons if the carbon is bonded to four different groups.

The equation for finding Stereoisomers from number of asymmetric centers in compounds is 2n, in which ‘n’ is the number of asymmetric centers.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The configuration of each of asymmetric centers has to be given.

Concept introduction:

According to Cahn-Ingold-Prelog system,

The group attached to asymmetric center should be ranked based on the atomic number of atom which directly connected to asymmetric center. The higher the atomic number of atom, higher the priority. If there is tie, then consider the next atoms attached to the connected atom and so on.

Check the direction of arrow drawn in the direction of decreasing priority. If the arrow points clockwise direction, then the compound has R configuration. If the arrow points counterclockwise direction, then the compound has S configuration. If the group with lowest priority is not bonded by a hatched wedge, then interchange this group (lowest priority) by group bonded to hatched wedge and draw the arrow in priority order but the configuration is assigned as just reverse.

Answer 9

(b)

Interpretation Introduction

Interpretation:

The configuration of each of asymmetric centers has to be given.

Concept introduction:

According to Cahn-Ingold-Prelog system,

The group attached to asymmetric center should be ranked based on the atomic number of atom which directly connected to asymmetric center. The higher the atomic number of atom, higher the priority. If there is tie, then consider the next atoms attached to the connected atom and so on.

Check the direction of arrow drawn in the direction of decreasing priority. If the arrow points clockwise direction, then the compound has R configuration. If the arrow points counterclockwise direction, then the compound has S configuration. If the group with lowest priority is not bonded by a hatched wedge, then interchange this group (lowest priority) by group bonded to hatched wedge and draw the arrow in priority order but the configuration is assigned as just reverse.

Answer 10

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Answer 13

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Solution Summary: The author explains that stereoisomers have different spatial arrangement in spite of same bond connectivity. Asymmetric center arises to hydrocarbons if the carbon is bonded to four different groups.

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