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MATERIALS SCI.+ENGR.:INTRO.-NEXTGEN
10th Edition
ISBN: 9781119503941
Author: Callister
Publisher: WILEY
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I REPEAT!!!!! I NEED HANDDRAWING!!!!! NOT A USELESS EXPLANATION!!!! I REPEAT SUBMIT A HANDDRAWING IF YOU CANNOT UNDERSTAND THIS SKIP IT !
I need the real handdrawing complete it by adding these :
Pneumatic Valves
Each linear actuator must be controlled by a directional control valve (DCV) (e.g., 5/2 or 4/2 valve).
The bi-directional motor requires a reversible valve to change rotation direction.
Pressure Regulators & Air Supply
Include two pressure regulators as per the assignment requirement.
Show the main compressed air supply line connecting all components.
Limit Switches & Safety Features
Attach limit switches to each actuator to detect positions.
Implement a two-handed push-button safety system to control actuator movement.
Connections Between Components
Draw air supply lines linking the compressor, valves, and actuators.
Clearly label all inputs and outputs for better understanding.
Pls show neat and whole solution
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- I need the real handdrawing complete it by adding these : Pneumatic Valves Each linear actuator must be controlled by a directional control valve (DCV) (e.g., 5/2 or 4/2 valve). The bi-directional motor requires a reversible valve to change rotation direction. Pressure Regulators & Air Supply Include two pressure regulators as per the assignment requirement. Show the main compressed air supply line connecting all components. Limit Switches & Safety Features Attach limit switches to each actuator to detect positions. Implement a two-handed push-button safety system to control actuator movement. Connections Between Components Draw air supply lines linking the compressor, valves, and actuators. Clearly label all inputs and outputs for better understanding.arrow_forwardSolve the homework in a realistic way in more than one way with paper and pen without artificial intelligencearrow_forwardAn elastic bar of the length L and cross section area A is rigidly attached to the ceiling of a room, and it supports a mass M. Due to the acceleration of gravity g the rod deforms vertically. The deformation of the rod is measured by the vertical displacement u(x) governed by the following equations: dx (σ(x)) + b(x) = 0 PDE σ(x) = Edx du Hooke's law (1) b(x) = gp= body force per unit volume where E is the constant Young's modulus, p is the density, and σ(x) the axial stress in the rod. g * I u(x) L 2arrow_forward
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