Chapter 4, Problem 26QAP

CORRECT AND DETAILED HANDWRITTEN SOLUTION WITH FBD ONLY. I WILL UPVOTE THANK YOU. CORRECT ANSWER IS ALREADY PROVIDED. A short plate is attached to the center of the shaft as shown. The bottom of the shaft is fixed to the ground.Given: a = 75 mm, h = 125 mm, D = 38 mmP1 = 24 kN, P2 = 28 kN1. Calculate the maximum torsional stress in the shaft, in MPa.2. Calculate the maximum flexural stress in the shaft, in MPa.3. Calculate the maximum horizontal shear stress in the shaft, in MPa.ANSWERS: (1) 167.07 MPa; (2) 679.77 MPa; (3) 28.22 MPa

Medium 1 is a lossless dielectric (ε₁, μ₁ = μo, σ₁ = 0) Medium 2 is a perfect electric conductor (PEC) ( 2 = 0, μ2 = μo, σ₂ = ∞) [ Moσ = 0] [ε0 μ₁ σ₂ = ∞ ] (J=σE is finite, E = 0) E(z) Exe² +Пe₁²] 1. For the case εr] = λι = = E2(z)-0 - 1 (vacuum), E₁x 1 V/m and a frequency f = 500 MHz determine: n₁ = 12= 2. Determine: r = T= 3. Using this I show that the total electric field E₁0(z) in region 1 can be written as: E(z) = -2jE, sin(2лz/λ)✰ 4. The magnitude E10(z) will show an interference pattern. The SWR (standing wave ratio) is the Emax/Emin ratio of the magnitude of the total electric field in region 1. What is the SWR? E (z) = 2|E|sin(2лz/2₁)| E" (z) SWR A Imax E(z) Imin 1+r 1-|| tot 5. Roughly SKETCH the magnitude of E10(z) and E20(z) on the graph below. E₁tot(z) tot E20(z) -0.40 -0.30 -0.ło z=0 +0.1b +0.20

I need detailed help solving this exercise from homework of Engineering Mathematics II.I do not really understand how to do, please do it step by step, not that long but clear. Thank you!P.S.: Please do not use AI, thanks!