Chapter 4, Problem 26QAP

R2 L3 C5 BRF_OUT HH Sine_OUT 100 1m 100n C3 C4 100n 100n Figure 9. Square to sine waveform converter circuit How do we make sense of this? First, we note that R2 and C3 form a first order low pass filter and L3 and C4 form another low pass filter. Both low pass filters have been set at the same cutoff frequency. The combination of both form a two stage filter to remove the high frequency content present in the DAB signal. Capacitor C5 is used to remove any residual DC offset in the signal. But let's just deal with the AC steady state response, which means that you don't need to know any of these details, and then can conveniently treat this circuit as a blackbox. What is the theoretical cutoff frequency for the RC and LC filters shown in Figure 9? Answer to within 1% accuracy. (a) RC Filter cutoff frequency (f 1) = kHz

For the following steady-state AC circuit, find the complex output voltage, VO, shown in the diagram. Write the answer in polar form (angles in degrees), accurate within 1%. L1=0.7H, L2=5H, C=14F, R=0.60, and w=0.7 rad/s L1 m Vo R Vs 5/30°V Answer: ய ww L2 23

A (A) Q1/ It is required to apply a net depth of 120mm to a total area of 60 ha. The applied discharge is continuously 180 L/s. What must be the time of irrigation? Assume the application efficiency 85%. а Eas 85 0% t

heat and mass transfer

heat and mass transfer

heat and mass transfer

heat and mass transfer

The following figure is a flexible pavement system with the resilient moduli layer coefficients and drainage coefficients as shown. If the predicted ESAL = 6x106, Reliability, R = 99%, Standard Deviation (So) = 0.45, and APSI = 2.5, select thicknesses D1, D2, and D3 in accordance with the AASHTO Guide for Design of Pavement Structures. E₁ = 400, 000 psi; a₁ = 0.42, Thickness = D₁ E₂=30,000 psi; a₂= 0.14, m₂ = 1.2; Thickness = Dz E=11,000 psi; a=0.08, m3 = 1.2; Thickness = D3 MR= 5,700 psi

(read image) (Answer: M motor = 0.836 Ib-ft, Mf = 0.1045 Ib-ft)