COLLEGE ALGEBRA ESSENTIALS-DIGITAL 18WK
6th Edition
ISBN: 9780136804741
Author: Blitzer
Publisher: PEARSON
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Chapter 3.7, Problem 20E
To determine
To write: The equation that expresses the given relationship.
To determine
To solve: The above equation that express the given relationship for y.
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Students have asked these similar questions
??!!
rections: For problem
rough 3, read
each question carefully and be sure to
show all work.
1. Determine if
9(4a²-4ab+b²) = (6a-3b)² is a
polynomial identity.
2. Is (2x-y) (8x3+ y³) equivalent to
16x4-y4?
3. Find an expression that is equivalent to
(a - b)³.
Directions: For problems 4 and 5,
algebraically prove that the following
equations are polynomial identities. Show
all of your work and explain each step.
4. (2x+5)² = 4x(x+5)+25
5. (4x+6y)(x-2y)=2(2x²-xy-6y²)
Name:
Mussels & bem
A section of a river currently has a population of 20 zebra mussels. The
population of zebra mussels increases 60 % each month. What will be the
population of zebra mussels after 2 years?
9
10
# of
months
# of
mussels
1
2
3
4
5
6
7
8
o
Graph your data. Remember to title your graph.
What scale should be used on the y-axis?
What scale should be used on the x-axis?
Exponential Growth Equation
y = a(1+r)*
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- Expanding a logarithmic expression: Problem type 2 Use the properties of logarithms to expand the following expression. 3 yz log 5 x 0/3 An Each logarithm should involve only one variable and should not have any radicals or exponents. You may assume that all variables are positive. log yz 3 厚 5 Explanation Check log ☑ 2025 MG ¿W MIII LLC. All Rights Reserved. Terms of Use | Privacy Centerarrow_forwardWhat is the domain and range, thank you !!arrow_forwardAssume a bivariate patch p(u, v) over the unit square [0, 1]² that is given as a tensor product patch where u-sections (u fixed to some constant û; v varying across [0, 1]) are quadratic polynomials Pu:û(v) = p(û, v) while v-sections are lines pv:ô (u) = p(u, v). The boundary lines pv:o(u) and pv:1 (u) are specified by their end points p(0,0) 0.8 and p(1,0) 0.2 as well as p(0, 1) 0.3 and p(1, 1) = 0.8. The boundary quadratics pu:o(v) and pu:1 (v) interpolate p(0,0.5) = 0.1 and p(1, 0.5) = 0.9 in addition to the above given four corner-values. = = = Use Pu:û(v) = (1, v, v² ) Mq (Pu:û(0), Pu:û (0.5), Pu:û(1)) with Ma = 1 0 0 -3 4-1 2 4 2 (Pv:ô as well as pu: (u) = (1, u) M₁ (pv:v (0), P: (1)) with M₁ = = (19) 0 to formulate p(u, v) using the "geometric input" G with G = = (P(0,0%) p(0,0) p(0,0.5) p(0,1) ) = ( 0.39 0.8 0.1 0.3 0.2 0.9 0.8 p(1,0) p(1, 0.5) p(1, 1) See the figure below for (left) a selection of iso-lines of p(u, v) and (right) a 3D rendering of p(u, v) as a height surface…arrow_forward
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