You are conducting a single-slit diffraction experiment with light of wavelength λ . What appears, on a distant viewing screen, at a point at which the top and bottom rays through the slit have a path length difference equal to (a) 5 λ and (b) 4.5 λ ?
You are conducting a single-slit diffraction experiment with light of wavelength λ . What appears, on a distant viewing screen, at a point at which the top and bottom rays through the slit have a path length difference equal to (a) 5 λ and (b) 4.5 λ ?
You are conducting a single-slit diffraction experiment with light of wavelength λ. What appears, on a distant viewing screen, at a point at which the top and bottom rays through the slit have a path length difference equal to (a) 5λ and (b) 4.5λ?
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Expert Solution & Answer
To determine
To find:
a) What appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 5λ.
b) What appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 4.5λ.
Answer to Problem 1Q
Solution:
a) m=5 minimum.
b) Maximum between the m=4 and m=5 (approximately).
Explanation of Solution
1) Concept:
Usingthe condition for occurrence of minimum in a single slit experiment, we can find what appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 5λand4.5λ.
2) Formula:
∆L=mλ
3) Given:
The single slit experiment is conducted with the light of wavelength λ.
4) Calculations:
a) In the single slit experiment, the condition for occurrence of minimum is
Pathlengthdifference=∆L=mλForm=1,2,3
From this, we can interpret that at ∆L=5λ;m=5 minimum appears.
b) ∆L=4.5λ implies that it corresponds to approximately maximum between m=4minimumandm=5minimum.
Conclusion:
We can predict about what appears on screen in a single slit experiment from the condition for minimum.
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