DIFFERENTIAL EQUATIONS-ACCESS
4th Edition
ISBN: 9781133109044
Author: Blanchard, Devaney, and Hall
Publisher: ACME
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can I see the steps for how you got the same answers already provided for μ1->μ4. this is a homework that provide you answers for question after attempting it three tries
1. Prove that for each n in N, 1+2++ n = n(n+1)/2.
2. Prove that for each n in N, 13 +23+
3. Prove that for each n in N, 1+3+5+1
4. Prove that for each n ≥ 4,2" -1, then (1+x)" ≥1+nx for each
n in N.
11. Prove DeMoivre's Theorem: fort a real number,
(cost+i sint)" = cos nt + i sinnt
for each n in N, where i = √√-1.
Given the following sample data values:
7, 12, 15, 9, 15, 13, 12, 10, 18,12
Find the following:
a) Σ
x=
b) x² =
c) x =
n
d) Median
=
e) Midrange
x
=
(Enter a whole number)
(Enter a whole number)
(use one decimal place accuracy)
(use one decimal place accuracy)
(use one decimal place accuracy)
f) the range=
g) the variance, s²
(Enter a whole number)
f) Standard Deviation, s =
(use one decimal place accuracy)
Use the formula s²
·Σx² -(x)²
n(n-1)
nΣ x²-(x)²
2
Use the formula s =
n(n-1)
(use one decimal place accuracy)
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- Find the values of p for which the series is convergent. P-?- ✓ 00 Σ nº (1 + n10)p n = 1 Need Help? Read It Watch It SUBMIT ANSWER [-/4 Points] DETAILS MY NOTES SESSCALCET2 8.3.513.XP. Consider the following series. 00 Σ n = 1 1 6 n° (a) Use the sum of the first 10 terms to estimate the sum of the given series. (Round the answer to six decimal places.) $10 = (b) Improve this estimate using the following inequalities with n = 10. (Round your answers to six decimal places.) Sn + + Los f(x) dx ≤s ≤ S₁ + Jn + 1 + Lo f(x) dx ≤s ≤ (c) Using the Remainder Estimate for the Integral Test, find a value of n that will ensure that the error in the approximation s≈s is less than 0.0000001. On > 11 n> -18 On > 18 On > 0 On > 6 Need Help? Read It Watch Itarrow_forward√5 Find Lª³ L² y-are y- arctan (+) dy dydx. Hint: Use integration by parts. SolidUnderSurface z=y*arctan(1/x) Z1 2 y 1 1 Round your answer to 4 decimal places.arrow_forwardFor the solid lying under the surface z = √√4-² and bounded by the rectangular region R = [0,2]x[0,2] as illustrated in this graph: Double Integral Plot of integrand over Region R 1.5 Z 1- 0.5- 0 0.5 1 1.5 205115 Answer should be in exact math format. For example, some multiple of .arrow_forward
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