In Exercises 1-4, graph the given quadratic function. Give each functions domain and range f( x) = ( x - 3) 2 - 4

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Answer 1

Textbook Question

Chapter 3, Problem 1MCCP

In Exercises 1-4, graph the given quadratic function. Give each functions domain and range

f(x) = (x - 3)² - 4

Expert Solution & Answer

To determine

The graph of the given quadratic function and also, the domain and range of the function.

Answer to Problem 1MCCP

Solution: The range of function $f$ is $[−4,∞)$ and the domain of the function is the set of all real number or $(−∞,∞)$ .

COLLEGE ALGEBRA-MYMATHLAB, Chapter 3, Problem 1MCCP , additional homework tip 1

Explanation of Solution

Given: The function is $f(x)=(x−3)2−4$ .

Comparing the provided equation $f(x)=(x−3)2−4$ to the standard parabolic equation $f(x)=a(x−h)2+k$ .

Where, $a=1,h=3,k=−4$ .

The vertex of the parabolic equation is $(h,k)=(3,−4)$ .

Determine the $x$ intercepts.

Put $f(x)=0$ .

$f(x)=(x−3)2−40=(x−3)2−4x−3=±2$

This implies that:

$x−3=±2$

For $+2$

$x−3=2x=5$

For $−2$

$x−3=−2x=1$

The $x$ intercept are $5$ and $1$ . And the parabola passes through the points $(5,0)$ and $(1,0)$ .

Now, to find the $y$ intercept, put $x=0$ .

$f(x)=(x−3)2−4=(0−3)2−4=9−4=5$

The $y$ intercept is $y=5$ and parabola passes through the point $(0,5)$ .

The graph of the parabola equation is shown below as:

COLLEGE ALGEBRA-MYMATHLAB, Chapter 3, Problem 1MCCP , additional homework tip 2

Now, compute the domain.

The $x$ axis on the graph corresponds to the domain of the function. In the graph it is clear that the domain of the function is the set of all real number or $(−∞,∞)$ .\

The range of the function is the output on the $y$ axis on the graph. Since, the vertex is -4, the points on $y$ axis fall at or above -4. Thus, the range of the function is $[−4,∞)$ .

Conclusion: The graph shows that the parabola’s vertex $(3,−4)$ is the lowest point. Thus, the range of function $f$ is $[−4,∞)$ and the domain of the function is the set of all real number or $(−∞,∞)$ .

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Answer 2

Textbook Question

Chapter 3, Problem 1MCCP

In Exercises 1-4, graph the given quadratic function. Give each functions domain and range

f(x) = (x - 3)² - 4

Expert Solution & Answer

To determine

The graph of the given quadratic function and also, the domain and range of the function.

Answer to Problem 1MCCP

Solution: The range of function $f$ is $[−4,∞)$ and the domain of the function is the set of all real number or $(−∞,∞)$ .

COLLEGE ALGEBRA-MYMATHLAB, Chapter 3, Problem 1MCCP , additional homework tip 1

Explanation of Solution

Given: The function is $f(x)=(x−3)2−4$ .

Comparing the provided equation $f(x)=(x−3)2−4$ to the standard parabolic equation $f(x)=a(x−h)2+k$ .

Where, $a=1,h=3,k=−4$ .

The vertex of the parabolic equation is $(h,k)=(3,−4)$ .

Determine the $x$ intercepts.

Put $f(x)=0$ .

$f(x)=(x−3)2−40=(x−3)2−4x−3=±2$

This implies that:

$x−3=±2$

For $+2$

$x−3=2x=5$

For $−2$

$x−3=−2x=1$

The $x$ intercept are $5$ and $1$ . And the parabola passes through the points $(5,0)$ and $(1,0)$ .

Now, to find the $y$ intercept, put $x=0$ .

$f(x)=(x−3)2−4=(0−3)2−4=9−4=5$

The $y$ intercept is $y=5$ and parabola passes through the point $(0,5)$ .

The graph of the parabola equation is shown below as:

COLLEGE ALGEBRA-MYMATHLAB, Chapter 3, Problem 1MCCP , additional homework tip 2

Now, compute the domain.

The $x$ axis on the graph corresponds to the domain of the function. In the graph it is clear that the domain of the function is the set of all real number or $(−∞,∞)$ .\

The range of the function is the output on the $y$ axis on the graph. Since, the vertex is -4, the points on $y$ axis fall at or above -4. Thus, the range of the function is $[−4,∞)$ .

Conclusion: The graph shows that the parabola’s vertex $(3,−4)$ is the lowest point. Thus, the range of function $f$ is $[−4,∞)$ and the domain of the function is the set of all real number or $(−∞,∞)$ .

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 3, Problem 1MCCP

In Exercises 1-4, graph the given quadratic function. Give each functions domain and range

f(x) = (x - 3)² - 4

Expert Solution & Answer

To determine

The graph of the given quadratic function and also, the domain and range of the function.

Answer to Problem 1MCCP

Solution: The range of function $f$ is $[−4,∞)$ and the domain of the function is the set of all real number or $(−∞,∞)$ .

COLLEGE ALGEBRA-MYMATHLAB, Chapter 3, Problem 1MCCP , additional homework tip 1

Explanation of Solution

Given: The function is $f(x)=(x−3)2−4$ .

Comparing the provided equation $f(x)=(x−3)2−4$ to the standard parabolic equation $f(x)=a(x−h)2+k$ .

Where, $a=1,h=3,k=−4$ .

The vertex of the parabolic equation is $(h,k)=(3,−4)$ .

Determine the $x$ intercepts.

Put $f(x)=0$ .

$f(x)=(x−3)2−40=(x−3)2−4x−3=±2$

This implies that:

$x−3=±2$

For $+2$

$x−3=2x=5$

For $−2$

$x−3=−2x=1$

The $x$ intercept are $5$ and $1$ . And the parabola passes through the points $(5,0)$ and $(1,0)$ .

Now, to find the $y$ intercept, put $x=0$ .

$f(x)=(x−3)2−4=(0−3)2−4=9−4=5$

The $y$ intercept is $y=5$ and parabola passes through the point $(0,5)$ .

The graph of the parabola equation is shown below as:

COLLEGE ALGEBRA-MYMATHLAB, Chapter 3, Problem 1MCCP , additional homework tip 2

Now, compute the domain.

The $x$ axis on the graph corresponds to the domain of the function. In the graph it is clear that the domain of the function is the set of all real number or $(−∞,∞)$ .\

The range of the function is the output on the $y$ axis on the graph. Since, the vertex is -4, the points on $y$ axis fall at or above -4. Thus, the range of the function is $[−4,∞)$ .

Conclusion: The graph shows that the parabola’s vertex $(3,−4)$ is the lowest point. Thus, the range of function $f$ is $[−4,∞)$ and the domain of the function is the set of all real number or $(−∞,∞)$ .

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 3, Problem 1MCCP

In Exercises 1-4, graph the given quadratic function. Give each functions domain and range

f(x) = (x - 3)² - 4

Expert Solution & Answer

To determine

The graph of the given quadratic function and also, the domain and range of the function.

Answer to Problem 1MCCP

Solution: The range of function $f$ is $[−4,∞)$ and the domain of the function is the set of all real number or $(−∞,∞)$ .

COLLEGE ALGEBRA-MYMATHLAB, Chapter 3, Problem 1MCCP , additional homework tip 1

Explanation of Solution

Given: The function is $f(x)=(x−3)2−4$ .

Comparing the provided equation $f(x)=(x−3)2−4$ to the standard parabolic equation $f(x)=a(x−h)2+k$ .

Where, $a=1,h=3,k=−4$ .

The vertex of the parabolic equation is $(h,k)=(3,−4)$ .

Determine the $x$ intercepts.

Put $f(x)=0$ .

$f(x)=(x−3)2−40=(x−3)2−4x−3=±2$

This implies that:

$x−3=±2$

For $+2$

$x−3=2x=5$

For $−2$

$x−3=−2x=1$

The $x$ intercept are $5$ and $1$ . And the parabola passes through the points $(5,0)$ and $(1,0)$ .

Now, to find the $y$ intercept, put $x=0$ .

$f(x)=(x−3)2−4=(0−3)2−4=9−4=5$

The $y$ intercept is $y=5$ and parabola passes through the point $(0,5)$ .

The graph of the parabola equation is shown below as:

COLLEGE ALGEBRA-MYMATHLAB, Chapter 3, Problem 1MCCP , additional homework tip 2

Now, compute the domain.

The $x$ axis on the graph corresponds to the domain of the function. In the graph it is clear that the domain of the function is the set of all real number or $(−∞,∞)$ .\

The range of the function is the output on the $y$ axis on the graph. Since, the vertex is -4, the points on $y$ axis fall at or above -4. Thus, the range of the function is $[−4,∞)$ .

Conclusion: The graph shows that the parabola’s vertex $(3,−4)$ is the lowest point. Thus, the range of function $f$ is $[−4,∞)$ and the domain of the function is the set of all real number or $(−∞,∞)$ .

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

To determine

The graph of the given quadratic function and also, the domain and range of the function.

Answer to Problem 1MCCP

Solution: The range of function $f$ is $[−4,∞)$ and the domain of the function is the set of all real number or $(−∞,∞)$ .

COLLEGE ALGEBRA-MYMATHLAB, Chapter 3, Problem 1MCCP , additional homework tip 1

Explanation of Solution

Given: The function is $f(x)=(x−3)2−4$ .

Comparing the provided equation $f(x)=(x−3)2−4$ to the standard parabolic equation $f(x)=a(x−h)2+k$ .

Where, $a=1,h=3,k=−4$ .

The vertex of the parabolic equation is $(h,k)=(3,−4)$ .

Determine the $x$ intercepts.

Put $f(x)=0$ .

$f(x)=(x−3)2−40=(x−3)2−4x−3=±2$

This implies that:

$x−3=±2$

For $+2$

$x−3=2x=5$

For $−2$

$x−3=−2x=1$

The $x$ intercept are $5$ and $1$ . And the parabola passes through the points $(5,0)$ and $(1,0)$ .

Now, to find the $y$ intercept, put $x=0$ .

$f(x)=(x−3)2−4=(0−3)2−4=9−4=5$

The $y$ intercept is $y=5$ and parabola passes through the point $(0,5)$ .

The graph of the parabola equation is shown below as:

COLLEGE ALGEBRA-MYMATHLAB, Chapter 3, Problem 1MCCP , additional homework tip 2

Now, compute the domain.

The $x$ axis on the graph corresponds to the domain of the function. In the graph it is clear that the domain of the function is the set of all real number or $(−∞,∞)$ .\

The range of the function is the output on the $y$ axis on the graph. Since, the vertex is -4, the points on $y$ axis fall at or above -4. Thus, the range of the function is $[−4,∞)$ .

Conclusion: The graph shows that the parabola’s vertex $(3,−4)$ is the lowest point. Thus, the range of function $f$ is $[−4,∞)$ and the domain of the function is the set of all real number or $(−∞,∞)$ .

Answer 8

Expert Solution & Answer

To determine

The graph of the given quadratic function and also, the domain and range of the function.

Answer to Problem 1MCCP

Solution: The range of function $f$ is $[−4,∞)$ and the domain of the function is the set of all real number or $(−∞,∞)$ .

COLLEGE ALGEBRA-MYMATHLAB, Chapter 3, Problem 1MCCP , additional homework tip 1

Explanation of Solution

Given: The function is $f(x)=(x−3)2−4$ .

Comparing the provided equation $f(x)=(x−3)2−4$ to the standard parabolic equation $f(x)=a(x−h)2+k$ .

Where, $a=1,h=3,k=−4$ .

The vertex of the parabolic equation is $(h,k)=(3,−4)$ .

Determine the $x$ intercepts.

Put $f(x)=0$ .

$f(x)=(x−3)2−40=(x−3)2−4x−3=±2$

This implies that:

$x−3=±2$

For $+2$

$x−3=2x=5$

For $−2$

$x−3=−2x=1$

The $x$ intercept are $5$ and $1$ . And the parabola passes through the points $(5,0)$ and $(1,0)$ .

Now, to find the $y$ intercept, put $x=0$ .

$f(x)=(x−3)2−4=(0−3)2−4=9−4=5$

The $y$ intercept is $y=5$ and parabola passes through the point $(0,5)$ .

The graph of the parabola equation is shown below as:

COLLEGE ALGEBRA-MYMATHLAB, Chapter 3, Problem 1MCCP , additional homework tip 2

Now, compute the domain.

The $x$ axis on the graph corresponds to the domain of the function. In the graph it is clear that the domain of the function is the set of all real number or $(−∞,∞)$ .\

The range of the function is the output on the $y$ axis on the graph. Since, the vertex is -4, the points on $y$ axis fall at or above -4. Thus, the range of the function is $[−4,∞)$ .

Conclusion: The graph shows that the parabola’s vertex $(3,−4)$ is the lowest point. Thus, the range of function $f$ is $[−4,∞)$ and the domain of the function is the set of all real number or $(−∞,∞)$ .

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

To determine

The graph of the given quadratic function and also, the domain and range of the function.

Answer 12

Answer to Problem 1MCCP

Solution: The range of function $f$ is $[−4,∞)$ and the domain of the function is the set of all real number or $(−∞,∞)$ .

COLLEGE ALGEBRA-MYMATHLAB, Chapter 3, Problem 1MCCP , additional homework tip 1

Answer 13

Explanation of Solution

Given: The function is $f(x)=(x−3)2−4$ .

Comparing the provided equation $f(x)=(x−3)2−4$ to the standard parabolic equation $f(x)=a(x−h)2+k$ .

Where, $a=1,h=3,k=−4$ .

The vertex of the parabolic equation is $(h,k)=(3,−4)$ .

Determine the $x$ intercepts.

Put $f(x)=0$ .

$f(x)=(x−3)2−40=(x−3)2−4x−3=±2$

This implies that:

$x−3=±2$

For $+2$

$x−3=2x=5$

For $−2$

$x−3=−2x=1$

The $x$ intercept are $5$ and $1$ . And the parabola passes through the points $(5,0)$ and $(1,0)$ .

Now, to find the $y$ intercept, put $x=0$ .

$f(x)=(x−3)2−4=(0−3)2−4=9−4=5$

The $y$ intercept is $y=5$ and parabola passes through the point $(0,5)$ .

The graph of the parabola equation is shown below as:

COLLEGE ALGEBRA-MYMATHLAB, Chapter 3, Problem 1MCCP , additional homework tip 2

Now, compute the domain.

The $x$ axis on the graph corresponds to the domain of the function. In the graph it is clear that the domain of the function is the set of all real number or $(−∞,∞)$ .\

The range of the function is the output on the $y$ axis on the graph. Since, the vertex is -4, the points on $y$ axis fall at or above -4. Thus, the range of the function is $[−4,∞)$ .

Conclusion: The graph shows that the parabola’s vertex $(3,−4)$ is the lowest point. Thus, the range of function $f$ is $[−4,∞)$ and the domain of the function is the set of all real number or $(−∞,∞)$ .