Concept explainers
During meiosis I
- Homologous chromosomes synapse.
- Crossing over between homologous chromosomes occurs.
- the chromosomal number is reduced by half.
- the haploid cells are produced.
- All of these are correct.

Introduction:
The process of DNA replication is the process by which the genetic material of the organism copies itself to be distributed among the daughter cells during cell division. The DNA replication takes place before the cell division and prepares the cell for mitosis and meiosis. This process is followed by transcription and translation.
Answer to Problem 1RAC
The correct answer is option (e) all of these are correct.
Explanation of Solution
Explanation/justification for the correct answer:
Option (e) all of these are correct. The meiosis or the reductional division reduces the chromosome number in the two haploid cells by half and consists of crossing over at the synapse. So, the correct answer is option (e).
Explanation for incorrect answer:
Option (a) homologous chromosomes synapse. The meiotic division allows the recombination to occur between the homologous chromosomes at the synapse and allows the exchange of the genetic material, but that is not the only characteristic of meiosis. So, this is an incorrect option.
Option (b) crossing over between homologous chromosomes occurs. During meiosis, the crossing over takes place between the homologous chromosomes that allow the two chromosomes to exchange the genetic material, but that is not the only characteristic of meiosis. So, this is an incorrect answer.
Option (c) the chromosome number is reduced by half. The chromosome number is reduced to half from diploid cell to haploid gametes that give rise to diploid zygote, but that is not the only characteristic of meiosis. So, this is an incorrect answer.
Option (d) two haploid cells are produced. The diploid cell results in the production of two cells that are haploid in nature as the chromosome number is reduced to half during the meiotic divisions, but that is not the only characteristic of meiosis. So, this is an incorrect answer.
Want to see more full solutions like this?
Chapter 28 Solutions
SEELEY'S ANATOMY+PHYSIOLOGY
Additional Science Textbook Solutions
Campbell Essential Biology (7th Edition)
Biological Science (6th Edition)
Genetics: From Genes to Genomes
Campbell Biology in Focus (2nd Edition)
HUMAN ANATOMY
Applications and Investigations in Earth Science (9th Edition)
- Skryf n kortkuns van die Egyptians pyramids vertel ñ story. Maximum 500 woordearrow_forward1.)What cross will result in half homozygous dominant offspring and half heterozygous offspring? 2.) What cross will result in all heterozygous offspring?arrow_forward1.Steroids like testosterone and estrogen are nonpolar and large (~18 carbons). Steroids diffuse through membranes without transporters. Compare and contrast the remaining substances and circle the three substances that can diffuse through a membrane the fastest, without a transporter. Put a square around the other substance that can also diffuse through a membrane (1000x slower but also without a transporter). Molecule Steroid H+ CO₂ Glucose (C6H12O6) H₂O Na+ N₂ Size (Small/Big) Big Nonpolar/Polar/ Nonpolar lonizedarrow_forward
- what are the answer from the bookarrow_forwardwhat is lung cancer why plants removes liquid water intead water vapoursarrow_forward*Example 2: Tracing the path of an autosomal dominant trait Trait: Neurofibromatosis Forms of the trait: The dominant form is neurofibromatosis, caused by the production of an abnormal form of the protein neurofibromin. Affected individuals show spots of abnormal skin pigmentation and non-cancerous tumors that can interfere with the nervous system and cause blindness. Some tumors can convert to a cancerous form. i The recessive form is a normal protein - in other words, no neurofibromatosis.moovi A typical pedigree for a family that carries neurofibromatosis is shown below. Note that carriers are not indicated with half-colored shapes in this chart. Use the letter "N" to indicate the dominant neurofibromatosis allele, and the letter "n" for the normal allele. Nn nn nn 2 nn Nn A 3 N-arrow_forward
- I want to be a super nutrition guy what u guys like recommend mearrow_forwardPlease finish the chart at the bottom. Some of the answers have been filled in.arrow_forward9. Aerobic respiration of one lipid molecule. The lipid is composed of one glycerol molecule connected to two fatty acid tails. One fatty acid is 12 carbons long and the other fatty acid is 18 carbons long in the figure below. Use the information below to determine how much ATP will be produced from the glycerol part of the lipid. Then, in part B, determine how much ATP is produced from the 2 fatty acids of the lipid. Finally put the NADH and ATP yields together from the glycerol and fatty acids (part A and B) to determine your total number of ATP produced per lipid. Assume no other carbon source is available. 18 carbons fatty acids 12 carbons 9 glycerol A. Glycerol is broken down to glyceraldehyde 3-phosphate, a glycolysis intermediate via the following pathway shown in the figure below. Notice this process costs one ATP but generates one FADH2. Continue generating ATP with glyceraldehyde-3-phosphate using the standard pathway and aerobic respiration. glycerol glycerol-3- phosphate…arrow_forward
- Biology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStaxHuman Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage LearningBiology Today and Tomorrow without Physiology (Mi...BiologyISBN:9781305117396Author:Cecie Starr, Christine Evers, Lisa StarrPublisher:Cengage Learning
- Human Biology (MindTap Course List)BiologyISBN:9781305112100Author:Cecie Starr, Beverly McMillanPublisher:Cengage LearningHuman Physiology: From Cells to Systems (MindTap ...BiologyISBN:9781285866932Author:Lauralee SherwoodPublisher:Cengage Learning





