Modified Mastering Physics without Pearson eText-- Instant Access -- for Physics for Scientists & Engineers with Modern Physics
5th Edition
ISBN: 9780134402659
Author: GIANCOLI, Douglas
Publisher: PEARSON
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Chapter 25.4, Problem 1EE
To determine
Length of a wire with diameter
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3. By using the fact that around any closed loop the sum of the EMFS = the sum of the PDs. Write
equations for the two loops shown in the cct below.
40
ΔΩ
I₂
4V
(loop1
20 (loop2) 2v
I+12
Use these equations to show that the current flowing through the 20 resistor is 0.75A
5. A potential divider circuit is made by stretching a 1 m long wire with a resistance of 0.1 per cm
from A to B as shown.
8V
A
100cm
B
sliding contact
5Ω
A varying PD is achieved across the 5 Q resistor by moving the slider along the resistance wire.
Calculate the distance from A when the PD across the 5 Q resistor is 6 V.
4. A voltmeter with resistance 10 kQ is used to measure the pd across the 1 kQ resistor in the circuit
below.
6V
5ΚΩ
1ΚΩ
V
Calculate the percentage difference between the value with and without the voltmeter.
Chapter 25 Solutions
Modified Mastering Physics without Pearson eText-- Instant Access -- for Physics for Scientists & Engineers with Modern Physics
Ch. 25.2 - If 1 million electrons per second pass a point in...Ch. 25.2 - Prob. 1BECh. 25.3 - Return to the Chapter-Opening Question, page 651,...Ch. 25.4 - Prob. 1DECh. 25.4 - Prob. 1EECh. 25.4 - Prob. 1FECh. 25.4 - How many 60-W 120-V lightbulbs can operate on a...Ch. 25.6 - Each channel of a stereo receiver is capable of an...Ch. 25 - What quantity is measured by a battery rating...Ch. 25 - When an electric cell is connected to a circuit,...
Ch. 25 - When a flashlight is operated, what is being used...Ch. 25 - One terminal of a car battery is said to be...Ch. 25 - When you turn on a water faucet, the water usually...Ch. 25 - Can a copper wire and an aluminum wire of the same...Ch. 25 - The equation P = V2/R indicates that the power...Ch. 25 - What happens when a lightbulb burns out?Ch. 25 - If the resistance of a small immersion heater (to...Ch. 25 - Prob. 10QCh. 25 - Explain why lightbulbs almost always burn out just...Ch. 25 - Which draws more current, a 100-W lightbulb or a...Ch. 25 - Electric power is transferred over large distances...Ch. 25 - A 15-A fuse blows repeatedly. Why is it dangerous...Ch. 25 - When electric lights are operated on low-frequency...Ch. 25 - Driven by ac power, the same electrons pass back...Ch. 25 - The heating element in a toaster is made of...Ch. 25 - Is current used up in a resistor? Explain.Ch. 25 - Compare the drift velocities and electric currents...Ch. 25 - A voltage V is connected across a wire of length l...Ch. 25 - Why is it more dangerous to turn on an electric...Ch. 25 - Prob. 1PCh. 25 - Prob. 2PCh. 25 - Prob. 3PCh. 25 - Prob. 4PCh. 25 - Prob. 5PCh. 25 - Prob. 6PCh. 25 - Prob. 7PCh. 25 - Prob. 8PCh. 25 - Prob. 9PCh. 25 - Prob. 10PCh. 25 - Prob. 11PCh. 25 - Prob. 12PCh. 25 - Prob. 13PCh. 25 - Prob. 14PCh. 25 - Prob. 15PCh. 25 - (II) A rectangular solid made of carbon has sides...Ch. 25 - (III) A hollow cylindrical resistor with inner...Ch. 25 - Prob. 63GP
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- 1. A 9V battery with internal resistance 5 2 is connected to a 100 2 resistor. Calculate: a. the Power dissipated in the 100 2 resistor b. The heat generated per second inside the battery. C. The rate of converting chemical to electrical energy by the battery. 2. A 230 V kettle is rated at 1800 W. Calculate the resistance of the heating element.arrow_forward2. If each of the resistors in the circuit below has resistance R show that the total resistance between A and B is 5R/11 A Barrow_forward1. At 0°C a steel cable is 1km long and 1cm diameter when it is heated it expands and its resistivity increases. Calculate the change in resistance of the cable as it is heated from 0-20°C The temperature coefficient of resistance a, gives the fractional increase in resistance per °C. So increase in resistance AR = Ra.AT Where R, is the resistance at 0°C For steel a, 0.003 °C The coefficient of linear expansion a- gives the fractional increase in length per °C temperature rise. So increase in Length AL La-AT Where L, is the length at 0°C For steel a₁ = 12 x 10 °C-1 The resistivity of steel at 0°C = 1.2 x 10 Qmarrow_forward
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