![Prescott's Microbiology](https://www.bartleby.com/isbn_cover_images/9781259281594/9781259281594_largeCoverImage.gif)
Concept explainers
Protist encystment is usually triggered by changes in the environment. Compare and contrast this with endospore formation in Gram-positive bacteria.
![Check Mark](/static/check-mark.png)
A microbial cyst is a dormant or resting stage of microorganism, generally a protist or bacterium or rarely an invertebrate animal. It assists the organism to live in an unfavourable environment. Several protists are capable of encystment. The morphology of an organism becomes simpler and it matures into a resting stage is called cyst.
Explanation of Solution
Encystment also assists the microbes to easily disperse from one host to another host and to favourable environmental conditions.
Comparison:
Generally, both encystment and endospore formation are triggered by starvation. Additionally, both cysts and endospores have strong and thick cell walls, low or no metabolic rate and it can live in harsh environments.
Contrast:
The formation of endospore takes place within the female gametophyte and it only disperses after the death of gametophyte. In encystment, any cell death cannot be caused by cell but it survives over unfavourable conditions. When compared to Gram-positive spores, the cysts of protist are less resistant to long environmental stress.
Want to see more full solutions like this?
Chapter 25 Solutions
Prescott's Microbiology
- , if one of the archaeological specimens lacked the celiac disease-causing epitope, how could PCR be used to identify the allele in a contemporary germplasm collection of wild wheats, and to assist in transferring the allele to modern wheat varieties?arrow_forwardNow you will consider the composition of lipoproteins, including where they are synthesized, how they circulate, and where the various lipid and protein components are located within the lipoprotein molecule. Drag the appropriate labels to their respective targets.arrow_forwardThe Oregon Wolfe Barley mapping population is unique in having 12 easily-scored morphological markers, each showing monogenic inheritance. Do you consider these markers useful? Briefly defend your answer, pointing out advantages and disadvantages of morphological vs. molecular markers.arrow_forward
- Biopharmaceutics and Pharmacokinetics:Two-Compartment Model Instant Absorption Questions Calculate these : a) B1, b) B2, c) hybrid rate constant (1) d) hybrid rate constant (2) e) t1/2,dist f) t1/2,elim g) k10 h) k12 i) k21 j) initial concentration (C0) k) central compartment volume (V1) l) steady-state volume (Vss) m) clearance (CL) AUC (0→10 min) using trapezoidal rule n) AUC (20→30 min) using trapezoidal rule o) AUCtail (AUC360→∞) p) total AUC (using short cut method) q) volume from AUC (VAUC)arrow_forwardIn a population of Jackalopes (pictured below), horn length will vary between 0.5 and 2 feet, with the mean length somewhere around 1.05 feet. You pick Jackalopes that have horn lengths around 1.75 feet to breed as this appears to be the optimal length for battling other Jackalopes for food. After a round of breeding, you measure the offsprings' mean horn length is 1.67. What is the heritability of horns length (h2)? Is Jackalope horn length a heritable trait? (4 pts)? 12pt v R Paragraph V BIU A श्र > Barrow_forwardThere are many differences between DNA replication happening during mitosis in a Douglas fir tree growing in the Oregon Cascade Mountains and DNA replication happening during a PCR reaction in a forestry research lab at Oregon State University where the laboratory is amplifying a Simple Sequence Repeat. Complete the following table that compares the two DNA replication events in terms of the primers, the nucleotides, the polymerase, and the target sequence. Additionally, give a general value for the number of copies of the template DNA after one S phase in one cell and after the lab has completed the PCR reaction. Tree SSR Type your answer here: Primers Nucleotides Polymerase Target sequence Number of copiesarrow_forward
- Describe how insulin binding to its receptor induces glucose uptake in healthy individuals. Please specifyeach step in the cascade and use a diagram to illustrate the answer.arrow_forwardThere is a patient with breast cancer, after staining the breast tissue with H&E, state the molecular subtype of the tumour extracted. Results of H&E staining are down belowarrow_forwardBiopharmaceutics and Pharmacokinetics:Two-Compartment Model Instant Absorption Questions Calculate these : a) B1, b) B2, c) hybrid rate constant (1) d) hybrid rate constant (2) e) t1/2,dist f) t1/2,elim g) k10 h) k12 i) k21 j) initial concentration (C0) k) central compartment volume (V1) l) steady-state volume (Vss) m) clearance (CL) AUC (0→10 min) using trapezoidal rule n) AUC (20→30 min) using trapezoidal rule o) AUCtail (AUC360→∞) p) total AUC (using short cut method) q) volume from AUC (VAUC)arrow_forward
- Use the Henderson-Hasselbalch equation for a propanoic acid solution (CH₂CH₂CO₂H, pK₁ = 4.874) to calculate the quotient [A-]/[HA] at three different pH values. pH = 4.479 [A-] [HA] [A-] pH = 4.874 [HA] = pH = 5.220 [A-] = [HA]arrow_forwardIn order to establish the expiration date of perishable food, growth curve data must be collected. Once the microbial load is so high that it poses a hazard to human health, the food item is no longer considered safe (expired). Generally a load of x50,000 bacteria/gram is considered unsafe. Your task is to determine the microbial growth curves for MicroYo, a new brand of yogurt. The growth is determined by sampling the yogurt and growing the bacterial isolates in broth culture which is then serially diluted by a total of x10,000 and inoculated onto standard petri plates of nutrient agar. The following colony counts are measured: Time (days) MicroYo colony count# 1 1 4 1 12 2 16 20 4 7 What day should you recommend expiring the yogurt (the last possible date before the microbial load is unsafe). 12 4 20 16arrow_forward9. Chicken combs in chickens is an example where you see interactions between genes. See potential genotypes and phenotypes below. Which genotype, when mated to a rose comb chicken, will produce progeny that are 50% walnut comb and 50% pea comb? walnut (RRPP) walnut (RrPP) pea (rrPP) walnut (RRPP) walnut (RrPp) pea (rrPp) rose rose single (RRPP) (Rrpp) (rrpp)arrow_forward
- Basic Clinical Lab Competencies for Respiratory C...NursingISBN:9781285244662Author:WhitePublisher:CengageConcepts of BiologyBiologyISBN:9781938168116Author:Samantha Fowler, Rebecca Roush, James WisePublisher:OpenStax College
- Medical Terminology for Health Professions, Spira...Health & NutritionISBN:9781305634350Author:Ann Ehrlich, Carol L. Schroeder, Laura Ehrlich, Katrina A. SchroederPublisher:Cengage LearningBiology Today and Tomorrow without Physiology (Mi...BiologyISBN:9781305117396Author:Cecie Starr, Christine Evers, Lisa StarrPublisher:Cengage LearningBiology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStax
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305967359/9781305967359_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781938168116/9781938168116_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305634350/9781305634350_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305117396/9781305117396_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781947172517/9781947172517_coverImage_Textbooks.gif)