Numerical Analysis
10th Edition
ISBN: 9781305730663
Author: Richard L. Burden; J. Douglas Faires; Annette M. Burden
Publisher: Cengage Learning US
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Listed in the accompanying table are weights (kg) of randomly selected U.S. Army male personnel measured in 1988 (from "ANSUR I 1988") and different weights (kg) of randomly selected U.S.
Army male personnel measured in 2012 (from "ANSUR II 2012"). Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not
assume that the population standard deviations are equal. Complete parts (a) and (b).
Click the icon to view the ANSUR data.
a. Use a 0.05 significance level to test the claim that the mean weight of the 1988…
Math Test
3 3
x³+y³ =
Ꭹ = 9
2 2
x²+y² = 5
x+y=?
For each of the following series, determine whether the absolute convergence series test
determines absolute convergence or fails. For the ¿th series, if the test is inconclusive then let
Mi = 4, while if the test determines absolute convergence let Mi
1 :
2:
∞
Σ(−1)"+¹ sin(2n);
n=1
Σ
n=1
Σ
((−1)”.
COS
n²
3+2n4
3: (+
4:
5 :
n=1
∞
n
2+5n3
ПП
n²
2 5+2n3
пп
n²
Σ(+)+
n=1
∞
n=1
COS
4
2 3+8n3
П
ηπ
n-
(−1)+1 sin (+727) 5 + 2m³
4
= 8.
Then the value of cos(M₁) + cos(2M2) + cos(3M3) + sin(2M) + sin(M5) is
-0.027
-0.621
-1.794
-1.132
-1.498
-4.355
-2.000
2.716
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- No it is not a graded assignment, its a review question but i only have the final answer not the working or explanationarrow_forwardsolving problem 1arrow_forwardClass, the class silues, and the class notes, whether the series does alternate and the absolute values of the terms decrease), and if the test does apply, determine whether the series converges or diverges. For the ith series, if the test does not apply the let Mi = 2, while if the test determines divergence then M¿ = 4, and if it determines convergence then M¿ = 8. 1: 2: 3 : 4: 5 : ∞ n=1 ∞ (−1)n+1. Σ(-1) +1 n=1 ∞ п 3m² +2 Σ(-1)+1 sin(2n). n=1 ∞ 2n² + 2n +3 4n2 +6 1 e-n + n² 3n23n+1 9n² +3 In(n + 1) 2n+1 Σ(-1) +1 n=1 ∞ Σ(-1)". n=1 Then the value of cos(M₁) + cos(2M2) + cos(3M3) + sin(2M4) + sin(M5) is 1.715 0.902 0.930 -1.647 -0.057 ● 2.013 1.141 4.274arrow_forward
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