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L₁ D₁ L₂ D2 Aluminum has a resistivity of p = 2.65 × 10 8 2. m. An aluminum wire is L = 2.00 m long and has a circular cross section that is not constant. The diameter of the wire is D₁ = 0.17 mm for a length of L₁ = 0.500 m and a diameter of D2 = 0.24 mm for the rest of the length. a) What is the resistance of this wire? R = Hint A potential difference of AV = 1.40 V is applied across the wire. b) What is the magnitude of the current density in the thin part of the wire? Hint J1 = c) What is the magnitude of the current density in the thick part of the wire? J₂ = d) What is the magnitude of the electric field in the thin part of the wire? E1 = Hint e) What is the magnitude of the electric field in the thick part of the wire? E2 =
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A cheetah spots a gazelle in the distance and begins to sprint from rest, accelerating uniformly at a rate of 8.00 m/s^2 for 5 seconds. After 5 seconds, the cheetah sees that the gazelle has escaped to safety, so it begins to decelerate uniformly at 6.00 m/s^2 until it comes to a stop.

Chapter 24 Solutions

Modified Mastering Physics With Pearson Etext -- Standalone Access Card -- For Physics For Scientists & Engineers With Modern Physics (5th Edition)

Ch. 24 - Suppose three identical capacitors are connected...Ch. 24 - A large copper sheet of thickness is placed...Ch. 24 - The parallel plates of an isolated capacitor carry...Ch. 24 - If the voltage across a capacitor is doubled, the...Ch. 24 - An isolated charged capacitor has horizontal...Ch. 24 - Suppose a battery remains connected to the...Ch. 24 - How does the energy stored in a capacitor change...Ch. 24 - For dielectrics consisting of polar molecules, how...Ch. 24 - A dielectric is pulled out from between the plates...Ch. 24 - We have seen that the capacitance C depends on the...Ch. 24 - What value might we assign to the dielectric...Ch. 24 - Prob. 5MCQCh. 24 - Prob. 6MCQCh. 24 - Prob. 9MCQCh. 24 - Prob. 11MCQCh. 24 - Prob. 12MCQCh. 24 - Prob. 13MCQCh. 24 - Prob. 1PCh. 24 - Prob. 2PCh. 24 - Prob. 3PCh. 24 - Prob. 4PCh. 24 - Prob. 5PCh. 24 - Prob. 6PCh. 24 - Prob. 7PCh. 24 - Prob. 8PCh. 24 - Prob. 9PCh. 24 - Prob. 10PCh. 24 - Prob. 11PCh. 24 - Prob. 12PCh. 24 - Prob. 13PCh. 24 - Prob. 14PCh. 24 - Prob. 15PCh. 24 - Prob. 16PCh. 24 - Prob. 17PCh. 24 - Prob. 18PCh. 24 - Prob. 19PCh. 24 - Prob. 20PCh. 24 - Prob. 21PCh. 24 - Prob. 22PCh. 24 - Prob. 24PCh. 24 - Prob. 25PCh. 24 - Prob. 26PCh. 24 - Prob. 27PCh. 24 - Prob. 28PCh. 24 - Prob. 29PCh. 24 - Prob. 31PCh. 24 - Prob. 32PCh. 24 - Prob. 33PCh. 24 - Prob. 34PCh. 24 - Prob. 35PCh. 24 - Prob. 36PCh. 24 - Prob. 37PCh. 24 - Prob. 38PCh. 24 - Prob. 39PCh. 24 - Prob. 40PCh. 24 - Prob. 41PCh. 24 - Prob. 42PCh. 24 - Prob. 43PCh. 24 - Prob. 44PCh. 24 - Prob. 45PCh. 24 - Prob. 49PCh. 24 - Prob. 53PCh. 24 - Prob. 54PCh. 24 - Prob. 57PCh. 24 - Prob. 58PCh. 24 - (II) Two different dielectrics fill the space...Ch. 24 - (II) Repeat Problem 60 (Fig. 2431) but assume the...Ch. 24 - Prob. 63PCh. 24 - Prob. 76GPCh. 24 - Prob. 84GPCh. 24 - Prob. 87GP
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