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Chapter 24, Problem 1Q

Suppose two nearby conductors carry the same negative charge. Can there be a potential difference between them? If so, can the definition of capacitance, C = Q/V, be used here?

Expert Solution & Answer
Check Mark
To determine

If two nearby conductors carry the same negative charges means does it carry the potential difference between them, if so capacitance can be used here.

Answer to Problem 1Q

Yes, there will be potential difference between the two nearby conductors carry the same negative charges, and definition of capacitance cannot be used here.

Explanation of Solution

Suppose two nearby conductors carry same charges, there would be potential difference because they have different charge densities. When they have same amount with same sign charges then there would zero potential difference.

So, that the definition of capacitance C=Q/V cannot be used because for the case of capacitance both conductors should have same amount but opposite charges.

Conclusion:

Yes, there will be potential difference between the two nearby conductors carry the same negative charges, and definition of capacitance cannot be used here.

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Chapter 24 Solutions

Modified Mastering Physics With Pearson Etext -- Standalone Access Card -- For Physics For Scientists & Engineers With Modern Physics (5th Edition)

Ch. 24 - Suppose three identical capacitors are connected...Ch. 24 - A large copper sheet of thickness is placed...Ch. 24 - The parallel plates of an isolated capacitor carry...Ch. 24 - If the voltage across a capacitor is doubled, the...Ch. 24 - An isolated charged capacitor has horizontal...Ch. 24 - Suppose a battery remains connected to the...Ch. 24 - How does the energy stored in a capacitor change...Ch. 24 - For dielectrics consisting of polar molecules, how...Ch. 24 - A dielectric is pulled out from between the plates...Ch. 24 - We have seen that the capacitance C depends on the...Ch. 24 - What value might we assign to the dielectric...Ch. 24 - Prob. 5MCQCh. 24 - Prob. 6MCQCh. 24 - Prob. 9MCQCh. 24 - Prob. 11MCQCh. 24 - Prob. 12MCQCh. 24 - Prob. 13MCQCh. 24 - Prob. 1PCh. 24 - Prob. 2PCh. 24 - Prob. 3PCh. 24 - Prob. 4PCh. 24 - Prob. 5PCh. 24 - Prob. 6PCh. 24 - Prob. 7PCh. 24 - Prob. 8PCh. 24 - Prob. 9PCh. 24 - Prob. 10PCh. 24 - Prob. 11PCh. 24 - Prob. 12PCh. 24 - Prob. 13PCh. 24 - Prob. 14PCh. 24 - Prob. 15PCh. 24 - Prob. 16PCh. 24 - Prob. 17PCh. 24 - Prob. 18PCh. 24 - Prob. 19PCh. 24 - Prob. 20PCh. 24 - Prob. 21PCh. 24 - Prob. 22PCh. 24 - Prob. 24PCh. 24 - Prob. 25PCh. 24 - Prob. 26PCh. 24 - Prob. 27PCh. 24 - Prob. 28PCh. 24 - Prob. 29PCh. 24 - Prob. 31PCh. 24 - Prob. 32PCh. 24 - Prob. 33PCh. 24 - Prob. 34PCh. 24 - Prob. 35PCh. 24 - Prob. 36PCh. 24 - Prob. 37PCh. 24 - Prob. 38PCh. 24 - Prob. 39PCh. 24 - Prob. 40PCh. 24 - Prob. 41PCh. 24 - Prob. 42PCh. 24 - Prob. 43PCh. 24 - Prob. 44PCh. 24 - Prob. 45PCh. 24 - Prob. 49PCh. 24 - Prob. 53PCh. 24 - Prob. 54PCh. 24 - Prob. 57PCh. 24 - Prob. 58PCh. 24 - (II) Two different dielectrics fill the space...Ch. 24 - (II) Repeat Problem 60 (Fig. 2431) but assume the...Ch. 24 - Prob. 63PCh. 24 - Prob. 76GPCh. 24 - Prob. 84GPCh. 24 - Prob. 87GP
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