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Interpretation:
The difference in the dipole moment of two similar molecules of N;
Concept introduction:
VSEPR is the theory purposed to explain the geometry of those molecules mainly which have lone pairs on the central atom as due to presence of lone pair and bond pairs, the repulsion plays important role in the determination of molecular geometry of the molecule. According to VSEPR theory, the lone pair-bond pair repulsion determines the molecular geometry of the molecules and geometry determines the dipole moment of the molecule. Dipole moment is the product of charge and distance between bonded atoms. Electronegativity of bonded atoms determines the direction as well as magnitude of dipole moment.
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Chapter 22 Solutions
GENERAL CHEMISTRY(LL)-W/MASTERINGCHEM.
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- I have a excitation/emission spectra of a quinine standard solution here, and I'm having trouble interpreting it. the red line is emission the blue line is excitation. i'm having trouble interpreting properly. just want to know if there is any evidence of raman or rayleigh peaks in the spectra.arrow_forwardGive the major product of the following reaction. excess 1. OH, H₂O 1.OH H CH3CH2CH21 H 2. A.-H₂O Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default.arrow_forward2. Use Hess's law to calculate the AH (in kJ) for: rxn CIF(g) + F2(g) → CIF 3 (1) using the following information: 2CIF(g) + O2(g) → Cl₂O(g) + OF 2(g) AH = 167.5 kJ ΔΗ 2F2 (g) + O2(g) → 2 OF 2(g) 2C1F3 (1) + 202(g) → Cl₂O(g) + 3 OF 2(g) о = = -43.5 kJ AH = 394.1kJarrow_forward
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