Bundle: Modern Business Statistics with Microsoft Office Excel, Loose-Leaf Version, 6th + MindTap Business Statistics, 2 terms (12 months) Printed Access Card
6th Edition
ISBN: 9781337589383
Author: David R. Anderson, Dennis J. Sweeney, Thomas A. Williams, Jeffrey D. Camm, James J. Cochran
Publisher: Cengage Learning
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Textbook Question
Chapter 2.1, Problem 5E
In alphabetical order, the six most common last names in the United States are Brown, Johnson, Jones, Miller, Smith, and Williams (The World Almanac, 2012). Assume that a sample of 50 individuals with one of these last names provided the following data.
Summarize the data by constructing the following:
- a. Relative and percent frequency distributions
- b. A bar chart
- c. A pie chart
- d. Based on these data, what are the three most common last names?
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THE QUESTION:
Set up a free RStudio account at posit.cloud. At the start of your R session, you should enter the following commands.
set.seed(1)
e<-rnorm(n = 100,mean = 0,sd = 80)
x<-seq(1,100,1)
y<-10+15*x + e
Follow the examples in the Panopto Videos to use R to obtain the values requested below. (As always, if you round your answers, make sure you do so correctly and keep at least
three decimal places.)
(a) The smallest value of y =
(b) The largest value of y =
(c) The standard deviation of y =
(d) The mean of y =
(e) The median of y =
(f) The correlation between x and y =
(g) Using the variable e as data, the p-value for a test of Ho = 0 vs. Hд μ0 is
ANSWERS I HAVE TRIED
THAT ARE NOT CORRECT ↓
Answer Preview
(BESIDES F, F IS CORRECT)
(A)
-104.123
(B)
1545.84
(C)
448.543
(D)
752.347
(E)
775.533
(F)
(G)
0.987
0.497
PLEASSSEEE DO NOT GIVE ME
BACK THE SAME ANSWERS
THAT I HAVE SAID ARE WRONG
Result
incorrect
incorrect
incorrect
incorrect
incorrect
correct
incorrect
3:23
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1 of 2
UMCISI
mville.brightspace.com
onomic Statistics
our grade, can be done as a 2 people's group)
-
Due date Sunday, 12/08/202 through Brightspace portal.
College students' physical, emotional, and mental health are at the forefront of many national
discussions and statistical studies. Many factors can influence students' overall health,
including diet, sleep, exercise, social media usage, etc. In this project, you will look at real data
gathered from 30 college students and determine related descriptive and inferential statistics.
Please use MS Excel (see attached file) to collect your data and complete the assignment.
The students surveyed were asked the following questions:
On a typical weekday,
Are you an on-campus student or a commuter?
How many hours of sleep do you get?
How many hours do you study?
How many calories do you intake?
How many hours do you exercise?
How many hours do you spend on social media?
How many hours do you spend with your friends and family…
Is the area to the right of the left-tail critical value Chi-squared(1-alpha) of the chi-squared distribution always (1-alpha), and is the area to the left of this critical value always alpha? Does this apply to all chi-squared distributions?Please see image attached
Chapter 2 Solutions
Bundle: Modern Business Statistics with Microsoft Office Excel, Loose-Leaf Version, 6th + MindTap Business Statistics, 2 terms (12 months) Printed Access Card
Ch. 2.1 - Methods
1. The response to a question has three...Ch. 2.1 - 2. A partial relative frequency distribution is...Ch. 2.1 - A questionnaire provides 58 Yes, 42 No, and 20...Ch. 2.1 -
For the 2010–2011 viewing season, the top five...Ch. 2.1 -
In alphabetical order, the six most common last...Ch. 2.1 - Top Rated Television Show Networks. Nielsen Media...Ch. 2.1 - Airline Customer Satisfaction Survey. Many...Ch. 2.1 - Prob. 8ECh. 2.1 - Prob. 9ECh. 2.1 -
VirtualTourist provides ratings for hotels...
Ch. 2.2 - 11. Consider the following data.
Develop a...Ch. 2.2 - 12. Consider the following frequency...Ch. 2.2 - Construct a histogram for the data in exercise...Ch. 2.2 - Prob. 14ECh. 2.2 - Construct a stem-and-leaf display for the...Ch. 2.2 - Construct a stem-and-leaf display for the...Ch. 2.2 - Applications
17. A doctor’s office staff studied...Ch. 2.2 - NBA Total Player Ratings. CBSSports.com developed...Ch. 2.2 - Prob. 19ECh. 2.2 - CEO Time in Meetings. The London School of...Ch. 2.2 - Quantcast.com provides the number of people from...Ch. 2.2 - Top U.S. Franchises. Entrepreneur magazine ranks...Ch. 2.2 - Prob. 24ECh. 2.2 - Best Paying College Degrees. Each year America.EDU...Ch. 2.2 - Prob. 26ECh. 2.3 - The following data are for 30 observations...Ch. 2.3 - The following observations are for two...Ch. 2.3 - Daytona 500 Automobile Makes Average Speeds. The...Ch. 2.3 - Daytona 500 Average Speeds of Winners. The...Ch. 2.3 - 31. Recently, management at Oak Tree Golf Course...Ch. 2.3 - Household Income Levels. The following...Ch. 2.3 - 33. Each year Forbes ranks the world’s most...Ch. 2.3 - Prob. 34ECh. 2.3 -
The U.S. Department of Energy's Fuel Economy...Ch. 2.4 - The following 20 observations are for two...Ch. 2.4 - Prob. 37ECh. 2.4 - The following crosstabulation summarizes the data...Ch. 2.4 - Driving Speed and Fuel Efficiency. A study on...Ch. 2.4 - The DATAfile Snow contains average annual snowfall...Ch. 2.4 - Hypertension and Heart Disease. People often wait...Ch. 2.4 -
Smartphones are mobile phones with Internet,...Ch. 2.4 - Store Managers Time Study. The Northwest regional...Ch. 2 - SAT Scores. The SAT is a standardized test used by...Ch. 2 - Median Household Incomes. The file MedianHousehold...Ch. 2 - State Populations. Data showing the population by...Ch. 2 - Startup Company Funds. According to the Wall...Ch. 2 - Complaints Reported to BBB. Consumer complaints...Ch. 2 - Stock Price Volatility. The term “beta” refers to...Ch. 2 - Education Level and Household Income. The U.S....Ch. 2 - Prob. 51SECh. 2 - Best Places to Work. Fortune magazine publishes an...Ch. 2 - Prob. 53SECh. 2 - Prob. 54SECh. 2 - Prob. 55SECh. 2 - Prob. 56SECh. 2 -
Google has changed its strategy with regard to...Ch. 2 -
A zoo has categorized its visitors into three...Ch. 2 - Pelican Stores, a division of National Clothing,...Ch. 2 -
Motion Picture Industry
The motion picture...Ch. 2 - Cincinnati, Ohio, also known as the Queen City,...Ch. 2 - Jon Weideman, first shift foreman for Cut-Rate...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.Similar questions
- Set up a free RStudio account at posit.cloud. At the start of your R session, you should enter the following commands. set.seed(1) e<-rnorm(n = 100,mean = 0,sd = 80) x<-seq(1,100,1) y<-10+15*x + e Follow the examples in the Panopto Videos to use R to obtain the values requested below. (As always, if you round your answers, make sure you do so correctly and keep at least three decimal places.) (a) The smallest value of y = (b) The largest value of y = (c) The standard deviation of y = (d) The mean of y = (e) The median of y = (f) The correlation between x and y = : (g) Using the variable e as data, the p-value for a test of Hoμ = 0 vs. HA μ0 isarrow_forwardDoes Chi-squared(alpha) always represent the right tail of the the chi-square distribution and does Chi-squared(1-alpha) always represent the left tail of the the chi-square distribution. Also, for a standard normal distribution would Z(1-alpha) be equivalent to -Zalpha in represneting the left tail of the standard normal distribution curve because they both have the same z-score. Furthermore, is my understanding correct in the sense that if we have a critical value,say Zalpha, would the area to the right of it will be alpha and to the left of it would be 1-alphaarrow_forwardOne bulb manufacturer claims an average bulb life of 1,600 hours. It is suspected that the actual average is significantly lower. To verify this, a sample of 49 bulbs is selected and the life of each bulb is measured. A sample mean of 1,500 hours and a standard deviation of 120 hours were obtained from them. Can you be sure, at 5% significance, that the mean life is less than what the manufacturer claims?arrow_forward
- The specification calls for the dimension of a certain mechanical part to be 0.55 inches. A random sample of 35 parts taken from a large batch showed a mean 0.54 in. with a deviation of 0.05 in. Can it be concluded, at 1% significance, that the batch of parts meets the required specification?arrow_forwardA manufacturer produces a wire rope of a certain type, which has a breaking strength of not more than 300 kg. A new and cheaper process is discovered which is desired to be employed, provided that the wire rope thus produced has an average breaking strength greater than 300 kg. If a random sample of 26 wires produced with the new process has given a mean of 304.5 kg and a standard deviation of 15 kg, should the manufacturer adopt the new process?arrow_forwardWe are interested in whether the proportions of female suicide victims for ages 15 to 24 are the same between the white and the black races in the United States. We randomly pick one year to compare the races. The number of suicides estimated in the United States in that year for white females is 4,930. Five hundred eighty-three were aged 15 to 24. The estimate for black females is 330. Forty-one were aged 15 to 24. We will let female suicide victims be our population. (Use α = 0.05.) NOTE: If you are using a Student's t-distribution for the problem, including for paired data, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.) Part (a) State the null hypothesis. ○ Ho: PW> PB O Ho: PW + PB Ho: Pw≤ PB Ho: PW-PB ○ Ho: Pw PB Part (c) In words, state what your random variable P'w-P'B represents. P'w-P'B represents the average difference of white and black female suicide victims, aged 15 to 24. ○ P'w-P'B…arrow_forward
- please solve this problem step by step and make it quick pleasearrow_forwardplease solve this problem step by step and make it quick pleasearrow_forward8.67 Free recall memory strategy. Psychologists who study ①memory often use a measure of "free recall" (e.g., the RECALL number of correctly recalled items in a list of to-be- remembered items). The strategy used to memorize the list-for example, category clustering-is often just as important. Researchers at Central Michigan University developed an algorithm for computing measures of cat- egory clustering in Advances in Cognitive Psychology (Oct. 2012). One measure, called ratio of repetition, was recorded for a sample of 8 participants in a memory study. These ratios are listed in the table. Test the theory that the average ratio of repetition for all participants in a similar memory study differs from .5. Select an appropriate Type I error rate for your test. .25 .43 .57 .38 .38 .60 .47 .30 Source: Senkova, O., & Otani, H. "Category clustering calculator for free recall." Advances in Cognitive Psychology, Vol. 8, No. 4, Oct. 2012 (Table 3).arrow_forward
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