Chapter 20, Problem 36P

Repeat 1.3-9 but use the method of sections go find member forces in AC and BD.

Solve the preceding problem for the element shown in the figure.

Beam AB has a pin support at A and a roller support at B Joint B is also restrained by a linearly elastic rotational spring with stiffness kR, which provides a resisting moment MBdue to rotation at B. Member AB has flexural rigidity EI. A moment M0acts counterclockwise at B. Use the method of superposition to solve for all reactions. Find an expression for joint rotation Ain terms of spring stiffness kR. What is Awhen kR 0? What is Awhen kR— ? What is Awhen kR= 6EI/L?

The inclined ladder AB supports a house painter (85 kg) at C and the weight iq = 40 K/m} of the ladder itself. Each ladder rail (t5= 4 mm) is supported by a shoe (ts= 5 mm) that is attached to the ladder rail by a bolt of diameter d = 8 mm

Repeat Problem 9,5-15 for the anti-symmetric loading shown in the figure.

Pipe 2 has been inserted snugly into Pipe I. but the holes Tor a connecting pin do not line up; there is a gap s. The user decides to apply either force P:lo Pipe I or force P-, to Pipe 2, whichever is smaller. Determine the following using the numerical properties in the box. (a) If only P{is applied, find Pt{tips} required to close gap s; if a pin is then inserted and Ptremoved, what are reaction forces RAand RBfor this load case? (b) If only P2is applied, find P2{kips) required to close gap a; if a pin is inserted and P2removed, what are reaction forces R^ and RBfor this load case? (c) What is the maximum shear stress in the pipes, for the loads in parts (a) and (b)? (d) If a temperature increase IT is to be applied to the entire structure to close gaps{instead of applying forces Ptand P2), find the AT required to close the gap. If a pin is inserted after the gaphas closed, what are reaction forces .''.', and RBfor this case? (e) Finally, if the structure (with pin inserted) then cools to the original ambient temperature, what are reaction forces Rtand P

Show your complete solution and put whether it is clockwise (+) or counterclockwise (-) and if to the left or to the right. Also, draw again the figure. Thank you

5 - note: ignore weight of the bar.A) ( - 6/7)T(CB) + A(y)=0 (A=reaction force at A, A(x), A(y), A(z) are components of force A)B) (2/7)T(CB)+A(x)=392 (A=reaction force at A, A(x), A(y), A(z) are components of force A)C) A(x)=2A(y) (A=reaction force at A, A(x), A(y), A(z) are components of force A)D) A(x)=5A(z) (A=reaction force at A,A(x), A(y), A(z) are components of force A)

B1