Mass spectrometry is one of the most versatile and powerful tools chemical analysis because of its capacity to discriminate between atoms of different masses. When a sample containing a mixture of isotopes is introduced into a mass spectrometer, the ratio of the peaks observed reflects the ratio of the percent isotopic abundances . This ratio provides an internal standard from which the amount of a certain isotope present in a sample can be determined. This is accomplished by deliberately introducing a known quantity of a particular isotope into the sample to be analyzed. A comparison of the new isotope ratio to the first ratio allows the determination of the amount of the isotope present in the original sample. An analysis was done on a rock sample to determine its rubidium content. The rubidium content of a portion of rock weighing 0.350 g was extracted, and to the extracted sample was added an additional 29.45 μg of 27 Rb . The mass spectrum of this speed sample showed a 2 7 Rb peak that was 1.12 times as high as the peak for 27 Rb . Assuming that the two isotopes react identically, what is the Rb content of the rock (expressed in parts per minion by mass)? The isotopic abundances and isotopic messes are shown in the table.
Mass spectrometry is one of the most versatile and powerful tools chemical analysis because of its capacity to discriminate between atoms of different masses. When a sample containing a mixture of isotopes is introduced into a mass spectrometer, the ratio of the peaks observed reflects the ratio of the percent isotopic abundances . This ratio provides an internal standard from which the amount of a certain isotope present in a sample can be determined. This is accomplished by deliberately introducing a known quantity of a particular isotope into the sample to be analyzed. A comparison of the new isotope ratio to the first ratio allows the determination of the amount of the isotope present in the original sample. An analysis was done on a rock sample to determine its rubidium content. The rubidium content of a portion of rock weighing 0.350 g was extracted, and to the extracted sample was added an additional 29.45 μg of 27 Rb . The mass spectrum of this speed sample showed a 2 7 Rb peak that was 1.12 times as high as the peak for 27 Rb . Assuming that the two isotopes react identically, what is the Rb content of the rock (expressed in parts per minion by mass)? The isotopic abundances and isotopic messes are shown in the table.
Solution Summary: The author explains the rubidium content of the rock based on its mass spectrometry analysis needs to be determined.
Mass spectrometry is one of the most versatile and powerful tools chemical analysis because of its capacity to discriminate between atoms of different masses. When a sample containing a mixture of isotopes is introduced into a mass spectrometer, the ratio of the peaks observed reflects the ratio of the percent isotopic abundances. This ratio provides an internal standard from which the amount of a certain isotope present in a sample can be determined. This is accomplished by deliberately introducing a known quantity of a particular isotope into the sample to be analyzed. A comparison of the new isotope ratio to the first ratio allows the determination of the amount of the isotope present in the original sample. An analysis was done on a rock sample to determine its rubidium content. The rubidium content of a portion of rock weighing 0.350 g was extracted, and to the extracted sample was added an additional 29.45 μg of
27
Rb
. The mass spectrum of this speed sample showed a 27Rb peak that was 1.12 times as high as the peak for
27
Rb
. Assuming that the two isotopes react identically, what is the Rb content of the rock (expressed in parts per minion by mass)? The isotopic abundances and isotopic messes are shown in the table.
sketch the nature of the metal-alkylidene bonding interactions.
Part C
The perspective formula of isoleucine, an amino acid, is provided below.
HOOC
H₂NIC
H
川
CH3
CH,CH3
Draw the Newman projection in staggered conformation for isoleucine by viewing the molecule along the
C-2-C-3 bond.
1. Edit the Newman projection on the canvas.
2. Replace the appropriate hydrogens with the appropriate -CH3 or other groups.
3. If you need to start over, Undo or choose a Newman projection from the Templates toolbar
(bottom).
Important: Never delete the hydrogen atoms or bonds directly attached to the template, and do not move
them by dragging or dropping them. That will break the projections structures. Only replace them!
▸ View Available Hint(s)
0 2
H± 3D
EXP.
L
ד
י
CONT. 2
H
0
N
о
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Atomic Number, Atomic Mass, and the Atomic Structure | How to Pass ChemistryThe Nucleus: Crash Course Chemistry #1; Author: Crash Course;https://www.youtube.com/watch?v=FSyAehMdpyI;License: Standard YouTube License, CC-BY