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To review:
Definition of the following terminologies:
a) Prokaryote
b) Eukaryote
c) Organelle
d) Hydrophilic
e) Hydrophobic
Introduction:
Organisms are classified into prokaryotesand eukaryotes on the basis of theircell characteristics. Both types of cells contain cytoplasm, which provides a site for various
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Explanation of Solution
a) Prokaryote: Unicellular living organisms thatlack a well-defined nucleus are termed as prokaryotes. They are classified into two distinct classes: archaea and bacteria. Some of the bacteria can cause disease, such as cholera, syphili, snd tetanus, whereas some are useful to humans, such as those which are involved in the preparation of yogurt, chees, end bread. Organisms in group Archaea can thrive in challenging habitats.
b) Eukaryote: These organisms can be unicellular (such as protist) ormulticellular (such as plants and animals). They possess a well-defined nucleus and membrane-bound organelles(subcellular compartments) in their large sized cells. Their cells are more complex due to cellular specialization (according to their specific functions) and communication mechanisms among the cells.
c) Organelles: These are thesubcellular compartmentspresent mainly in eukaryotes. They have the ability to perform specificcellular functions. They are often bounded by a membrane, and provide compartmentalization for efficient regulation of biochemical processes.
d) Hydrophilic: The molecules thatfavorably interact with water molecules or polar materials are termed as hydrophilic. They possess charge (positive or negative), or contain electronegative elements, such as nitrogen or oxygen to form a hydrogen bond with water. Examples of such molecules in a cell include sugar (glucose) and salt (sodium chloride).
e) Hydrophobic: Hydrophobic molecules are those which do not interact with water as they lack any electronegative elements. They tend to form aggregation spontaneously when mixed with waterin an aqueous environment. Aggregation results in minimum contact between their nonpolar hydrocarbon chains and water, thus preventing any interaction.
Therefore, it can be concluded that prokaryotes and eukaryotes are different from each other on the basis of nucleus, size, and presence of membrane-bound organelles. Substances in a cell can be hydrophobic or hydrophilic, depending upon whether they interact with water or not.
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Chapter 2 Solutions
Biochemistry, The Molecular Basis of Life, 6th Edition
- A protein biochemist attempted to determine the amino acid sequence of a decapeptide. The results from the trypsin, chymotrypsin, and cyanogen bromide treatments are shown: • Trypsin digestion gave two fragments with multiple residues (not in order): T1: Ala, Arg, Phe, Gly, Thr, Trp, Tyr • T2: Lys, Met, Val Chymotrypsin digestion gave four fragments with multiple residues (not in order): • CTI: Ala, Phe 。 CT2: Thr, Trp • CT3: Lys, Met, Tyr, Val 。 CT4: Arg, Gly ⚫ Treatment with cyanogen bromide yielded a single amino acid, methionine, and a nonapeptide. What is a possible sequence of the decapeptide? Use three-letter abbreviations in your answer, and add a dash between each residue.arrow_forwardPoly-L-leucine in an organic solvent such as dioxane is a helical, whereas poly-L-isoleucine is not. Why do these amino acids with the same number and kinds of atoms have different helix-forming tendencies? L-isoleucine's methyl group sterically interferes with α-helix formation, whereas L-leucine's methyl group does not interfere. L-isoleucine lacks an NH group that can donate a hydrogen bond to stabilize an a helix, whereas L-leucine has an NH group. L-isoleucine contains a hydrogen-bond acceptor in close proximity to the main chain, whereas L-leucine lacks this group. L-isoleucine's ring structure prevents it from assuming the op value to fit into an a helix, whereas L-isoleucine does not have a ring structure.arrow_forwardSamples of the octapeptide AVGWRVKS are subjected to proteolytic cleavage by either trypsin or chymotrypsin. Select the most appropriate technique for separating the digestion products of AVGWRVKS if cleaved by trypsin. salting out ion-exchange chromatography gel-filtration chromatography dialysis Select the most appropriate technique for separating the digestion products of AVGWRVKS if cleaved by chymotrypsin. ion-exchange chromatography gel-filtration chromatography dialysis salting outarrow_forward
- Classify each description as corresponding to DNA or RNA. DNA a single molecule that can be over 10,000,000 nucleotides long Answer Bank usually single stranded RNA makes up the genome for eukaryotic organisms a single molecule that can form a complex secondary structure usually double stranded can be translated into a protein includes deoxyribose sugar includes the base uracilarrow_forwardA protein biochemist attempted to determine the amino acid sequence of a decapeptide. The results from the trypsin, chymotrypsin, and cyanogen bromide treatments are shown: • Trypsin digestion gave two fragments with multiple residues (not in order): T1: Ala, Arg, Phe, Gly, Thr, Trp, Tyr • T2: Lys, Met, Val ⚫ Chymotrypsin digestion gave four fragments with multiple residues (not in order): • CT1: Ala, Phe ° • CT2: Thr, Trp 。 CT3: Lys, Met, Tyr, Val • CT4: Arg, Gly ⚫ Treatment with cyanogen bromide yielded a single amino acid, methionine, and a nonapeptide. What is a possible sequence of the decapeptide? Use three-letter abbreviations in your answer, and add a dash between each residue. sequence:arrow_forwardClassify each nucleotide or nucleoside by the type of base and sugar present in each image. HO. -CH₂ 0 NH₂ OH OH OH он NH Classify the molecule. Opurine, deoxyribose purine, ribose Opyrimidine, deoxyribose pyrimidine, ribose NH₂ Classify the molecule. purine, deoxyribose Opyrimidine, ribose Opurine, ribose pyrimidine, deoxyribose H₂C. ·CH₂ NH Classify the molecule. pyrimidine, ribose Opurine, deoxyribose O purine, ribose Opyrimidine, deoxyribose OHarrow_forward
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- Which of these amino acids have R groups that have hydrogen-bonding potential? Ser Ile Glu Tyr Ala Thrarrow_forwardSelect the true statements about SDS-PAGE, a method of separating proteins. Assume that SDS-PAGE is performed under reducing conditions. Proteins are visualized using a dye that binds to the gel matrix, but not to proteins. Protein-SDS complexes have similar mass to charge ratios; therefore, separation is by size. Proteins are separated in a polyacrylamide gel matrix. Protein-SDS complexes migrate toward the negative electrode. Smaller proteins migrate faster through the polyacrylamide gel. Sodium dodecyl sulfate binds proteins, resulting in SDS-protein complexes that are similar in size.arrow_forwardClassify each feature as charactistic of DNA polymerase or RNA polymerase. DNA polymerase RNA polymerase Answer Bank uses deoxyribonucleoside triphosphates does not need a primer needs a primer uses ribonucleoside triphosphates exhibits semiconservative replicationarrow_forward
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