STATISTICS F/BUSINESS+ECONOMICS-TEXT
13th Edition
ISBN: 9781305881884
Author: Anderson
Publisher: CENGAGE L
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Textbook Question
Chapter 19, Problem 16SE
Samples of size 5 provided the following 20 sample means for a production process that is believed to be in control.
| 95.72 | 95.24 | 95.18 |
| 95.44 | 95.46 | 95.32 |
| 95.40 | 95.44 | 95.08 |
| 95.50 | 95.80 | 95.22 |
| 95.56 | 95.22 | 95.04 |
| 95.72 | 94.82 | 95.46 |
| 95.60 | 95.78 |
- a. Based on these data, what is an estimate of the
mean when the process is in control? - b. Assume that the process standard deviation is σ = .50. Develop the
- c. Do any of the 20 sample means indicate that the process was out of control?
a.
Expert Solution
To determine
Find the estimate of the mean when the process is in control.
Answer to Problem 16SE
The estimate of the mean for production process that is in control is 95.4.
Explanation of Solution
Calculation:
The 20 sample means for a production process are provided.
The estimate of the mean for production process is given below:
Thus, the estimate of the mean for production process that is in control is 95.4.
b.
Expert Solution
To determine
Construct a
Answer to Problem 16SE
Output obtained using MINITAB software is given below:
Explanation of Solution
Calculation:
Upper control limits for
Lower control limits for
Software procedure:
Step-by-step software procedure to construct the
- Choose Graph > Time Series Plot or Stat > Time Series > Time Series Plot.
- Choose Simple, and then click OK.
- In Series, select Mean.
- In Show reference lines at Y values, enter 96.07, 95.4, and 94.73.
- Click OK.
Thus, the control limits for
c.
Expert Solution
To determine
Explain whether any of the 20 sample means indicate that the process is out of control or not.
Explanation of Solution
From the
Thus, the 20 sample means do not indicate that the process was out of control.
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Microsoft Excel snapshot for random sampling: Also note the formula used for the last
column
02
x✓ fx =INDEX(5852:58551, RANK(C2, $C$2:$C$51))
A
B
1
No.
States
2
1
ALABAMA
Rand No.
0.925957526
3
2
ALASKA
0.372999976
4
3
ARIZONA
0.941323044
5
4 ARKANSAS
0.071266381
Random Sample
CALIFORNIA
NORTH CAROLINA
ARKANSAS
WASHINGTON
G7
Microsoft Excel snapshot for systematic sampling:
xfx INDEX(SD52:50551, F7)
A
B
E
F
G
1
No.
States
Rand No. Random Sample
population
50
2
1 ALABAMA
0.5296685 NEW HAMPSHIRE
sample
10
3
2 ALASKA
0.4493186 OKLAHOMA
k
5
4
3 ARIZONA
0.707914 KANSAS
5
4 ARKANSAS 0.4831379 NORTH DAKOTA
6
5 CALIFORNIA 0.7277162 INDIANA
Random Sample
Sample Name
7
6 COLORADO 0.5865002 MISSISSIPPI
8
7:ONNECTICU 0.7640596 ILLINOIS
9
8 DELAWARE 0.5783029 MISSOURI
525
10
15
INDIANA
MARYLAND
COLORADO
Chapter 19 Solutions
STATISTICS F/BUSINESS+ECONOMICS-TEXT
Ch. 19.2 - A process that is in control has a mean of = 12.5...Ch. 19.2 - Twenty-five samples, each of size 5, were selected...Ch. 19.2 - Twenty-five samples of 100 items each were...Ch. 19.2 - A process sampled 20 times with a sample of size 8...Ch. 19.2 - Temperature is used to measure the output of a...Ch. 19.2 - A quality control process monitors the weight per...Ch. 19.2 - The Goodman Tire and Rubber Company periodically...Ch. 19.2 - Over several weeks of normal, or in-control,...Ch. 19.2 - An airline operates a call center to handle...Ch. 19.3 - For an acceptance sampling plan with n = 25 and c...
Ch. 19.3 - Consider an acceptance sampling plan with n = 20...Ch. 19.3 - Repeat exercise 11 for the acceptance sampling...Ch. 19.3 - Refer to the KALI problem presented in this...Ch. 19.3 - To inspect incoming shipments of raw materials, a...Ch. 19 - Samples of size 5 provided the following 20 sample...Ch. 19 - Product filling weights are normally distributed...Ch. 19 - Twenty-five samples of size 5 resulted in x = 5.42...Ch. 19 - The following are quality control data for a...Ch. 19 - The following were collected for the Master Blend...Ch. 19 - An insurance company samples claim forms for...Ch. 19 - Managers of 1200 different retail outlets make...Ch. 19 - An n = 10, c = 2 acceptance sampling plan is being...Ch. 19 - Prob. 24SE
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