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Concept explainers
(a)
Interpretation:
To write anode half cell reaction.
Concept introduction:
An electrolytic cell consists of two half cells namely anode and cathode. Anode is the half cell where oxidation takes place and cathode is the half cell where reduction takes place. The capacity of an element to get oxidized ( to lose electrons) is called oxidation potential. From the given anode reaction, balance the reaction. The balanced equation is the anode half reaction.
(b)
Interpretation:
To write cathode half cell reaction.
Concept introduction:
An electrolytic cell consists of two half cells namely anode and cathode. Anode is the half cell where oxidation takes place and cathode is the half cell where reduction takes place. The capacity of an element to get reduced ( to gain electrons) is called reduction potential. From the given cathode reaction, balance the reaction. The balanced equation is the cathode half reaction.
(c)
Interpretation:
To calculate overall standard cell potential.
Concept introduction:
Overall standard cell potential is calculated from the following formula,
Summation of electrode potential of anode and electrode potential of cathode gives the overall standard potential.
(d)
Interpretation:
To determine the role of microbes in
Concept introduction:
Generation of electricity is also possible by action of microbes in soil or organic matter. In fuel cell anode produces electrons by oxidation of organic compounds in soil.
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Chapter 19 Solutions
GENERAL CHEMISTRY(LL)-W/MASTERINGCHEM.
- propose synthesisarrow_forwardExplanation O Conjugated Pi Systems Deducing the reactants of a Diels-Alder reaction Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. Click and drag to start drawing a structure. Xarrow_forwardDiels Alder Cycloaddition: Focus on regiochemistry (problems E-F) –> match + of thedienophile and - of the diene while also considering stereochemistry (endo).arrow_forward
- HELP! URGENT! PLEASE RESOND ASAP!arrow_forwardQuestion 4 Determine the rate order and rate constant for sucrose hydrolysis. Time (hours) [C6H12O6] 0 0.501 0.500 0.451 1.00 0.404 1.50 0.363 3.00 0.267 First-order, k = 0.210 hour 1 First-order, k = 0.0912 hour 1 O Second-order, k = 0.590 M1 hour 1 O Zero-order, k = 0.0770 M/hour O Zero-order, k = 0.4896 M/hour O Second-order, k = 1.93 M-1-hour 1 10 ptsarrow_forwardDetermine the rate order and rate constant for sucrose hydrolysis. Time (hours) [C6H12O6] 0 0.501 0.500 0.451 1.00 0.404 1.50 0.363 3.00 0.267arrow_forward
- Draw the products of the reaction shown below. Use wedge and dash bonds to indicate stereochemistry. Ignore inorganic byproducts. OSO4 (cat) (CH3)3COOH Select to Draw ઘarrow_forwardCalculate the reaction rate for selenious acid, H2SeO3, if 0.1150 M I-1 decreases to 0.0770 M in 12.0 minutes. H2SeO3(aq) + 6I-1(aq) + 4H+1(aq) ⟶ Se(s) + 2I3-1(aq) + 3H2O(l)arrow_forwardProblem 5-31 Which of the following objects are chiral? (a) A basketball (d) A golf club (b) A fork (c) A wine glass (e) A spiral staircase (f) A snowflake Problem 5-32 Which of the following compounds are chiral? Draw them, and label the chirality centers. (a) 2,4-Dimethylheptane (b) 5-Ethyl-3,3-dimethylheptane (c) cis-1,4-Dichlorocyclohexane Problem 5-33 Draw chiral molecules that meet the following descriptions: (a) A chloroalkane, C5H11Cl (c) An alkene, C6H12 (b) An alcohol, C6H140 (d) An alkane, C8H18 Problem 5-36 Erythronolide B is the biological precursor of erythromycin, a broad-spectrum antibiotic. How H3C CH3 many chirality centers does erythronolide B have? OH Identify them. H3C -CH3 OH Erythronolide B H3C. H3C. OH OH CH3arrow_forward
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