College Physics
7th Edition
ISBN: 9780321601834
Author: Jerry D. Wilson, Anthony J. Buffa, Bo Lou
Publisher: Addison-Wesley
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Textbook Question
Chapter 19, Problem 10E
The enlarged circular inset in Fig.19.11 shows how the positive sodium (Na+) ions in seawater are accelerated out the rear of the submarine to provide a propulsive force. But what about the negative chlorine (Cl-) ions in the seawater? Because they have charge of the opposite sign, aren't they accelerated forward, resulting in a net force of zero on the submarine? Explain.
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Four capacitors are connected as shown in the figure below. (Let C = 12.0 μF.)
a
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(a) Find the equivalent capacitance between points a and b.
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(b) Calculate the charge on each capacitor, taking AV ab = 16.0 V.
20.0 uF capacitor 94.7
6.00 uF capacitor 67.6
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3.00 µF capacitor
capacitor C
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The 3 µF and 12.0 uF capacitors are in series and that combination is in parallel with the 6 μF capacitor. What quantity is the same for capacitors in parallel? μC
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You are correct that the charge on this capacitor will be the same as the charge on the 3 μF capacitor. μC
In the pivot assignment, we observed waves moving on a string stretched by hanging
weights. We noticed that certain frequencies produced standing waves. One such
situation is shown below:
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Direct Measurement
©2015 Peter Bohacek I.
20
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20
30
40
50
60
70
80
90
100
Which Harmonic is this?
Do NOT include units!
What is the wavelength of this wave in cm with only no decimal places?
If the speed of this wave is 2500 cm/s, what is the frequency of this harmonic (in Hz, with
NO decimal places)?
Four capacitors are connected as shown in the figure below. (Let C = 12.0 µF.)
A circuit consists of four capacitors. It begins at point a before the wire splits in two directions. On the upper split, there is a capacitor C followed by a 3.00 µF capacitor. On the lower split, there is a 6.00 µF capacitor. The two splits reconnect and are followed by a 20.0 µF capacitor, which is then followed by point b.
(a) Find the equivalent capacitance between points a and b. µF(b) Calculate the charge on each capacitor, taking ΔVab = 16.0 V.
20.0 µF capacitor
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6.00 µF capacitor
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3.00 µF capacitor
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µC
Chapter 19 Solutions
College Physics
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