
Concept explainers
What early advancements made the GTA welding process more effective and reduced its cost?

The early advancements that made the GTA welding process more effective and reduced its cost.
Explanation of Solution
GTA Welding: Gas tungsten arc welding (GTAW) process is also referred to as Heliarc or tungsten-inert-gas (TIG) welding. In this process, a non-consumable electrode (tungsten) is used for the arc generation. The melting of the electrode does not take place in this process, although the melting of work takes place at the spot where the arc impacts its surface. A molten metal pool is generated due to the melting of work. The filler metal of thin wire is fed directly into the molten metal pool. An inert gas is used to provide needed arc characteristics.
The effectiveness and cost reduction of the GTAW process is achieved by:
- The improvement in the composition of the gas (switching from Helium to Tungsten).
- Theproper understanding of the importance of polarity.
- Use of argon gas instead of aluminium.
Before the development of GTAW process, the helium gas was utilized as the protecting gas for the GTAW procedure alongside DCEP welding current.However, this gas causes numerous issues that restricted the uses of the GTAW procedure. The welding of aluminium was troublesome by GTAW process before its improvement, yet the utilization of argon gas makes this procedure more common.
Want to see more full solutions like this?
Chapter 16 Solutions
Welding: Principles and Applications (MindTap Course List)
- Sketch h, for Problem 13.64 13 13.65 In Sketch i the tension on the slack side of the left pulley is 20% of that on the tight side. The shaft rotates at 1000 rpm. Select a pair of deep-groove roller bearings to sup- port the shaft for 99% reliability and a life of 20,000 hr. Assume Eq. (13.83) can be used to account for lubricant cleanliness. All length dimensions are in millimeters. b Z 02 0 y 200 500. 187 100 30° B TONE 500 diam 800 N 650 diam 100 N Sketch i, for Problem 13.65 வarrow_forwardProblem 2: Consider the rectangular wood beam below. Use E=1.0. 1. Determine the slope at A. 2. Determine the largest deflection between A and B. Use the elastic curve equation. Show all work. (20%) 3 kN/m A 2.4 m - 50 mm AT 150 mm 0000 - B C 1.2 m→arrow_forwardPlease give a clear solution.arrow_forward
- USE MATLAB ONLY Turbomachienery . GIven: vx = 185 m/s, flow angle = 60 degrees, R = 0.5, U = 150 m/s, b2 = -a3, a2 = -b3 Find: velocity triangle , a. magnitude of abs vel leaving rotor (m/s) b. flow absolute angles (a1, a2, a3) 3. flow rel angles (b2, b3) d. specific work done e. use code to draw vel. diagram Use this code for plot % plots Velocity Tri. in Ch4 function plotveltri(al1,al2,al3,b2,b3) S1L = [0 1]; V1x = [0 0]; V1s = [0 1*tand(al3)]; S2L = [2 3]; V2x = [0 0]; V2s = [0 1*tand(al2)]; W2s = [0 1*tand(b2)]; U2x = [3 3]; U2y = [1*tand(b2) 1*tand(al2)]; S3L = [4 5]; V3x = [0 0]; V3r = [0 1*tand(al3)]; W3r = [0 1*tand(b3)]; U3x = [5 5]; U3y = [1*tand(b3) 1*tand(al3)]; plot(S1L,V1x,'k',S1L,V1s,'r',... S2L,V2x,'k',S2L,V2s,'r',S2L,W2s,'b',U2x,U2y,'g',... S3L,V3x,'k',S3L,V3r,'r',S3L,W3r,'b',U3x,U3y,'g',...... 'LineWidth',2,'MarkerSize',10),... axis([-1 6 -4 4]), ... title('Velocity Triangle'), ... xlabel('x'),ylarrow_forwardThe wall of a furnace has a thickness of 5 cm and thermal conductivity of 0.7 W/m-°C. The inside surface is heated by convection with a hot gas at 402°C and a heat transfer coefficient of 37 W/m²-°C. The outside surface has an emissivity of 0.8 and is exposed to air at 27°C with a heat transfer coefficient of 20 W/m²-ºC. Assume that the furnace is inside a large room with walls, floor and ceiling at 27°C. Show the thermal circuit and determine the heat flux through the furnace wall. h₁ T₁ k -L T. sur ho Earrow_forwardTurbomachienery . GIven: vx = 185 m/s, flow angle = 60 degrees, R = 0.5, U = 150 m/s, b2 = -a3, a2 = -b3 Find: velocity triangle , a. magnitude of abs vel leaving rotor (m/s) b. flow absolute angles (a1, a2, a3) 3. flow rel angles (b2, b3) d. specific work done e. use code to draw vel. diagram Use this code for plot % plots Velocity Tri. in Ch4 function plotveltri(al1,al2,al3,b2,b3) S1L = [0 1]; V1x = [0 0]; V1s = [0 1*tand(al3)]; S2L = [2 3]; V2x = [0 0]; V2s = [0 1*tand(al2)]; W2s = [0 1*tand(b2)]; U2x = [3 3]; U2y = [1*tand(b2) 1*tand(al2)]; S3L = [4 5]; V3x = [0 0]; V3r = [0 1*tand(al3)]; W3r = [0 1*tand(b3)]; U3x = [5 5]; U3y = [1*tand(b3) 1*tand(al3)]; plot(S1L,V1x,'k',S1L,V1s,'r',... S2L,V2x,'k',S2L,V2s,'r',S2L,W2s,'b',U2x,U2y,'g',... S3L,V3x,'k',S3L,V3r,'r',S3L,W3r,'b',U3x,U3y,'g',...... 'LineWidth',2,'MarkerSize',10),... axis([-1 6 -4 4]), ... title('Velocity Triangle'), ... xlabel('x'),ylabel('y'), gridarrow_forward
- To save fuel during the heating season it is suggested that glass windows be covered at night with a 1.2 cm layer of polystyrene. Estimate the percent savings in energy and discuss the feasibility of this idea. Show the thermal circuit with and without the insulation panel. Consider a typical case of 0.2 cm thick window glass with inside and outside heat transfer coefficients of 6 and 32 W/m²-ºC. Lg←←Lp h T₁ T。 g kp insulation panelarrow_forwardA plate of thickness L and thermal conductivity k is exposed to a fluid at temperature T1 with a heat transfer coefficient h, on one side and T2 and h₂ on the other side. Determine the one-dimensional temperature distribution in the plate. Assume steady state and constant conductivity. L h h T%2 k Tx1 0xarrow_forwardDetermine the heater capacity needed to maintain the inside temperature of a laboratory chamber at 38°C when placed in a room at 21°C. The chamber is cubical with each side measuring 35 cm. The walls are 1.2 cm thick and are made of polystyrene. The inside and outside heat transfer coefficients are 5 and 22 W/m²-°C.arrow_forward
- (a) Refer to the above figure .What kind of controller is it ? (b) simplify the block diagramto derive the closed loop transfer function of the system. (C) What are the assumptions thatare needed to make to findthe controller gain ? What arethe value of Kp , Ti and Td ?arrow_forwardLonsider a regenerative gas turbine power plant with two stages of compression and two stages of expansion. The compressor pressure ratio of the compressor is 3. Air enters each stage of compressor at 290 K and esch stage of turbine at 1400 K. The regetierator has an effectiveness of 100%, Determine (a) The enthalpy at stage#2 in KJ/kg (b) The enthalpy at stage in KJ/kg" (c) The cathalpy at stager in KJ/kg* (d) The enthalpy at stage#10 in KJ/kg (c) The mass flow rate of air needed to develop a net power output of 50 MW *For all final answers please enter the integer part only, (ie 1234) and do not include the decimal part and the decimal point No rounding in your calculationarrow_forwardConsider a regenerative gas turbine power plant with two stages of compression and two stages of expansion. The compressor pressure ratio of the compressor is 3. Air enters each stage of compressor at 290 K and each stage of turbine at 1400 K. The regenerator has an effectiveness of 100%. Determine (a) The enthalpy at stage#2 in KJ/kg⭑ (b) The enthalpy at stage#6 in KJ/kg* (c) The enthalpy at stage#9 in KJ/kg (d) The enthalpy at stage#10 in KJ/kg (e)The mass flow rate of air needed to develop a net power output of 50 MW* *For all final answers please enter the integer part only, (ie 1234) and do not include the decimal part and the decimal point No rounding in your calculation. Compressor stage 1 Regenerator www HX ww 9 Combustor Reheat Intercooler ww Compressor stage 2 Turbine 1 combustor Turbine 2arrow_forward
- Welding: Principles and Applications (MindTap Cou...Mechanical EngineeringISBN:9781305494695Author:Larry JeffusPublisher:Cengage Learning
