Concept explainers
(a)
Interpretation:
The structure of 3-bromohexane has to be drawn and the optical activity has to be determined.
Concept Introduction:
The structure of the compound is given by its systematic name.
To give the structure from the name of the compound, the root name has to be identified. The root name indicates the number of carbon atoms present in the longest chain.
Then the functional group (suffix) has to be identified. It indicates whether any
The prefix of the name indicates the branched groups and their positions on the carbon chain.
The name of the compound is in the form
Prefix + Root + Suffix
The isomers which are mirror images of each other and are non-superimposable are said to be optical isomers and the isomerism is said to be optical isomerism. The optical isomers are also called as enantiomers. The optical isomers which rotates the plane-polarized light are optically active.
The optical isomers are asymmetric and plane of symmetry will be absent. An organic molecule is said to be chiral when it is bonded to four different groups and is asymmetric. The carbon atom bonded to four different groups is said to be chiral carbon or asymmetric carbon. An organic compound is said to be optically active when it contains at least one chiral center.
(b)
Interpretation:
The structure of 3-chloro-3-methylpentane has to be drawn and the optical activity has to be determined.
Concept Introduction:
The structure of the compound is given by its systematic name.
To give the structure from the name of the compound, the root name has to be identified. The root name indicates the number of carbon atoms present in the longest chain.
Then the functional group (suffix) has to be identified. It indicates whether any functional groups are present in the compound, it also gives whether the compound is an alkane or alkene or alkyne.
The prefix of the name indicates the branched groups and their positions on the carbon chain.
The name of the compound is in the form
Prefix + Root + Suffix
The isomers which are mirror images of each other and are non-superimposable are said to be optical isomers and the isomerism is said to be optical isomerism. The optical isomers are also called as enantiomers. The optical isomers which rotates the plane-polarized light are optically active.
The optical isomers are asymmetric and plane of symmetry will be absent. An organic molecule is said to be chiral when it is bonded to four different groups and is asymmetric. The carbon atom bonded to four different groups is said to be chiral carbon or asymmetric carbon. An organic compound is said to be optically active when it contains at least one chiral center.
(c)
Interpretation:
The structure of 1,2-dibromo-2-methylbutane has to be drawn and the optical activity has to be determined.
Concept Introduction:
The structure of the compound is given by its systematic name.
To give the structure from the name of the compound, the root name has to be identified. The root name indicates the number of carbon atoms present in the longest chain.
Then the functional group (suffix) has to be identified. It indicates whether any functional groups are present in the compound, it also gives whether the compound is an alkane or alkene or alkyne.
The prefix of the name indicates the branched groups and their positions on the carbon chain.
The name of the compound is in the form
Prefix + Root + Suffix
The isomers which are mirror images of each other and are non-superimposable are said to be optical isomers and the isomerism is said to be optical isomerism. The optical isomers are also called as enantiomers. The optical isomers which rotates the plane-polarized light are optically active.
The optical isomers are asymmetric and plane of symmetry will be absent. An organic molecule is said to be chiral when it is bonded to four different groups and is asymmetric. The carbon atom bonded to four different groups is said to be chiral carbon or asymmetric carbon. An organic compound is said to be optically active when it contains at least one chiral center.
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Chapter 15 Solutions
CHEMISTRY: MOLECULAR NATURE OF MATTER
- There is an instrument in Johnson 334 that measures total-reflectance x-ray fluorescence (TXRF) to do elemental analysis (i.e., determine what elements are present in a sample). A researcher is preparing a to measure calcium content in a series of well water samples by TXRF with an internal standard of vanadium (atomic symbol: V). She has prepared a series of standard solutions to ensure a linear instrument response over the expected Ca concentration range of 40-80 ppm. The concentrations of Ca and V (ppm) and the instrument response (peak area, arbitrary units) are shown below. Also included is a sample spectrum. Equation 1 describes the response factor, K, relating the analyte signal (SA) and the standard signal (SIS) to their respective concentrations (CA and CIS). Ca, ppm V, ppm SCa, arb. units SV, arb. units 20.0 10.0 14375.11 14261.02 40.0 10.0 36182.15 17997.10 60.0 10.0 39275.74 12988.01 80.0 10.0 57530.75 14268.54 100.0…arrow_forwardA mixture of 0.568 M H₂O, 0.438 M Cl₂O, and 0.710 M HClO are enclosed in a vessel at 25 °C. H₂O(g) + C₁₂O(g) = 2 HOCl(g) K = 0.0900 at 25°C с Calculate the equilibrium concentrations of each gas at 25 °C. [H₂O]= [C₁₂O]= [HOCI]= M Σ Marrow_forwardWhat units (if any) does the response factor (K) have? Does the response factor (K) depend upon how the concentration is expressed (e.g. molarity, ppm, ppb, etc.)?arrow_forward
- Provide the structure, circle or draw, of the monomeric unit found in the biological polymeric materials given below. HO OH amylose OH OH 행 3 HO cellulose OH OH OH Ho HOarrow_forwardWhat units (if any) does K have? Does K depend upon how the concentration is expressed (e.g. molarity, ppm, ppb, etc.)? in calculating the response factorarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- Don't used Ai solution and don't used hand raitingarrow_forwardOA. For the structure shown, rank the bond lengths (labeled a, b and c) from shortest to longest. Place your answer in the box. Only the answer in the box will be graded. (2 points) H -CH3 THe b Нarrow_forwardDon't used hand raitingarrow_forward
- Quizzes - Gen Organic & Biological Che... ☆ myd21.lcc.edu + O G screenshot on mac - Google Search savings hulu youtube google disney+ HBO zlib Homework Hel...s | bartleby cell bio book Yuzu Reader: Chemistry G periodic table - Google Search b Home | bartleby 0:33:26 remaining CHEM 120 Chapter 5_Quiz 3 Page 1: 1 > 2 > 3 > 6 ¦ 5 > 4 > 7 ¦ 1 1 10 8 ¦ 9 a ¦ -- Quiz Information silicon-27 A doctor gives a patient 0.01 mC i of beta radiation. How many beta particles would the patient receive in I minute? (1 Ci = 3.7 x 10 10 d/s) Question 5 (1 point) Saved Listen 2.22 x 107 222 x 108 3.7 x 108 2.22 x 108 none of the above Question 6 (1 point) Listen The recommended dosage of 1-131 for a test is 4.2 μCi per kg of body mass. How many millicuries should be given to a 55 kg patient? (1 mCi = 1000 μСi)? 230 mCiarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
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