
Concept explainers
A referent system that can be used to locate objects in the sky is the
a. celestial globe.
b. celestial coordinates.
c. celestial sphere.
d. celestial maps.

The referent system that can be used to locate the objects in the sky from the following options:
Celestial globe
Celestial coordinates
Celestial sphere
Celestial maps
Answer to Problem 1AC
Solution:
Option (c) is correct.
Explanation of Solution
Introduction:
Referent system is a system for reference that can be needed in order to locate anything, including astronomical objects or planets, in the skyappropriately. It can be established easily by first considering the sky to be an imaginary ‘celestial sphere’.
Explanation:
Reason for the correct option:
The imaginary sphere of arbitrarily larger radius, with earth located at its center is usually referred as theCelestial sphere. In astronomy, all the objects located in the observer’s sky are assumed as projected upon the inner surface of the celestial sphere. To locate the objects in the sky, an imaginary celestial sphere is thus considered as the referent system.
Hence, option (c) is correct.
Reason for the incorrect option:
Option (a) is incorrect because the celestial globe is basically referred as the representation of constellations and stars as they are located on an apparent sphere in the sky. These globes are used for some astrological or astronomical calculations, and as ornaments. So, it is a wrong answer.
Option (b) is incorrect because celestial coordinates are the set of numbers that are used for reference in order to pinpoint the position of a celestial object in the sky. In astronomy, several different coordinate systems are used to locate the position of an object in the celestial sphere in the sky. So, it is a wrong answer.
Option (d) is incorrect because celestial maps are the representations of astronomical objects located in the sky. The division of grids makes it easier for the astronomers to develop and use the celestial maps in an appropriate manner. Thus, it cannot be used as a referent system. So, it is a wrong answer.
Hence, options (a), (b) and (d) are incorrect.
Conclusion:
The referent system that can be used to locate the objects in the sky is the celestial sphere.
Want to see more full solutions like this?
Chapter 14 Solutions
Physical Science
- A man holds a double-sided spherical mirror so that he is looking directly into its convex surface, 33 cm from his face. The magnification of the image of his face is +0.17. What will be the image distance when he reverses the mirror (looking into its concave surface), maintaining the same distance between the mirror and his face? Be sure to include the algebraic sign (+ or -) with your answer.arrow_forwardHow do you draw a diagram of the ruler and mass system in equilibrium identifying the anti-clockwise torque and clockwise torque? How do I calculate the anti-clockwise torque and the clockwise torque of the system with the ruler and the washers, does it come from the data in table 4? Please help, thank you!arrow_forwardExample Double pane windows have two panes of glass (n = 1.5), with a layer of air sandwiched between them. If light from outside enters the first pane at an angle of 25° from the surface normal, what angle does it enter the house at? ☑ 3 5arrow_forward
- Did your experiment results in Data Table 3 verify, to within a reasonable experimental error, the condition of equilibrium of Equation 6: Στanti-clockwise = Στclockwise? Support your response with experimental data. What does this Σ mean? My results do not show they are equal to each other, what does this mean then, and what does the data show? Thanks!arrow_forwardmicro wave.arrow_forwardmicro wave.arrow_forward
- kerjakanarrow_forwardAn object is placed 37.4cm in front of a diverging lens with a focal length of 18.1 cm. Please provide your answers in units of cm if necessary. bookmark_border1.0p3a Find the image distance. Answer Updated 6 days ago Show feedback bookmark_border1.0p3b Is the image real or virtual? Real Virtual Updated 6 days ago Show feedback bookmark_border1.0p3c Suppose the object is brought to a distance of 10.3 cm in front of the lens. Where is the image now with respect to its previous location? (Note: Ensure the sign convention you use is consistent by treating all image distances on the object side of the lens as negative.) Answer Updated 7 minutes ago Show feedback bookmark_border1.0p3d How has the height of the image changed if the object is 84.2 cm tall? Answerarrow_forwardn object is placed 37.4cm in front of a diverging lens with a focal length of 18.1 cm. Please provide your answers in units of cm if necessary. bookmark_border1.0p3a Find the image distance. Answer Updated 6 days ago Show feedback bookmark_border1.0p3b Is the image real or virtual? Real Virtual Updated 6 days ago Show feedback bookmark_border1.0p3c Suppose the object is brought to a distance of 10.3 cm in front of the lens. Where is the image now with respect to its previous location? (Note: Ensure the sign convention you use is consistent by treating all image distances on the object side of the lens as negative.) Answer Updated just now Show feedback bookmark_border1.0p3d How has the height of the image changed if the object is 84.2 cm tall? Answerarrow_forward
- An Introduction to Physical SciencePhysicsISBN:9781305079137Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar TorresPublisher:Cengage LearningHorizons: Exploring the Universe (MindTap Course ...PhysicsISBN:9781305960961Author:Michael A. Seeds, Dana BackmanPublisher:Cengage LearningAstronomyPhysicsISBN:9781938168284Author:Andrew Fraknoi; David Morrison; Sidney C. WolffPublisher:OpenStax
- Stars and GalaxiesPhysicsISBN:9781305120785Author:Michael A. Seeds, Dana BackmanPublisher:Cengage LearningFoundations of Astronomy (MindTap Course List)PhysicsISBN:9781337399920Author:Michael A. Seeds, Dana BackmanPublisher:Cengage Learning





