Chapter 14, Problem 14.3.3P

Please solve this question step by step with dia gram

Use the second picture to answer the question, Thank you so much for your help!

P6.16 A compound shaft (Figure P6.16) consists of a titanium alloy [G= 6,200 ksi] tube (1) and a solid stainless steel [G= 11,500 ksi] shaft (2). Tube (1) has a length L₁ = 40 in., an outside diameter D₁ = 1.75 in., and a wall thickness t₁ = 0.125 in. Shaft (2) has a length 42 = 50 in. and a diameter d₂ = 1.25 in. If an external torque TB = 580 lb ft acts at pulley B in the direction shown, calculate the torque Tcrequired at pulley C so that the rotation angle of pulley Crelative to A is zero. B Te (2) TB (1) FIGURE P6.16

7.43 Neglecting head losses, determine what horsepower the pump must deliver to produce the flow as shown. Here, the elevations at points A, B, C, and D are 124 ft, 161 ft, 110 ft, and 90 ft, respectively. The nozzle area is 0.10 ft². B Nozzle Water C Problem 7.43

A 1.8m x 1.8m footing is located at a depth of 1 m below the ground surface in a deep deposit of compacted sand (f'= 33 , f' = 28 , γ = 17.5 kN/m). Calculate the ultimate net bearing capacity considering several factors (e.g., shape, depth, and inclination) when the groundwater table is located (a) at 5 m below the footing base, (b) at the ground surface, (c) at the footing base, and (d) at 1.5 m below the footing base. Also, explain the effects of the groundwater levels in the bearing capacities of the footing with your own words. If the information is not given for the calculation, please assume it reasonably.

7.18 Determine the discharge in the pipe and the pressure at point B. Neglect head losses. Assume α = 1.0 at all locations. 1.5 m Water B 3.5 m 40 cm diameter -20 cm diameter nozzle Problem 7.18

A 200-lb block is at rest on a 30° inclined plane. The coefficient of friction between the block and the inclined plane is 0.20. Compute the value of a horizontal force P that will cause motion to impend the block up the inclined plane. 200 lb P 30°

Please explain step by step

Problem 1 = = = 13,600 Manometers can be used in combination with cardiovascular catheters to measure blood pressure based on height differences. In the example in Figure 1, the manometer contains two fluids: water (density p 995 Kg/m³) and mercury (density pm Kg/m³). The density of blood is p 1,060 Kg/m³. Assume that there is atmospheric pressure at the interface between mercury and air. The interface between mercury and water is at z₁ = 7 cm, the interface between water and blood is at Z2 27 cm, and the tip of the manometer at za 10 cm. Recall that the fluid statics equation is dp/dz-pg 0, when the z axis is taken pointing downwards. a. What is the gauge pressure po at the interface with air, in mmHg? (5 points) b. Calculate the gauge pressure ps at the tip of the manometer, in mmHg. (5 points) N Z37 blood ப Zz Water Mercury Zo 3=0 z Figure 1. Manometer for blood pressure measurement.