Chapter 14, Problem 10E

Interpretation Introduction

(a)

Interpretation:

The percent by volume of ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}\text{OH}$ needs to be calculated.

Concept introduction:

The percent by volume of solute can be calculated as follows:

$\%V_{\text{Solute}}=\frac{V_{Solute}}{V_{\text{Solution}}}\times 100\%$

Here, $V_{Solute}$ is volume of solute and $V_{\text{Solution}}$ is volume of solution.

Interpretation Introduction

(b)

Interpretation:

The percent by mass of ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}\text{OH}$ needs to be calculated.

Concept introduction:

The percent by mass of solute can be calculated as follows:

$\%m_{\text{Solute}}=\frac{m_{Solute}}{m_{\text{Solution}}}\times 100\%$

Here, $m_{Solute}$ is mass of solute and $m_{\text{Solution}}$ is mass of solution.

Interpretation Introduction

(c)

Interpretation:

The percent mass by volume of ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}\text{OH}$ needs to be calculated.

Concept introduction:

The percent mass by volume of solute can be calculated as follows:

$\%m/V_{\text{Solute}}=\frac{m_{Solute}}{V_{\text{Solution}}}\times 100\%$

Here, $m_{Solute}$ is mass of solute and $V_{\text{Solution}}$ is volume of solution.