Calculus
5th Edition
ISBN: 9781429241861
Author: Laura Taalman, Peter Kohn
Publisher: W. H. Freeman
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Let the region R be the area enclosed by the function f(x) = ln (x) + 2 and g(x) = x. Write an integral in terms of x and also an
integral in terms of y that would represent the area of the region R. If necessary, round limit values to the nearest thousandth.
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(28 points) Define T: [0,1] × [−,0] → R3 by
T(y, 0) = (cos 0, y, sin 0).
Let S be the half-cylinder surface traced out by T.
(a) (4 points) Calculate the normal field for S determined by T.
(14 points) Let S = {(x, y, z) | z = e−(x²+y²), x² + y² ≤ 1}. The surface is the graph of
ze(+2) sitting over the unit disk.
=
(a) (4 points) What is the boundary OS? Explain briefly.
(b) (4 points) Let F(x, y, z) = (e³+2 - 2y, xe³±² + y, e²+y). Calculate the curl V × F.
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.Similar questions
- (6 points) Let S be the surface z = 1 − x² - y², x² + y² ≤1. The boundary OS of S is the unit circle x² + y² = 1. Let F(x, y, z) = (x², y², z²). Use the Stokes' Theorem to calculate the line integral Hint: First calculate V x F. Jos F F.ds.arrow_forward(28 points) Define T: [0,1] × [−,0] → R3 by T(y, 0) = (cos 0, y, sin 0). Let S be the half-cylinder surface traced out by T. (a) (4 points) Calculate the normal field for S determined by T.arrow_forwardI need the last answer t=? I did got the answer for the first two this is just homework.arrow_forward
- 7) 8) Let R be the region bounded by the given curves as shown in the figure. If the line x = k divides R into two regions of equal area, find the value of k 7. y = 3√x, y = √x and x = 4 8. y = -2, y = 3, x = −3, and x = −1 -1 2 +1 R Rarrow_forwardSolve this question and show steps.arrow_forwardu, v and w are three coplanar vectors: ⚫ w has a magnitude of 10 and points along the positive x-axis ⚫ v has a magnitude of 3 and makes an angle of 58 degrees to the positive x- axis ⚫ u has a magnitude of 5 and makes an angle of 119 degrees to the positive x- axis ⚫ vector v is located in between u and w a) Draw a diagram of the three vectors placed tail-to-tail at the origin of an x-y plane. b) If possible, find w × (ū+v) Support your answer mathematically or a with a written explanation. c) If possible, find v. (ū⋅w) Support your answer mathematically or a with a written explanation. d) If possible, find u. (vxw) Support your answer mathematically or a with a written explanation. Note: in this question you can work with the vectors in geometric form or convert them to algebraic vectors.arrow_forward
- Question 3 (6 points) u, v and w are three coplanar vectors: ⚫ w has a magnitude of 10 and points along the positive x-axis ⚫ v has a magnitude of 3 and makes an angle of 58 degrees to the positive x- axis ⚫ u has a magnitude of 5 and makes an angle of 119 degrees to the positive x- axis ⚫ vector v is located in between u and w a) Draw a diagram of the three vectors placed tail-to-tail at the origin of an x-y plane. b) If possible, find w × (u + v) Support your answer mathematically or a with a written explanation. c) If possible, find v. (ū⋅ w) Support your answer mathematically or a with a written explanation. d) If possible, find u (v × w) Support your answer mathematically or a with a written explanation. Note: in this question you can work with the vectors in geometric form or convert them to algebraic vectors.arrow_forwardK Find all values x = a where the function is discontinuous. For each value of x, give the limit of the function as x approaches a. Be sure to note when the limit doesn't exist. x-7 p(x) = X-7 Select the correct choice below and, if necessary, fill in the answer box(es) within your choice. (Use a comma to separate answers as needed.) OA. f is discontinuous at the single value x = OB. f is discontinuous at the single value x= OC. f is discontinuous at the two values x = OD. f is discontinuous at the two values x = The limit is The limit does not exist and is not co or - ∞. The limit for the smaller value is The limit for the larger value is The limit for the smaller value is The limit for the larger value does not exist and is not c∞ or -arrow_forwardK x3 +216 complete the table and use the results to find lim k(x). If k(x) = X+6 X-6 X -6.1 -6.01 - 6.001 - 5.999 - 5.99 -5.9 k(x) Complete the table. X -6.1 -6.01 - 6.001 - 5.999 - 5.99 - 5.9 k(x) (Round to three decimal places as needed.) Find the limit. Select the correct choice below and, if necessary, fill in the answer box within your choice.arrow_forward
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