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- Suppose a raindrop evaporates as it falls but maintains its spherical shape. Assume that the rate at which the raindrop evaporates (that is, the rate at which it loses mass) is proportional to its surface area, where the constant of proportionality is –0.01. The density (mass per volume) of water at 3.98°C is 1 g/cm3. The surface area of a sphere is 4πr2, and its volume is 4πr3/3, where r is the radius. Assume no air resistance. (Project 8 models the motion of this raindrop under the influence of air resistance.) Assume that the initial radius is 0.3 cm. Determine the raindrop’s initial mass. Write a differential equation for the rate of change of mass as a function of r. Write an equation for r as a function of massarrow_forwardConsider a water tank that is being filled with rainfall at the top and is drained through a small hole at the bottom. The change in volume can be modelled by considering the amount of water entering and leaving the tank (per unit of time) as follows dV dt fin - fout. Here volume of water in the tank V is in litres, flow rate in fin is in litres per hour, flow rate out fout is. in litres per hour and time t is in hours. Initially, the tank contains 50L of water: V(0) = 50. (a) Assume the rainfall throughout the day is getting heavier, such that, fin(t) = 10 + t and that the tank is losing 10% of its volume of water per hour, such that, fout (V) = 0.1V. Check by direct substitution that the function V(t) = 10(t + 5e-0.1t) satisfies the ODE and the initial condition. (b) Now assume that the hole is slowly growing in size, so that the flow rate out increases with time: fout (V, t) = 0.1(1 + 0.1t) V. Solve the ordinary differential equation for V(t) with this flow rate out, using either…arrow_forwardLet f (x, y, z) = xln(yz). Find the maximum rate of change of f at the point (1,2,) and the direction in which it occurs. %3Darrow_forward
- Write the differential for y = (3x − 1)³. 2 dy = 9(x − 1)² dx - - О dy = 9(3x − 1)² dx - О dy = (9x − 3)² dx – 2 dy = 3(3x − 1)² dx -arrow_forwardEvaluate ∆yA and ∆y if y=x2+2x+1 at x=1 and dx = 0.1.arrow_forward(Underdamped) A body weighing 100 lb (mass m = 3.125 slugs in fps units) is oscillating attached to a spring and a dashpot. Its first two maximum displacements of 6.73in. and 1.46 in. are observed to occur at times 0.34 s and 1.17 s, respectively. Compute the damping constant (in pound-seconds per foot) and spring constant (in pounds per foot).arrow_forward
- The specific gravity of a substance is given by G = DS/DW, where DS is the density of thesubstance in kg/m³ and DW is the density of water, which is known to be 1000 kg/m³. Thedensity of a particular substance is measured to be DS = 500 ± 5 kg/m³. Estimate the specific gravity, and find the uncertainty in the estimate.arrow_forwardA. We are given the acceleration function of a particle to be alt) = -9.8 m/ s2.If vl0) = 30m/s find the function vlt) using the fact that ult) is the antiderivative of S %3D alt). B. Using ult) above, compute the net change in distance (displacement) the particle made from O to 5 seconds. Use the Net Change formula and the fact that s ' (t) = vlt). C. Using ult) obtained above and the average function formula to obtain the average velocity of the particle from O to 5 seconds.arrow_forward7 Determine the gradient function of y = Vx '. %3Darrow_forward
- An object of mass m moves at a constant speed v in a circular path of radius r. The force required to produce the centripetal component of acceleration is called the centripetal force and is given by F = mv2/r. Newton's Law of Universal Gravitation is given by F = GMm/d2, where d is the distance between the centers of the two bodies of masses M and m, and G is a gravitational constant. The speed required for circular motion is v = √ GM/r. Use the result above to find the speed necessary for the given circular orbit around Earth. Let GM = 9.56 x 104 cubic miles per second per second, and assume the radius of Earth is 4000 miles. (Round your answer to two decimal places.) The orbit of a communications satellite R miles above the surface of Earth that is in geosynchronous orbit. [The satellite completes one orbit per side real day (approximately 23 hours, 56 minutes), and therefore appears to remain stationary above a point on Earth.] X mi/sarrow_forwardDo just part f urgent solution requiredarrow_forwardvt e dtarrow_forward
- Functions and Change: A Modeling Approach to Coll...AlgebraISBN:9781337111348Author:Bruce Crauder, Benny Evans, Alan NoellPublisher:Cengage Learning