Concept explainers
(a)
Interpretation:
The aqueous solution of
Concept introduction:
The solution is a homogeneous mixture of two or more substances. It can exist in any of the phases. Saltwater, rubbing alcohol, bleach, and air are some examples of solutions. It has two components: solute and solvent. The solute is the substance that is present in smaller quantity and gets itself dissolved in the other substance. The solvent is the substance that is present in a larger amount and it dissolves solute in itself.
The characteristics of the solution are as follows:
1. It is a homogeneous mixture of two or more substances.
2. The particles of solute can never be seen by the naked eye.
3. It does not allow the light beam to scatter.
4. It is stable.
5. The components of the solution cannot be separated by filtration.
6. It is composed of one phase only.
(b)
Interpretation:
The aqueous solution of
Concept introduction:
The solution is a homogeneous mixture of two or more substances. It can exist in any of the phases. Saltwater, rubbing alcohol, bleach, and air are some examples of solutions. It has two components: solute and solvent. The solute is the substance that is present in smaller quantity and gets itself dissolved in the other substance. The solvent is the substance that is present in a larger amount and it dissolves solute in itself.
The characteristics of the solution are as follows:
1. It is a homogeneous mixture of two or more substances.
2. The particles of solute can never be seen by the naked eye.
3. It does not allow the light beam to scatter.
4. It is stable.
5. The components of the solution cannot be separated by filtration.
6. It is composed of one phase only.
The formula to relate the molarity of a diluted and concentrated solution is as follows:
Here,
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Chapter 13 Solutions
CHEMISTRY:MOLECULAR...(LL) W/ALEKS
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- Calculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0 choices: 0.0269 kJ/mole 2610 kJ/mole 27.6 kJ/mole 0.215 kJ/mole 20.8 kJ/molearrow_forwardCalculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- Rank the compounds in each group below according to their reactivity toward electrophilic aromatic substitution (most reactive = 1; least reactive = 3). Place the number corresponding to the compounds' relative reactivity in the blank below the compound. a. CH₂F CH3 F b. At what position, and on what ring, is bromination of phenyl benzoate expected to occur? Explain your answer. :0: C-O phenyl benzoate 6.Consider the reaction below to answer the following questions. A B C NO₂ FeBr3 + Br₂ D a. The nucleophile in the reaction is: BODADES b. The Lewis acid catalyst in the reaction is: C. This reaction proceeds d. Draw the structure of product D. (faster or slower) than benzene.arrow_forwardPart 2. A solution of 6.00g of substance B in 100.0mL of aqueous solution is in equilibrium, at room temperature, wl a solution of B in diethyl ether (ethoxyethane) containing 25.0 g of B in 50.0 mL 9) what is the distribution coefficient of substance B b) what is the mass of B extracted by shaking 200 ml of an aqueous solution containing 10g of B with call at room temp): i) 100 mL of diethyl ether ii) 50ml of diethyl ether twice iii) 25ml of diethyl ether four timesarrow_forward- Rank the following groups of compounds from most acidic (1) to least acidic (4). Place the number corresponding to the compound's relative rank in the blank below the structure. a. NO₂ NO₂ CH2CH2CH2CH2OH CH3 CH3CH2CHOH CH3CH2CH2CH2OH NO₂ CH3CHCH2CH2OH b. OH OH CH₂OH CO₂H HC CN CN CNarrow_forward
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