Chapter 1.2, Problem 29E

10 The hypotenuse of a right triangle has one end at the origin and one end on the curve y = Express the area of the triangle as a function of x. A(x) =

In Problems 17-26, solve the initial value problem. 17. dy = (1+ y²) tan x, y(0) = √√3

could you explain this as well as disproving each wrong option

could you please show the computation of this by wires

4 Consider f(x) periodic function with period 2, coinciding with (x) = -x on the interval [,0) and being the null function on the interval [0,7). The Fourier series of f: (A) does not converge in quadratic norm to f(x) on [−π,π] (B) is pointwise convergent to f(x) for every x = R П (C) is in the form - 4 ∞ +Σ ak cos(kx) + bk sin(kx), ak ‡0, bk ‡0 k=1 (D) is in the form ak cos(kx) + bk sin(kx), ak 0, bk 0 k=1

Solve the equation.

could you explain this please

the answer is C, could you show me how to do it

7. [-/1 Points] DETAILS MY NOTES SESSCALCET2 6.1.505.XP. Evaluate the integral. (Use C for the constant of integration.) 21z³e² dz | 21 Need Help? Read It SUBMIT ANSWER 8. [-/1 Points] DETAILS MY NOTES SESSCALCET2 6.1.020. Evaluate the integral. 36 In y dy ₤36 25 Need Help? Read It SUBMIT ANSWER 9. [-/1 Points] DETAILS MY NOTES SESSCALCET2 6.1.009. Evaluate the integral. (Use C for the constant of integration.) In(7x In(7x + 1) dx