What are the moons of the outer planets made of, and how is their composition different from that of our Moon?
The composition of the moons of the outer planets and the difference between their composition and our Moon’s composition.
Explanation of Solution
Introduction:
The first four planets of our solar system nearest to the Sun, that is, Mercury, Venus, Earth, and Mars lies inside the asteroid belt and are called the inner planets. The rest of the planets lie outside the asteroid belt and are called the outer planets. Moons are the natural satellites which revolve around the planets. The temperature of the outer planets and their moons is relatively very low due to the greater distance from the Sun.
The moons of the outer planets are composed of ice and rocks as their temperature is significantly low and due to this, the ice formation takes place easily. This ice is available in large quantity as the building material for the moons of the outer planets.
The composition of the moons of the outer planets differ from that of our Moon as the moons of outer planets are mainly composed of ice and rocks, whereas our Moon is mainly composed of rock only. Our Moon is situated closer to the Sun due to which, it does not have enough ice formation on it.
Conclusion:
Thus, the moons of the outer planets are composed of ice and rocks, whereas our Moon is mainly composed of rock only.
Want to see more full solutions like this?
Chapter 12 Solutions
Astronomy
Additional Science Textbook Solutions
Applications and Investigations in Earth Science (9th Edition)
Biology: Life on Earth (11th Edition)
Cosmic Perspective Fundamentals
Campbell Essential Biology with Physiology (5th Edition)
Campbell Essential Biology (7th Edition)
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
- air is pushed steadily though a forced air pipe at a steady speed of 4.0 m/s. the pipe measures 56 cm by 22 cm. how fast will air move though a narrower portion of the pipe that is also rectangular and measures 32 cm by 22 cmarrow_forwardNo chatgpt pls will upvotearrow_forward13.87 ... Interplanetary Navigation. The most efficient way to send a spacecraft from the earth to another planet is by using a Hohmann transfer orbit (Fig. P13.87). If the orbits of the departure and destination planets are circular, the Hohmann transfer orbit is an elliptical orbit whose perihelion and aphelion are tangent to the orbits of the two planets. The rockets are fired briefly at the depar- ture planet to put the spacecraft into the transfer orbit; the spacecraft then coasts until it reaches the destination planet. The rockets are then fired again to put the spacecraft into the same orbit about the sun as the destination planet. (a) For a flight from earth to Mars, in what direction must the rockets be fired at the earth and at Mars: in the direction of motion, or opposite the direction of motion? What about for a flight from Mars to the earth? (b) How long does a one- way trip from the the earth to Mars take, between the firings of the rockets? (c) To reach Mars from the…arrow_forward
- No chatgpt pls will upvotearrow_forwarda cubic foot of argon at 20 degrees celsius is isentropically compressed from 1 atm to 425 KPa. What is the new temperature and density?arrow_forwardCalculate the variance of the calculated accelerations. The free fall height was 1753 mm. The measured release and catch times were: 222.22 800.00 61.11 641.67 0.00 588.89 11.11 588.89 8.33 588.89 11.11 588.89 5.56 586.11 2.78 583.33 Give in the answer window the calculated repeated experiment variance in m/s2.arrow_forward
- How can i solve this if n1 (refractive index of gas) and n2 (refractive index of plastic) is not known. And the brewsters angle isn't knownarrow_forward2. Consider the situation described in problem 1 where light emerges horizontally from ground level. Take k = 0.0020 m' and no = 1.0001 and find at which horizontal distance, x, the ray reaches a height of y = 1.5 m.arrow_forward2-3. Consider the situation of the reflection of a pulse at the interface of two string described in the previous problem. In addition to the net disturbances being equal at the junction, the slope of the net disturbances must also be equal at the junction at all times. Given that p1 = 4.0 g/m, H2 = 9.0 g/m and Aj = 0.50 cm find 2. A, (Answer: -0.10 cm) and 3. Ay. (Answer: 0.40 cm)please I need to show all work step by step problems 2 and 3arrow_forward
- AstronomyPhysicsISBN:9781938168284Author:Andrew Fraknoi; David Morrison; Sidney C. WolffPublisher:OpenStaxFoundations of Astronomy (MindTap Course List)PhysicsISBN:9781337399920Author:Michael A. Seeds, Dana BackmanPublisher:Cengage Learning
- An Introduction to Physical SciencePhysicsISBN:9781305079137Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar TorresPublisher:Cengage Learning