Explanation Procedure used: To multiply the sum and difference of the conjugates: 1. Square the first term of either binomial. 2. Insert a minus sign. 3. Square the second term of either binomial. That is, symbolically represented by ( a + b ) ( a − b ) = a 2 − b 2 . Calculation: Note that the expression ( 3 a − 11 b ) ( 3 a + 11 b ) is of the form ( a + b ) ( a − b ) , where a = 3 a , b = 11 b . Substitute a = 3 a , b = 11 b in ( a + b ) ( a − b ) = a 2 − b 2 to simplify the expression ( 3 a − 11 b ) ( 3 a + 11 b ) as follows

Mylab Math With Pearson Etext -- Standalone Access Card -- For College Mathematics For Trades And Technologies (10th Edition) (my Math Lab)

10th Edition

ISBN: 9780134880402

Author: Hobbs, Margie; Cleaves, Cheryl

Publisher: PEARSON

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Chapter 11.3, Problem 84E

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The special products of the expression (3a−11b)(3a+11b) using patterns.

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Chapter 11.3, Problem 83E

Chapter 11.3, Problem 85E

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Chapter 11 Solutions

Mylab Math With Pearson Etext -- Standalone Access Card -- For College Mathematics For Trades And Technologies (10th Edition) (my Math Lab)

Ch. 11.1 - Prob. 1LC Ch. 11.1 - Prob. 2LC Ch. 11.1 - Prob. 1E Ch. 11.1 - Prob. 2E Ch. 11.1 - Prob. 3E Ch. 11.1 - Prob. 4E Ch. 11.1 - Prob. 5E Ch. 11.1 - Prob. 6E Ch. 11.1 - Prob. 7E Ch. 11.1 - Write the products. See Example 1. 2x3(5x8)

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The special products of the expression ( 3 a − 11 b ) ( 3 a + 11 b ) using patterns.

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The special products of the expression (3a−11b)(3a+11b) using patterns.

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Chapter 11 Solutions