ADV.ENG.MATH (LL) W/WILEYPLUS BUNDLE
10th Edition
ISBN: 9781119809210
Author: Kreyszig
Publisher: WILEY
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Original: 100-200 = 20,000
200400=20,000 80
602=3600 694761
=4
4x1.3225-6.29
4761/3600 = 1-3225 5.29-1058msy
6). The dose to the body was 200 mSv. Find
the dose to the lung in mrem?
W 200ms
20
2.15
and
8) A technique of 20 mAs, 40 kV produces a
f4 Sy Find the dose to the Thyroid in
original ssD
400x (100) 2 400 x (14)=100
34
10or (2)² = 100 × (0-85) = 100 x = 72.25
100x
40
72.25 =36.13
500
36.13 13.84
O. 7225
12x13.84≈ 166.08mAs
10) The dose of a radiograph was 100 mSv with a technique of: 10 mAs, 180 kV at 200 cm and
tabletop. If the technique is changed to: 20 mAs, 153 kV at 100 cm using a 5:1 grid then find the
new dose in rem to the Lungs.
11) A radiographic technique produces an exposure index of EI= 300 and TEI=600 at a source-
to-image receptor distance (SID) of 200 cm, 100 kV, 5:1 grid using 10 mAs. If the technique is
changed to 100 cm and 85 kV and 5 mAs with table top find the new exposure index? What is
the value of DI?
10
0.
75 and 34
KV
arved
fromise to 75
halfed
NAME Genesis Ward
0 mAs is 40 #2). A technique involves 150 mAs, 40 kV
and produces an intensity of 2 R.
are gone
down
KV C15%!
In =
200%
Find the new intensity in mGya, using 300
mAs and 46 kV?
=100
206a
150mAS 40KV 2R
kv
150
is so divide
00 mA, 200
alue of 100.
Boomts 46KY
4). A technique is taken with 100 mA, 200
ms, 60 kV and produces 200 mSv.
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- Fi is 2 O 2 ms, #3). A technique is taken with 100 mA, 200 60 kV and produces an EI value of 100. Find the EI value when this technique is changed to 200 mA, 100 ms, 69 kV? 4) m 2arrow_forward11) A radiographic technique produces an exposure index of EI= 300 and TEI=600 at a source- to-image receptor distance (SID) of 200 cm, 100 kV, 5:1 grid using 10 mAs. If the technique is changed to 100 cm and 85 kV and 5 mAs with table top find the new exposure index? What is the value of DI?arrow_forward5). The dose to the breast was 120 mGy find the entire body dose represented in rad?arrow_forward
- 1000 x= 800mGy to body X= = rad 7). If EI=300, TEI=500 with mAs = 20 and you want to decrease the kV by 15% then 0.8 Gy what is the new mAs value to set DI=0? =0% 100-00 Dorad 8) A te dose of rem w kV? 2 tom i sv 4sv 48rem to thyr. KV+ I formula K In = Fox2 kV (1979) (48 rem = 8.2 = 16. SVx 100 160oren-body 1600.0.03=X I M M Earrow_forward8 If f(x + y) = f(x)f(y) and Σ f (x) = 2, x, y = N, x=1 where N is the set of all natural number, then the f(4) value of is. f(2)arrow_forwardvide 0. OMS its 150MAS 40k 300mts 46KV 4). A technique is taken with 100 mA, 200 ms, 60 kV and produces 200 mSv. Find the intensity in rem when this technique is changed to 200 mA, 400 ms, 69 kV? nd 5). The dose to the body was 200 mSy. Findarrow_forward
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