Chapter 10, Problem 83P

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19. Mount Everest, Earth's highest mountain above sea level, has a peak of 8849 m above sea level. Assume that sea level defines the height of Earth's surface. (re = 6.38 × 106 m, ME = 5.98 × 1024 kg, G = 6.67 × 10 -11 Nm²/kg²) a. Calculate the strength of Earth's gravitational field at a point at the peak of Mount Everest. b. What is the ratio of the strength of Earth's gravitational field at a point 644416m below the surface of the Earth to a point at the top of Mount Everest? C. A tourist watching the sunrise on top of Mount Everest observes a satellite orbiting Earth at an altitude 3580 km above his position. Determine the speed of the satellite.

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6. As the distance between two charges decreases, the magnitude of the electric potential energy of the two-charge system: a) Always increases b) Always decreases c) Increases if the charges have the same sign, decreases if they have the opposite signs d) Increases if the charges have the opposite sign, decreases if they have the same sign 7. To analyze the motion of an elastic collision between two charged particles we use conservation of & a) Energy, Velocity b) Momentum, Force c) Mass, Momentum d) Energy, Momentum e) Kinetic Energy, Potential Energy

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17. Two charges, one of charge +2.5 × 10-5 C and the other of charge +3.7 × 10-6 C, are 25.0 cm apart. The +2.5 × 10−5 C charge is to the left of the +3.7 × 10−6 C charge. a. Draw a diagram showing the point charges and label a point Y that is 20.0 cm to the left of the +3.7 × 10-6 C charge, on the line connecting the charges. (Field lines do not need to be drawn.) b. Calculate the net electric field at point Y.