Chapter 10, Problem 46P

ANSWER THE FOLLOWING CORRECTLY AND PROVIDE A DETAILED SOLUTION.  1.  DETERMINE THE MOMENT OF INERTIA OF THE SHADED SECTION ABOUT THE GIVEN X-AXIS.

H6. Find the position of the cross-section’s centroid. Then, determine the moments of inertia of horizontal & vertical axes through the centroid.   (I'm not sure if the width of the verticle rectangle is needed or not. If it is, assume 5 mm.)

The shaded area has the following properties: 4 = 126 x10 mm* ; 1, = 6,55 x10* mm* ; and Pay =-1.02 10° mm* Determine the moments of inertia of the area about the x' and v' axes if e=30°.

​​​​​​​Determine the moments of inertia about the centroid of the shape

The variable h designates the arbitrary vertical location of the center of the circular cutout within the semicircular area. Determine the area moment of inertia about the x-axis for (a) h=0 and (b) h = 5 in. 3" 11" h Amswers: (a) h = 0 Ix = i in.4 (b) h = 5 in. Ix= i in.4

3. Determine the distance y to the centroid for the beam's cross sectional area; then determine the moment of inertia about the x' axis. 25 mm 50 mm 100 mm 75 mm C 25 mm 25 mm 75 mm- 50 mm 100 mm 25 mm -X

Locate the centroid  of the beam’s cross sectional area, and then determine the moment of inertia of the area about the centroidal y' axis

1). Locate the centroid C (x,j) of the shaded area. C(x.Y) 2). Determine the moment of inertia of the shaded area about the x-axis and y-axis. 3). Find the radius of gyration about the area, kx and ky y=2.5-0.12 2.5 ft 2 ft 5ft

Determine the location of centroidal x and y and the moment of inertia Ix of the figure shown. Use the parallel axis theorem.  Where B = 9, and Y = 82