Understanding Motor Controls
4th Edition
ISBN: 9781337798686
Author: Stephen L. Herman
Publisher: Delmar Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
thumb_up100%
Chapter 10, Problem 1RQ
Explain the difference between inching and jogging.
Expert Solution & Answer
To determine
The difference between inching and jogging.
Explanation of Solution
Jogging:
Jogging is to start a motor with short nudges of power at full voltage. Jogging should not exceed 5 times in a minute and if frequently done, the starter of the motor will be de-rated.
Inching:
Inching is similar to jogging but at reduced voltage. Inching is to start a motor with short nudges of power at reduced voltage.
Want to see more full solutions like this?
Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Determine the moments of the force about the x and the
a axes.
O
4 m
F = {-40i +20j + 10k} N
3 m
6 m
a
6. A part of the structure for a factory automation system is
a beam that spans 30.0 in as shown in Figure P5-6. Loads
are applied at two points, each 8.0 in from a support. The
left load F₁ = 1800 lb remains constantly applied, while
the right load F₂ = 1800 lb is applied and removed fre-
quently as the machine cycles. Evaluate the beam at both
B and C.
A
8 in
F₁ = 1800 lb
14 in
F2 = 1800 lb
8 in
D
RA
B
C
4X2X1/4
Steel
tube
Beam cross section
RD
30. Repeat Problem 28, except using a shaft that is rotating
and transmitting a torque of 150 N⚫m from the left bear-
ing to the middle of the shaft. Also, there is a profile key-
seat at the middle under the load.
Chapter 10 Solutions
Understanding Motor Controls
Ch. 10 -
Explain the difference between inching and...Ch. 10 - What is the main purpose of jogging?Ch. 10 - Refer to the circuit shown in Figure 108. In this...Ch. 10 - Refer to the circuit shown in Figure 109. In this...Ch. 10 - Refer to the circuit shown in Figure 107. Assume...Ch. 10 - Prob. 6RQCh. 10 - Prob. 7RQ
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- 28. The shaft shown in Figure P5-28 is supported by bear- ings at each end, which have bores of 20.0 mm. Design the shaft to carry the given load if it is steady and the shaft is stationary. Make the dimension a as large as pos- sible while keeping the stress safe. Determine the required d = 20mm D = ? R = ?| 5.4 kN d=20mm Length not to scale -a = ?- +а= a = ? + -125 mm- -250 mm- FIGURE P5-28 (Problems 28, 29, and 30)arrow_forward12. Compute the estimated actual endurance limit for SAE 4130 WQT 1300 steel bar with a rectangular cross sec- tion of 20.0 mm by 60 mm. It is to be machined and subjected to repeated and reversed bending stress. A reli- ability of 99% is desired.arrow_forward28. The shaft shown in Figure P5-28 is supported by bear- ings at each end, which have bores of 20.0 mm. Design the shaft to carry the given load if it is steady and the shaft is stationary. Make the dimension a as large as pos- sible while keeping the stress safe. Determine the required d = 20mm D = ? R = ?| 5.4 kN d=20mm Length not to scale -a = ?- +а= a = ? + -125 mm- -250 mm- FIGURE P5-28 (Problems 28, 29, and 30)arrow_forward
- 2. A strut in a space frame has a rectangular cross section of 10.0 mm by 30.0 mm. It sees a load that varies from a tensile force of 20.0 kN to a compressive force of 8.0 kN.arrow_forwardfind stress at Qarrow_forwardI had a theoretical question about attitude determination. In the attached images, I gave two axis and angles. The coefficient of the axes are the same and the angles are the same. The only difference is the vector basis. Lets say there is a rotation going from n hat to b hat. Then, you introduce a intermediate rotation s hat. So, I want to know if the DCM produced from both axis and angles will be the same or not. Does the vector basis affect the numerical value of the DCM? The DCM formula only cares about the coefficient of the axis and the angle. So, they should be the same right?arrow_forward
- 3-15. A small fixed tube is shaped in the form of a vertical helix of radius a and helix angle y, that is, the tube always makes an angle y with the horizontal. A particle of mass m slides down the tube under the action of gravity. If there is a coefficient of friction μ between the tube and the particle, what is the steady-state speed of the particle? Let y γ 30° and assume that µ < 1/√3.arrow_forwardThe plate is moving at 0.6 mm/s when the force applied to the plate is 4mN. If the surface area of the plate in contact with the liquid is 0.5 m^2, deterimine the approximate viscosity of the liquid, assuming that the velocity distribution is linear.arrow_forward3-9. Given that the force acting on a particle has the following components: Fx = −x + y, Fy = x − y + y², F₂ = 0. Solve for the potential energy V. -arrow_forward
- 2.5 (B). A steel rod of cross-sectional area 600 mm² and a coaxial copper tube of cross-sectional area 1000 mm² are firmly attached at their ends to form a compound bar. Determine the stress in the steel and in the copper when the temperature of the bar is raised by 80°C and an axial tensile force of 60 kN is applied. For steel, E = 200 GN/m² with x = 11 x 10-6 per °C. E = 100 GN/m² with α = 16.5 × 10-6 For copper, per °C. [E.I.E.] [94.6, 3.3 MN/m².]arrow_forward3–16. A particle of mass m is embedded at a distance R from the center of a massless circular disk of radius R which can roll without slipping on the inside surface of a fixed circular cylinder of radius 3R. The disk is released with zero velocity from the position shown and rolls because of gravity, all motion taking place in the same vertical plane. Find: (a) the maximum velocity of the particle during the resulting motion; (b) the reaction force acting on the disk at the point of contact when it is at its lowest position. KAR 60° 3R M Fig. P3-16arrow_forwardI have figured out the support reactions, Ay = 240 kN, Ax = 0 kN, Ma = 639.2 kN*m and the constant term for V(x) is 240. I am not figuring out the function of x part right. Show how to derive V(x) and M(x) for this distributed load.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Understanding Motor ControlsMechanical EngineeringISBN:9781337798686Author:Stephen L. HermanPublisher:Delmar Cengage Learning
International Edition---engineering Mechanics: St...Mechanical EngineeringISBN:9781305501607Author:Andrew Pytel And Jaan KiusalaasPublisher:CENGAGE L
Automotive Technology: A Systems Approach (MindTa...Mechanical EngineeringISBN:9781133612315Author:Jack Erjavec, Rob ThompsonPublisher:Cengage Learning
Precision Machining Technology (MindTap Course Li...Mechanical EngineeringISBN:9781285444543Author:Peter J. Hoffman, Eric S. Hopewell, Brian JanesPublisher:Cengage Learning
Understanding Motor Controls
Mechanical Engineering
ISBN:9781337798686
Author:Stephen L. Herman
Publisher:Delmar Cengage Learning
International Edition---engineering Mechanics: St...
Mechanical Engineering
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:CENGAGE L
Automotive Technology: A Systems Approach (MindTa...
Mechanical Engineering
ISBN:9781133612315
Author:Jack Erjavec, Rob Thompson
Publisher:Cengage Learning
Precision Machining Technology (MindTap Course Li...
Mechanical Engineering
ISBN:9781285444543
Author:Peter J. Hoffman, Eric S. Hopewell, Brian Janes
Publisher:Cengage Learning
General Industrial Safety; Author: Jim Pytel;https://www.youtube.com/watch?v=RXtF_vQRebM;License: Standard youtube license