EBK BUSINESS STATISTICS
7th Edition
ISBN: 9780134462783
Author: STEPHAN
Publisher: PEARSON CUSTOM PUB.(CONSIGNMENT)
expand_more
expand_more
format_list_bulleted
Videos
Question
error_outline
This textbook solution is under construction.
Students have asked these similar questions
Two researchers conduct separate studies to test Ho: p=0.50
against Ha: p0.50, each with n = 400. Researcher A gets 226
observations in the category of interest, and
p=
6=226/400=0.565. Researcher B gets 225 in the category of
interest, and p = 225/400=0.5625. Complete parts (a) through
(d) below.
a. Find the z-scores and P-values for both researchers.
Researcher A
Z =
Researcher B
Z =
P-value =
P-value =
(Round the z-scores to two decimal places as needed. Round
the P-values to three decimal places as needed.)
The result in case A is
The result in case B is
b. Using α = 0.01, indicate in each case whether the result is
"statistically significant." Interpret.
What does the statistical significance of the results above imply?
OA. A difference in conclusions between two hypothesis
tests does not necessarily mean that the test with the
result that is deemed "statistically significant" is actually
much more significant than the test with the result that
is deemed "not statistically…
With a = .01, what is the critical t value for a one-tailed test with n = 30?
O t = 2.457
Ot = 2.462
Ot = 2.756
Ot = 2.750
A farmer wants to test the effectiveness of a pest control method in allowing strawberry blooms to yield marketable strawberries. Out of a random sample of 100 blooms, 67 yield marketable strawberries. Specifically, he wants to test know if there is sufficient evidence that more than three-fourths of all blooms grown with this pest control method end up as marketable strawberries. The value of the statistic for this test is z=-1.85. Which of the following is the is the approximate p-value to the nearest thousandth for this test?
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.Similar questions
- A researcher obtains M = 45 with SS = 250 for a sample of n = 10 women and M = 49 with SS = 270 for a sample of n = 10 men. If the two samples are used to evaluate the mean difference between the two populations, what value will be obtained for the t statistic?arrow_forwardDetermine the upper-tail critical values of F in each of the following two-tail tests. a. a = 0.02, n, =21, n2 = 13 b. a = 0.01, n, = 21, n2 = 13 c. a = 0.10, n, = 21, ng = 13 a. The critical value of F when a = 0.02, n, = 21, n2 = 13 is (Round to two decimal places as needed.) b. The critical value of F when a = 0.01, n, = 21, n2 = 13 is (Round to two decimal places as needed.) c. The critical value of F when a = 0.10, n, = 21, n2 = 13 is (Round to two decimal places as needed.)arrow_forwardA sample of n= 64 scores is selected from a population with u =60 and o= 10. If the sample mean is M = 57, what is the z-score for this sample mean? Oz=-2.40 Oz=+1.00 Oz=-2.00 Oz= +4,00arrow_forward
- Find the t-value for a=0.005 one-tailed test with n=25.arrow_forwardIf the df value for a two tailed test with alpha =0.05 were to increase from df=5 to df=22,what would happen to the critical values for t?arrow_forwardIf the test of H0: = 19 against Ha: ≠ 19 based on an SRS of 15 observations from a Normal populationproduces the statistic of t = –1.75. The P-value isarrow_forward
- Determine the upper-tail critical values of F in each of the following two-tail tests. a. a = 0.01, n, = 31, ng = 16 b. a = 0.02, n, = 31, n2 = 16 c. a = 0.05, n, = 31, n, = 16 a. The critical value of F when a = 0.01, n, = 31, n, = 16 is (Round to two decimal places as needed.) b. The critical value of F when a = 0.02, n, = 31, n, = 16 is (Round to two decimal places as needed.) c. The critical value of F when a = 0.05, n, = 31, n, = 16 is (Round to two decimal places as needed.)arrow_forwardA medical researcher is interested in determining if there is a relationship between adults over 50 who exercise regularly and levels of blood pressure. A random sample of 236 adults over 50 is selected and the results are given below. Calculate the test statistic to test the claim that regular exercise and blood pressure are independent. Use α = 0.01.arrow_forwarda. Perform a test with the following scores: Population mean = 94, M=100 and the SEM=7.b. Consult the t table to obtain a critical value for the outcome using an alpha level of α=.05, for a two tailed test and with a degree of freedom of df=7.c. Would the t value you got be significant if doing a true test?arrow_forward
- If a =0.05 and df=26 for a left-tailed test, what is the critical value of x?? A. Xổ 05 = 38.885 Xổ.05 В. 15.379 C. Xã.95 = 38.885 2 D. Xá.95 = 15.379arrow_forwardThe NAEP considers that a national average of 283 is an acceptable performance. Using α = .05, run a two-tail t-test for one sample to test Ho: µ=283 for the 2019 scores. Report the t-obt, df, and p-values. Would you reject the null hypothesis that the 2019 scores come from a population with average 283? If this is the case, does it come from a population from larger or smaller average?arrow_forwardAfter conducting a two-tailed, one-sample t test you find the critical t value is -2.045 while the t value you obtained for your sample is -3.61. Which of the following decisions could you make?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw Hill
Glencoe Algebra 1, Student Edition, 9780079039897...
Algebra
ISBN:9780079039897
Author:Carter
Publisher:McGraw Hill
Hypothesis Testing using Confidence Interval Approach; Author: BUM2413 Applied Statistics UMP;https://www.youtube.com/watch?v=Hq1l3e9pLyY;License: Standard YouTube License, CC-BY
Hypothesis Testing - Difference of Two Means - Student's -Distribution & Normal Distribution; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=UcZwyzwWU7o;License: Standard Youtube License