Concept explainers
Choose the best answer to each of the following. Explain your reasoning.
Which of the following correctly lists our “cosmic address” from smallest to largest? (a) Earth, solar system, Milky way Galaxy, Local Group, Local Group, Local Super-cluster, universe (b) Earth, solar system, Local Group, Local Super-cluster, Milky Way Galaxy, universe (c) Earth, Milky Way Galaxy, solar system, Local Group, Local Supercluster, universe.
The correct listing of our "cosmic address" from smallest to largest.
Answer to Problem 1QQ
The correct listing of our cosmic address" is (a) Earth, solar system, Milky Way galaxy, Local Group, Local Supercluster, universe.
Explanation of Solution
Introduction:
The universe is extremely vast, consisting of millions of galaxies, stars and planetary systems. The Earth and the solar system are tiny parts of the universe.
The Earth is the third planet from the Sun in our solar system. The Solar system is in the Milky Way galaxy. The Milky Way galaxy is a part of the local group of galaxies. The Local group contains nearly 54 galaxies. The local group is a part of the Virgo Cluster which is in turn a part of the Laniakea Supercluster. The Universe contains many such superclusters.
Conclusion:
Therefore, the correct listing of our cosmic address" is (a) Earth, solar system, Milky Way galaxy, Local Group, Local Supercluster, universe.
Want to see more full solutions like this?
Chapter 1 Solutions
Cosmic Perspective Fundamentals
Additional Science Textbook Solutions
Biological Science (6th Edition)
College Physics: A Strategic Approach (3rd Edition)
Applications and Investigations in Earth Science (9th Edition)
Microbiology with Diseases by Body System (5th Edition)
Human Physiology: An Integrated Approach (8th Edition)
Chemistry: Structure and Properties (2nd Edition)
- No chatgpt pls will upvotearrow_forwardair is pushed steadily though a forced air pipe at a steady speed of 4.0 m/s. the pipe measures 56 cm by 22 cm. how fast will air move though a narrower portion of the pipe that is also rectangular and measures 32 cm by 22 cmarrow_forwardNo chatgpt pls will upvotearrow_forward
- 13.87 ... Interplanetary Navigation. The most efficient way to send a spacecraft from the earth to another planet is by using a Hohmann transfer orbit (Fig. P13.87). If the orbits of the departure and destination planets are circular, the Hohmann transfer orbit is an elliptical orbit whose perihelion and aphelion are tangent to the orbits of the two planets. The rockets are fired briefly at the depar- ture planet to put the spacecraft into the transfer orbit; the spacecraft then coasts until it reaches the destination planet. The rockets are then fired again to put the spacecraft into the same orbit about the sun as the destination planet. (a) For a flight from earth to Mars, in what direction must the rockets be fired at the earth and at Mars: in the direction of motion, or opposite the direction of motion? What about for a flight from Mars to the earth? (b) How long does a one- way trip from the the earth to Mars take, between the firings of the rockets? (c) To reach Mars from the…arrow_forwardNo chatgpt pls will upvotearrow_forwarda cubic foot of argon at 20 degrees celsius is isentropically compressed from 1 atm to 425 KPa. What is the new temperature and density?arrow_forward
- Calculate the variance of the calculated accelerations. The free fall height was 1753 mm. The measured release and catch times were: 222.22 800.00 61.11 641.67 0.00 588.89 11.11 588.89 8.33 588.89 11.11 588.89 5.56 586.11 2.78 583.33 Give in the answer window the calculated repeated experiment variance in m/s2.arrow_forwardNo chatgpt pls will upvotearrow_forwardCan you help me solve the questions pleasearrow_forward
- Can you help me solve these questions please so i can see how to do itarrow_forwardHow can i solve this if n1 (refractive index of gas) and n2 (refractive index of plastic) is not known. And the brewsters angle isn't knownarrow_forward2. Consider the situation described in problem 1 where light emerges horizontally from ground level. Take k = 0.0020 m' and no = 1.0001 and find at which horizontal distance, x, the ray reaches a height of y = 1.5 m.arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON